WO2017032343A1 - 传输he-ltf序列的方法和装置 - Google Patents

传输he-ltf序列的方法和装置 Download PDF

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Publication number
WO2017032343A1
WO2017032343A1 PCT/CN2016/096973 CN2016096973W WO2017032343A1 WO 2017032343 A1 WO2017032343 A1 WO 2017032343A1 CN 2016096973 W CN2016096973 W CN 2016096973W WO 2017032343 A1 WO2017032343 A1 WO 2017032343A1
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Prior art keywords
sequence
ltf
value
resource block
subcarrier
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Ceased
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PCT/CN2016/096973
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English (en)
French (fr)
Inventor
薛鑫
王宁娟
刘乐
林伟
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Huawei Technologies Co Ltd
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Huawei Technologies Co Ltd
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Priority claimed from CN201510849062.4A external-priority patent/CN106487737B/zh
Priority to CA2995892A priority Critical patent/CA2995892C/en
Priority to MX2018002300A priority patent/MX383648B/es
Priority to JP2018510392A priority patent/JP6463552B2/ja
Priority to SG11201801055TA priority patent/SG11201801055TA/en
Priority to PL16838601T priority patent/PL3334112T3/pl
Priority to KR1020187006056A priority patent/KR102028661B1/ko
Priority to EP23172732.2A priority patent/EP4280554B1/en
Priority to ES16838601T priority patent/ES2790383T3/es
Priority to EP19189060.7A priority patent/EP3657749B1/en
Priority to AU2016312080A priority patent/AU2016312080B2/en
Priority to EP21165745.7A priority patent/EP3937445B2/en
Application filed by Huawei Technologies Co Ltd filed Critical Huawei Technologies Co Ltd
Priority to EP25184864.4A priority patent/EP4645788A3/en
Priority to MYPI2018700567A priority patent/MY201594A/en
Priority to EP16838601.9A priority patent/EP3334112B1/en
Publication of WO2017032343A1 publication Critical patent/WO2017032343A1/zh
Priority to ZA201800863A priority patent/ZA201800863B/en
Priority to US15/905,567 priority patent/US10645687B2/en
Anticipated expiration legal-status Critical
Priority to US16/355,385 priority patent/US10616882B2/en
Priority to US16/694,695 priority patent/US11265873B2/en
Priority to US17/683,103 priority patent/US11843493B2/en
Priority to US18/512,013 priority patent/US20240205064A1/en
Priority to US19/030,207 priority patent/US20250260608A1/en
Ceased legal-status Critical Current

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    • H—ELECTRICITY
    • H04—ELECTRIC COMMUNICATION TECHNIQUE
    • H04L—TRANSMISSION OF DIGITAL INFORMATION, e.g. TELEGRAPHIC COMMUNICATION
    • H04L27/00—Modulated-carrier systems
    • H04L27/26—Systems using multi-frequency codes

Definitions

  • the present invention relates to the field of wireless communication technologies and, more particularly, to a method and apparatus for transmitting HE-LTF sequences.
  • WLAN Wireless Local Area Network
  • Orthogonal Frequency Division Multiplexing OFDM
  • OFDMA Orthogonal Frequency Division Multiple Access
  • the OFDMA technology divides the air interface time-frequency resources into a plurality of orthogonal time-frequency resource blocks (RBs).
  • the RBs may be shared in time and orthogonal in the frequency domain.
  • the LTF of 80 MHz or the LTF of 160 MHz in the 802.11ac standard is used as a basic template, and the value of the carrier part corresponding to the resource block scheduled by the user in the OFDMA mode is extracted therefrom, and the value of the carrier part not corresponding to the resource block is padded with 0.
  • the Peak to Average Power Ratio (PAPR) is higher.
  • Embodiments of the present invention provide a method for transmitting wireless local area network information to reduce a peak average power ratio.
  • a method of transmitting wireless local area network information including:
  • the HE-LTF sequence is specifically a sequence in each embodiment
  • the corresponding sequence segments in the HE-LTF sequence are transmitted according to the RU size and RU location allocated for the station.
  • a method for receiving a wireless local area network PPDU includes:
  • the HE-LTF sequence is specifically a sequence in each embodiment
  • the corresponding HE-LTF sequence segment is selected as the channel estimation reference sequence corresponding to the RU at the receiving end.
  • means for performing the aforementioned method such as an AP or STA, or a corresponding chip, are provided.
  • the HE-LTF sequence provided by the embodiment of the present invention has a relatively low PAPR in the next generation wireless local area network.
  • 1a, 1b, and 1c are tone plans of different bandwidths in an OFDMA transmission mode according to an embodiment of the present invention
  • 2a, 2b are schematic diagrams of PAPRs obtained if LTF simulations of 802.11ac are used.
  • FIG. 3 is a simplified schematic diagram of a wireless local area network according to an embodiment of the present invention.
  • FIG. 4 is a schematic diagram showing a simple data structure of a PPDU in a multi-user transmission mode according to an embodiment of the present invention
  • 5a, 5b, 5c, and 5d are tone plans including pilot positions in different bandwidths of an OFDMA transmission mode according to an embodiment of the invention.
  • Figure 6 is a schematic diagram of a PAPR simulated in a poor implementation.
  • 7a, 7b are simplified schematic views of the embodiment of the present invention in the uplink and downlink directions, respectively.
  • Figure 8a and Figure 8b show the PAPR values obtained by simulation using a better 2x HE-LTF sequence at 20MHz bandwidth.
  • Figure 9 shows the PAPR value obtained by simulation using a better 2x HE-LTF sequence at 40MHz.
  • Figure 10 and Figure 11 show the PAPR values obtained by simulation using a better 2x HE-LTF sequence at 80MHz.
  • Figure 12 shows the PAPR value obtained by simulation using a better 4x HE-LTF sequence at 20MHz bandwidth.
  • Figure 13 shows the PAPR value obtained by simulation using a better 4x HE-LTF sequence at 40MHz bandwidth.
  • Figure 14 shows the PAPR value obtained by simulation using a better 4x HE-LTF sequence at 80MHz bandwidth.
  • FIG. 15 is a block diagram of an access point in accordance with an embodiment of the present invention.
  • Figure 16 is a block diagram of a station in accordance with an embodiment of the present invention.
  • WLAN Wireless Local Area Networks Wireless LAN
  • An Access Point which can also be called a wireless access point or bridge or hotspot, can access a server or a communication network.
  • a station which may also be referred to as a user, may be a wireless sensor, a wireless communication terminal, or a mobile terminal, such as a mobile phone (or "cellular" phone) that supports WiFi communication functions and a computer with wireless communication capabilities.
  • a mobile phone or "cellular" phone
  • it may be a portable, pocket-sized, handheld, computer-built, wearable, or in-vehicle wireless communication device that supports WiFi communication functions, and exchanges communication data such as voice and data with the wireless access network.
  • next-generation wireless LAN standard 802.11ax is dedicated to further improving WLAN spectrum efficiency, regional throughput, actual user experience, and performance in a variety of indoor and outdoor dense network deployment environments.
  • the solution also requires suppression of inter-device interference to meet large-scale, High load networking requirements, etc.
  • OFDM symbols are constructed with 64-FFT in 20 MHz, 52 data subcarriers and 4 subcarriers in 56 subcarriers in total, and OFDM symbols are constructed with 128-FFT in 40 MHz, and 108 data subcarriers and 6 subcarriers in total 128 subcarriers
  • the carrier, while the 256-FFT constructs an OFDM symbol, has 234 data subcarriers and 8 subcarriers out of a total of 256 subcarriers.
  • the following tone plan (subcarrier distribution of data carrying) is adopted, and the positional relationship of different resource blocks (RU: resource unit) is as shown in FIG. 1a-1c, wherein the arrow indicates the residual subcarrier between the RUs.
  • the location, the number of large RU subcarriers and the corresponding number of small RUs that can be accommodated therein and the number of residual subcarriers between small RUs are the same.
  • FIG. 1a a simple schematic diagram of an OFDMA allocateable resource block (in English, a tone plan, or a resource block distribution) in FIG. 1b
  • FIG. 1b is a simple schematic diagram of an OFDMA resource block position in 40 MHz
  • FIG. 1c is within 80 MHz.
  • the OFDMA multi-user data packet in 802.11ax is a combination of multiple resource blocks (RU: resource unit).
  • the AP allocates one RU to each user.
  • the optional RUs that may be assigned to the user are:
  • RUs consisting of 26 consecutive subcarriers, including: 24 data subcarriers and 2 pilot pilot subcarriers;
  • RUs consisting of 52 consecutive subcarriers, including: 48 data subcarriers and 4 pilot pilot subcarriers;
  • RUs consisting of 106 consecutive subcarriers, including: 24 data subcarriers and 2 pilot pilot subcarriers;
  • RUs consisting of 242 consecutive subcarriers, including: 234 data subcarriers and 8 pilot pilot subcarriers;
  • RUs consisting of 484 consecutive subcarriers, including: 468 data subcarriers and 16 pilot pilot subcarriers;
  • RUs consisting of 996 consecutive subcarriers, including: 980 data subcarriers and 16 pilot pilot subcarriers.
  • 484-RU is used in 40MHz multi-user transmission
  • 996-RU is used in 80/160MHz multi-user transmission.
  • 160MHz can be seen as a combination of two 80MHz tone plans.
  • the subcarrier position indicated by the arrow in Figures 1a, 1b, 1c is the position of the aforementioned pilot subcarrier.
  • the HE-LTF for channel estimation in the 802.11ax system adopts two modes of 2x and 4x, and the 4x mode refers to the subcarrier number index of the HE-LTF sequence mapping and the resource block distribution of the data part.
  • the serial number is the same; and the 2x mode means that the HE-LTF serial number corresponds to the number of the 4x HE-LTF divided by 2, that is, the subcarrier number index of the HE-LTF sequence mapping and the resource block distribution in the data part.
  • the half of the subcarrier number is the same.
  • the tone plan of the OFDMA transmission in the 802.11ax system is different from the tone plan of the OFDM in the existing 802.11ac system. Therefore, the 20/40 VHT-LTF sequence defined in 802.11ac itself cannot be applied.
  • the total number of subcarriers of 80 MHz in 802.11ac is the same as the total number of subcarriers of 20 MHz in 802.11ax, but the peak value and the mean ratio (PAPR: Peak-to) are found directly in the 802.11ax 20 MHz bandwidth using the VHT-LTF sequence. -average power ratio) is relatively high.
  • 802.11ax is in the 40/80MHz tone plan, the number of subcarriers has exceeded the traditional sequence, and the VHT-LTF sequence of 802.11ac cannot be reused.
  • FIG. 3 is a simplified schematic diagram of a WLAN system to which an embodiment of the present invention is applied.
  • the system of Figure 3 includes one or more access points AP 101 and one or more stations STA 102.
  • the OFDMA technology is used for wireless communication between the access point 101 and the station 102.
  • FIG. 4 it is a frame structure of a possible AP sending data packet PPDU for the downlink WLAN system.
  • it complies with the relevant provisions of 802.11ax.
  • the information indicating the transmission bandwidth of the downlink user STA is included in the HE-SIG-A, and is included in the HE-SIG-B for indicating The information about the size and location of the RU allocated by the downlink scheduled user, or the scheduling information corresponding to the STA ID and other spatial stream numbers or modulation codes of each scheduled user.
  • the HE-SIG-A or HE-SIG-B may further include: a HE-LTF length for indicating alignment of a plurality of users, that is, a symbol number N of the HE-LTF.
  • the number of pilot subcarriers, the location of the pilot subcarrier, and the transmission mode are given.
  • the corresponding content can refer to "Motion #3, October 29, 2014, Removed with Motion 10, March 6, 2015 below"
  • the transmission method is: the pilot of the 802.11ax HE-LTF is transmitted in a single stream (similar to 802.11ac) in single-user, uplink-downlink OFDMA, and downlink MU-MIMO transmission.
  • the HE-LTF sequence of each STA is multiplied by the identification code assigned by the AP, and the AP can estimate the CFO of each STA by using the frequency identification code of each STA, so There is no special pilot subcarrier in the HE-LTF sequence of the MU-MIMO, which is different from the HE-LTF sequence of the downlink MU-MIMO.
  • some HE-LTF or methods of constructing HE-LTF are provided, but none of the effects of the pilot are considered, and the PAPR is relatively high in the corresponding method.
  • a Barker sequence of length 13, i.e. as x, to generate a sequence of length 121 according to the Barker sequence is represented by M 1, while finding the Barker sequence of lengths of 7 and 13, They are represented by M 2 and M 3 , respectively.
  • the specific sequence is represented as follows:
  • M 1 [-x,x,-x,-x,x,-x,-x,-x,-x,x,x,x,x];%121 tones
  • M 3 [+1 +1 +1 -1 -1 +1 -1];%Barker 7 tones
  • the HELTF sequence in the 2x/4x mode is constructed using the x, M 1 , M 2 , M 3 sequences.
  • the constructed HELTF sequence is as follows:
  • LTF 242 (-122:2:122) [M 1 (61:121),0,M 1 (1:61)];
  • LTF 996 (-500:2:500) [-M 1 ,-M 1 ,M 3 ,0,0,0,M 3 ,M 1 ,-M 1 ];
  • LTF 242 (-122:122) [M 1 ,0,0,0,M 1 ];
  • LTF 484 [M 1 , M 1 , 0, 0 , 0, 0 , 0, M 1 , -M 1 ];
  • the PAPR variation range is large in different cases, and in some cases PAPR bigger.
  • the previously mentioned case means that the pilot subcarrier phase change corresponds to the first row in P-maxtrix, and the other subcarrier phase changes correspond to the corresponding row in the P-matrix with the spatial stream.
  • the result of the PAPR is as follows, wherein the pilot subcarrier does not change the phase, and the fixed is multiplied by '+1', and the other subcarriers change the phase, and are respectively multiplied by '+1', '-1'. , 'w' or 'w 2 ', the PAPR corresponding to each row is shown in Figure 6. It can be seen that the PAPR varies greatly, and some PAPRs have exceeded 7dB.
  • the corresponding HE-LTF sequence has a lower PAPR when different values are set due to the pilot position.
  • the hardware implementation can also achieve low storage capacity and easy implementation.
  • a method of transmitting an HE-LTF sequence comprising:
  • the HE-LTF sequence is specifically a sequence in subsequent embodiments
  • a sequence segment corresponding to the location of the HE-LTF sequence is transmitted according to the RU size and the RU location in the resource allocation information.
  • the AP sends a data packet PPDU, where the PPDU can refer to the structure shown in FIG. 4, including:
  • the AP obtains a HE-LTF sequence corresponding to the bandwidth according to the total transmission bandwidth.
  • the HE-LTF sequence may be stored on the AP or may be constructed according to certain principles. For specific examples, reference may be made to subsequent examples.
  • 102 Obtain a corresponding HE-LTF sequence segment from the HE-LTF sequence according to the resource block RU size and the RU location allocated by the scheduled user, and map the HE-LTF sequence segment to the allocated RU subcarrier position. Send it out.
  • the AP allocates one row in the P-matrix matrix of size NxN to each stream on the RU as a signature for distinguishing the stream. Specifically, when transmitting the HE-LTF sequence of each stream on the RU, the tone plan on the nth symbol of the HE-LTF removes the length value other than the pilot subcarrier position, and multiplies the corresponding feature code used to distinguish the stream. The nth code word. It is known to those skilled in the art that the processing of the pilot subcarrier position is processed according to the prior art solution, and details are not described herein again.
  • a method for a downlink scheduled STA to receive an 802.11ax packet PPDU includes:
  • the scheduled STA receives the PPDU, and obtains the total transmission bandwidth indicated by the AP in the HE-SIG-A.
  • the HE-LTF sequence may be stored on the AP or the STA, or may be constructed according to certain principles. For specific examples, reference may be made to subsequent embodiments.
  • the scheduled STA identifies its own scheduled indication information by using its own STA ID according to the HE-SIG-B in the PPDU, where the size of the RU allocated by the AP to the user and the location of the RU are obtained. Selecting, according to the indicated RU size and location, a corresponding HE-LTF sequence segment from the HE-LTF sequence corresponding to the total bandwidth of the transmission, as a channel estimation reference sequence corresponding to the RU of the receiving end, for performing subsequent channels. Estimated operation, the principle of which is not described here.
  • the uplink STA sends the 802.11ax packet PPDU.
  • the AP indicates the uplink scheduling information by using the trigger frame, including the uplink user STA transmission bandwidth, the uplink scheduled STA ID, and the RU size and location allocated for the STA.
  • the length of the HE-LTF is the number of symbols N
  • the STA obtains an HE-LTF sequence corresponding to the bandwidth according to the indicated total bandwidth of the transmission.
  • the HE-LTF sequence may be stored on the AP or the STA, or may be constructed according to certain principles. For specific examples, reference may be made to subsequent embodiments.
  • the STA selects a HE-LTF sequence segment of the corresponding location from the HE-LTF sequence according to the allocated resource block RU size and the RU location, so that the mapping is sent out at the allocated RU subcarrier position.
  • the uplink AP receives the 802.11ax packet PPDU, the following:
  • the AP obtains a HE-LTF sequence corresponding to the bandwidth according to the total transmission bandwidth.
  • the HE-LTF sequence may be stored on the AP or may be constructed according to certain principles. For specific examples, reference may be made to subsequent embodiments.
  • the AP selects a corresponding HE-LTF sequence segment from the HE-LTF sequence according to the resource block RU size and the RU location allocated by each uplink scheduled user (station), and performs channel estimation as a reference sequence of the RU. .
  • 802.11ax compliant data packets may have transmission modes or data structures such as SU, MU, or OFDMA.
  • the HE-LTF sequence proposed by the embodiments of the present invention is not limited to application to a specific data structure, but can be applied to transmission of various data packets conforming to the 802.11ax standard.
  • the resource block RU size and the RU location allocated for the site mentioned in the foregoing embodiments are the entire bandwidth used by the current transmission. This article will not go into details.
  • a method for constructing a HE-LTF sequence is provided, which can be applied to the foregoing embodiments, in particular, for the size and location of different resource blocks RU in the 802.11ax OFDMA tone plan:
  • the small RU may refer to the aforementioned RU with a number of subcarriers of 26.
  • the basic HE-LTF sequence is a subsequence of length 26, for the 2x mode, since the HE-LTF sequence number corresponds to the number of 4x HE-LTF numbers divided by 2, the basic HE-LTF sequence in 2x mode Is a subsequence of length 13.
  • the HE-LTF sequences constructed according to the foregoing methods may be separately stored in the AP and STA ends in the WLAN, so as to be directly used in the uplink and downlink transmission mentioned above.
  • a transmitter transmits different HE-LTF sequences according to different bandwidth sizes, RU locations, and RU sizes.
  • AP or STA transmits different HE-LTF sequences according to different bandwidth sizes, RU locations, and RU sizes.
  • the 601 selects one HE-LTF sequence according to the bandwidth, and the one HE-LTF sequence has two forms, which respectively correspond to the 2x and 4x modes in 802.11ax.
  • the HE-LTF in the 2x mode includes: the sub-sequence Ga and the sub-sequence Gb, +1 or -1 at the position of the spare leftover subcarrier; the length of the Ga and Gb is +1 or -1 The sequence of 13.
  • Ga and Gb are:
  • G a ⁇ +1,+1,+1,-1,+1,+1,+1,-1,+1,-1,-1,+1,-1 ⁇
  • G b ⁇ +1,+1,+1,-1,-1,-1,-1,+1,-1,-1,-1,+1,-1 ⁇
  • the HE-LTF in the 2x mode may also include a sequence generated according to Ga and Gb.
  • a sequence generated according to Ga and Gb we will refer to the sequence generated by Ga and Gb as a derivative sequence, including but not limited to:
  • the sequence obtained by inverting the phase at the pilot position of the Ga sequence can be expressed as
  • the sequence obtained by inverting the phase at the pilot position of the Gb sequence can be expressed as
  • the sequence obtained by inverting the phase on the subcarrier of the even sequence of the Ga sequence can be expressed as G c .
  • a sequence obtained by inverting the phase of a value on a subcarrier of an even bit of the Gb sequence can be expressed as G d .
  • a further sequence includes: a sequence obtained by inverting a phase at a pilot position of the G c sequence, which can be expressed as And the sequence obtained by inverting the phase at the pilot position of the G d sequence can be expressed as
  • G c G a ⁇ *G xp
  • G d G b ⁇ *G xp
  • G ap ⁇ +1, +1, -1, +1, +1, +1, +1, +1, +1, +1, +1, -1, +1, +1, +1 ⁇ , meaning that The frequency position (ie, the subcarrier position with the number 3 and 10) is inverted.
  • G bp ⁇ +1,+1,+1,-1,+1,+1,+1,+1,+1,+1,+1,+1,-1,+1,+1 ⁇ , meaning at the pilot position (ie, the serial number is the 4th and 11th subcarrier positions) is inverted.
  • G xp ⁇ +1,-1,+1,-1,+1,-1,+1,-1,+1,-1,+1,-1,+1,-1,+1 ⁇ , meaning in the even position Inverted.
  • the PAPR value after the G a sequence IFFT is equal to the PAPR value after the G c sequence IFFT.
  • G b and its derived sequences are identical to G a and its derived sequences, and have the same properties as described in 1, 2 above.
  • the HELTF in 4x mode includes: sequence Ga, subsequence Gb, and +1 or -1 at the position of the spare leftover subcarrier; the Ga or Gb is a sequence of length 26 consisting of +1 or -1. specific:
  • Ga [+1 +1 +1 +1 +1 +1 +1 +1 +1 +1 -1 +1 +1 -1 -1 +1 -1 +1 +1 - 1 +1 -1];
  • Gb [+1 +1 +1 +1 -1 -1 +1 +1 +1 +1 +1 +1 -1 -1 +1 -1 -1 +1 -1 + 1 -1 +1];
  • the HE-LTF in the 4x mode may also include a sequence generated according to Ga or Gb.
  • a sequence generated according to Ga or Gb we refer to the sequence generated by Ga or Gb as a derived sequence, including but not limited to:
  • the sequence obtained by inverting the phase at the pilot position of the Ga sequence can be recorded as
  • the sequence obtained by inverting the phase at the pilot position of the Gb sequence can be recorded as
  • a sequence obtained by inverting the phase of the value on the subcarrier of the even sequence of the Ga sequence can be referred to as G c .
  • a sequence obtained by inverting the phase of a value on a subcarrier of an even bit of the Gb sequence can be referred to as G d .
  • the sequence obtained by inverting the phase at the pilot position of the G c sequence can be recorded as
  • the sequence obtained by inverting the phase at the pilot position of the G d sequence can be recorded as
  • G c G a ⁇ *G xp
  • G d G b ⁇ *G xp
  • G ap ⁇ 1, 1, 1, 1, 1, 1, -1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1,1,1,1 ⁇ means at
  • the pilot position (ie, the subcarriers with the number 6 and 20) is inverted.
  • G xp ⁇ +1,-1,+1,-1,+1,-1,+1,-1,+1,-1,+1,-1,+1-1,+1,-1 , +1, -1, +1, -1, +1, -1, +1, -1, +1, -1, +1, -1 ⁇ means negating the position of the even number.
  • the PAPR value after the G a sequence IFFT is equal to the PAPR value after the G c sequence IFFT.
  • G b and G a sequence derived with the same sequence and its derivatives, having the same properties as described above 1,2.
  • each of the foregoing subsequences and derived sequences may have different expression patterns, for example, the aforementioned G c is replaced by Replace G d with Replace with Replace with Its essence is no different. Alternatively, all of the basic subsequences and the corresponding derived sequences have different expressions, and their nature is not different.
  • the HE-LTF sequence further comprises a combination of different derived sequences for different 2x/4x patterns.
  • Cascade combinations in the 2x mode include, but are not limited to, one or any combination of the following sequences for the Ga, Gb sequences, and the different derived sequences they generate:
  • the cascaded combination in the 4x mode includes, but is not limited to, one or any combination of the following sequences for the Ga, Gb sequences, and the different derived sequences they generate:
  • the above-mentioned cascade combination may also have corresponding different expressions, and the contents thereof are not substantially different.
  • the AP or the STA of the WLAN only the sub-sequence Ga and the sub-sequence Gb may be stored, and when the PPDU needs to be transmitted, the HE-LTF sequence is constructed and then transmitted, or the foregoing HE-LTF sequence may be directly stored. In an AP or STA, it is transmitted on the corresponding subcarrier when needed.
  • the subsequences at corresponding positions of the HE-LTF sequence are placed on the subcarriers corresponding to the position and transmitted.
  • the RU size may be 13, 26, 54, and 121 subcarriers.
  • -122:2:122 refers to a subcarrier of an even position in a subcarrier of sequence number -122 to 122, that is, specifically the sequence number is ⁇ -122, -120, ..., -2
  • the values at the positions of these subcarriers are the elements of the corresponding positions in the above sequence, and the values of the subcarriers at other positions are 0.
  • the above expressions will not be described in the following.
  • the HE-LTF sequence includes Ga and Gb sequences and sequences generated by Ga and Gb sequences.
  • G c (Refer to the previous statement for details), +1 or -1 at the position of the spare leftover subcarrier, and further, may also contain consecutive +G a , Or, continuous +G b , Or, continuous +G c , continuously -G b and so on.
  • G a ⁇ +1,+1,+1,-1,+1,+1,+1,-1,+1,-1,-1,+1,-1 ⁇
  • G b ⁇ +1,+1,+1,-1,-1,-1,-1,+1,-1,-1,-1,+1,-1 ⁇
  • the HE-LTF sequence on the above 2X mode can be directly stored as:
  • FIG. 8a shows the PAPR value of the HE-LTF sequence in the 20 MHz bandwidth. It can be seen from the PAPR value that the PAPR value is still low when the pilot subcarrier and other subcarriers introduce different rotational phases.
  • the first set of PAPR values is the PAPR value corresponding to the 26 subcarrier resource blocks from left to right, wherein the first row of data 2.76, 3.68, 2.76, 3.68... refers to the value of the data position multiplied by +1, the pilot position
  • the value is multiplied by the PAPR value corresponding to the HELTF sequence when +1, which is from left to right 2.76 is the first 26 subcarrier resource block corresponding PAPR value, and the next 3.68 refers to the second 26 subcarrier from left to right.
  • the resource block corresponds to the PAPR value, and so on; the second row data 3.67, 2.76, 3.68, 2.76...
  • the fourth row of data 4.46, 3.30, 4.46, 3.30... means that the value of the data position is multiplied by w 2 , and the value of the pilot position is multiplied by the PAPR value corresponding to the HELTF sequence, which is sequentially from left to right.
  • the right 4.46 is the PAPR value corresponding to the first 26 subcarrier resource block, and the next 3.30 refers to the PAPR value corresponding to the second 26 subcarrier resource block from left to right, and so on;
  • the second group of PAPR values from left to right, the PAPR value corresponding to the second row 52 subcarrier resource block, wherein the first row data 4.68, 4.68, 4.33, 4.68... means that the value of the data position is multiplied by +1.
  • the value of the pilot position is multiplied by the PAPR value corresponding to the HELTF sequence at +1, which is from left to right, the first 4.68 is the corresponding 52PR carrier resource block corresponding to the PAPR value, and the second 4.68 refers to the left direction.
  • the second 52 subcarrier resource block of the right corresponds to the PAPR value, and so on;
  • the second row of data 4.68, 4.68, 4.48, 4.68 refers to the value of the data position multiplied by -1, the value of the pilot position is multiplied by +1, the PAPR value corresponding to the HELTF sequence, which is from left to right, first 4.68 is the corresponding 52PR carrier resource block corresponding PAPR value, the second 4.68 refers to the second 52 subcarrier resource block corresponding to the PAPR value from left to right, and so on;
  • the third row of data 4.69, 4.69, 4.35 4.69 means that the value of the data position is multiplied by w, and the value of the pilot position is multiplied by the PAPR value corresponding to the HELTF sequence, which is from left to right, and the first 4.69 is the first 52 subcarrier resource block.
  • the second 4.69 refers to the PAPR value corresponding to the second 52 subcarrier resource block from left to right, and so on.
  • the fourth row data 4.69, 4.69, 4.77, 4.69 refers to the value of the data position multiplied.
  • the value of w 2 , the location of the pilot is multiplied by the PAPR value corresponding to the HELTF sequence, which is from left to right, the first 4.69 is the corresponding 52PR carrier resource block corresponding to the PAPR value, and the second 4.69 is Refers to the second 52 subcarrier resource block corresponding to the PAPR value from left to right, and so on;
  • the third group of PAPR values is the PAPR value corresponding to the third row 106 subcarrier resource block from left to right, wherein the first row data 4.89 and 3.93 means that the value of the data position is multiplied by +1, and the value of the pilot position is multiplied.
  • the PAPR value corresponding to the HELTF sequence at +1, which is from left to right in sequence, 4.89 is the corresponding PAPR value of the first 106 subcarrier resource block
  • 3.93 refers to the corresponding PAPR value of the second 106 subcarrier resource block from left to right.
  • the second row of data 4.23, 4.76 means that the value of the data position is multiplied by -1, the value of the pilot position is multiplied by the PAPR value corresponding to the HELTF sequence, which is from left to right, and 4.23 is the first 106.
  • the subcarrier resource block corresponds to the PAPR value
  • 4.76 refers to the PAPR value corresponding to the second 106 subcarrier resource block from left to right
  • the third row data 4.79, 4.73 means that the value of the data position is multiplied by w, and the value of the pilot position is
  • the PAPR value corresponding to the HELTF sequence is multiplied by +1, which is from left to right in sequence
  • 4.79 is the corresponding PAPR value of the first 106 subcarrier resource block
  • 4.73 refers to the second 106 subcarrier resource block corresponding to PAPR from left to right.
  • 4.38,4.87 fourth line of data is the value of the position data are multiplied by w 2, the value of the position of the pilot sequence is multiplied by +1 HELTF
  • PAPR value sequentially from left to right, the first 4.38 106 corresponding to subcarrier resource block PAPR value 4.87 means 106 from left to right a second subcarrier resource block corresponding PAPR value.
  • the fourth group of data 5.31, 5.32, 5.48, 5.46 is the PAPR value corresponding to the fourth row 242 subcarrier resource block, wherein the first 5.31 means that the value of the data position is multiplied by +1, and the value of the pilot position is multiplied by + The PAPR value corresponding to the HELTF sequence at 1 o'clock; the second 5.32 means that the value of the data position is multiplied by -1, the value of the pilot position is multiplied by the PAPR value corresponding to the HELTF sequence when +1; the third 5.48 refers to the data position.
  • the values are multiplied by w, and the value of the pilot position is multiplied by the PAPR value corresponding to the HELTF sequence at +1; the first 5.46 means that the value of the data position is multiplied by w 2 , and the value of the pilot position is multiplied by +1.
  • the HE-LTF sequence in the 2x mode includes a Ga sequence and a sequence G c generated by the Ga and Gb sequences, G d , +1 or -1 at the position of the spare leftover subcarrier.
  • the contents of the foregoing sequences refer to the previous embodiments and will not be described again.
  • it also includes a continuous -G c , Or, continuous +G a , (or, as the consecutive -G d listed in the above sequence, Or, continuous +G a , continuously +G d .
  • the HE-LTF sequence in the aforementioned 2x mode can be directly stored as
  • the PAPR value using the above HE-LTF sequence is the same as that shown in Fig. 8a.
  • the HE-LTF sequence includes Ga and Gb sequences and sequences generated by Ga and Gb sequences.
  • G d , +1 or -1 located at the position of the spare leftover subcarrier may also contain a continuous +G a , Or continuous +G d , or continuous -G a , continuous -G b .
  • the specific content of each sequence refers to the foregoing embodiment, and details are not described herein again.
  • the HE-LTF sequence in the aforementioned 2x mode can be directly stored as
  • Figure 8b shows the PAPR value of the HE-LTF sequence in the 20MHz bandwidth. It can be seen from the set of PAPR values that the PAPR value is still low when the pilot subcarrier and other subcarriers introduce different rotational phases.
  • the first group of numbers is the PAPR value corresponding to the 26 subcarrier resource blocks from left to right, wherein the first row of data 2.76, 3.68, 2.76, 3.68... refers to the value of the data position multiplied by +1, the value of the pilot position
  • the PAPR value corresponding to the HELTF sequence is multiplied by +1, which is from left to right 2.76 is the first 26 subcarrier resource block corresponding PAPR value, and the next 3.68 refers to the second 26 subcarrier resources from left to right.
  • the block corresponds to the PAPR value, and so on; the second row of data 3.68, 2.76, 3.68, 2.76...
  • the first 26 subcarrier resource block corresponds to the PAPR value
  • the next 3.30 refers to the PAPR value corresponding to the second 26 subcarrier resource block from left to right, and so on;
  • the second group of numbers is the PAPR value corresponding to the second row 52 subcarrier resource block from left to right, wherein the first row data 4.68, 4.33, 4.68, 4.68 refers to the value of the data position multiplied by +1, the pilot position
  • the values are multiplied by the PAPR value corresponding to the HELTF sequence, which is from left to right.
  • the first 4.68 is the corresponding 52PR carrier resource block corresponding PAPR value
  • the second 4.33 refers to the second from left to right.
  • 52 subcarrier resource blocks correspond to PAPR values, and so on;
  • the second row of data 4.68, 4.48, 4.68, 4.68 means that the value of the data position is multiplied by -1, and the value of the pilot position is multiplied by +1.
  • the PAPR value corresponding to the HELTF sequence is sequentially from left to right, first 4.48 is the corresponding 52PR carrier resource block corresponding PAPR value, the second 4.68 refers to the second 52 subcarrier resource block corresponding to the PAPR value from left to right, and so on;
  • the third row of data 4.69, 4.35, 4.69 4.69 means that the value of the data position is multiplied by w, and the value of the pilot position is multiplied by the PAPR value corresponding to the HELTF sequence, which is from left to right, and the first 4.69 is the first 52 subcarrier resource block.
  • the second 4.35 refers to the PAPR value corresponding to the second 52 subcarrier resource block from left to right, and so on.
  • the fourth row data 4.69, 4.77, 4.69, 4.69 refers to the value of the data position multiplied by w 2
  • the value of the pilot position is multiplied by the PAPR value corresponding to the HELTF sequence when +1, which is from left to right
  • the first 4.69 is the corresponding 52PR carrier resource block corresponding PAPR value
  • the second 4.77 refers to The second 52 subcarrier resource block from left to right corresponds to the PAPR value, and so on;
  • the third group of data is the PAPR value corresponding to the third row 106 subcarrier resource block from left to right, wherein the first row data 3.93 and 4.89 means that the value of the data position is multiplied by +1, and the value of the pilot position is multiplied by
  • the second row of data 4.76, 4.23 means that the value of the data position is multiplied by -1, and the value of the pilot position is multiplied by +1.
  • the PAPR value corresponding to the HELTF sequence is sequentially from left to right, and 4.76 is the first 106.
  • the carrier resource block corresponds to the PAPR value
  • 4.23 refers to the PAPR value corresponding to the second 106 subcarrier resource block from left to right
  • the third row data 4.73 and 4.79 means that the value of the data position is multiplied by w, and the value of the pilot position is multiplied.
  • 4.73 is the corresponding PAPR value of the first 106 subcarrier resource block
  • 4.79 refers to the corresponding PAPR value of the second 106 subcarrier resource block from left to right.
  • the fourth row of data 4.87, 4.38 means that the value of the data position is multiplied by w 2 , and the value of the pilot position is multiplied by +1 when the HELTF sequence
  • Corresponding PAPR values which are sequentially from left to right, 4.87 is the corresponding 106-subcarrier resource block corresponding to the PAPR value, and 4.38 refers to the corresponding 106-hop PAPR value from the left to the right of the 106-subcarrier resource block.
  • the fourth group of data 5.31, 5.32, 5.48, 5.46 is the PAPR value corresponding to the fourth row 242 subcarrier resource block, wherein the first 5.31 means that the value of the data position is multiplied by +1, and the value of the pilot position is multiplied by + The PAPR value corresponding to the HELTF sequence at 1 o'clock; the second 5.32 means that the value of the data position is multiplied by -1, the value of the pilot position is multiplied by the PAPR value corresponding to the HELTF sequence when +1; the third 5.48 refers to the data position.
  • the values are multiplied by w, and the value of the pilot position is multiplied by the PAPR value corresponding to the HELTF sequence at +1; the first 5.46 means that the value of the data position is multiplied by w 2 , and the value of the pilot position is multiplied by +1.
  • the HE-LTF sequence includes a Gb sequence and a sequence G c generated by the Ga and Gb sequences, G d , +1 or -1 at the position of the spare leftover subcarrier, and further, may also include a continuous -G c , Or continuous +G b , or continuous +G c , continuous +G d .
  • the PAPR value of the above HE-LTF sequence is the same as that shown in FIG. 8b, and will not be described again here.
  • the illustrated RU size may be 26, 52, 106, 242, 484 subcarriers.
  • the HE-LTF sequence includes a Ga and Gb sequence and a sequence G c generated by the Ga and Gb sequences, G d , +1 or -1 at the position of the spare leftover subcarrier, and further, may further include: continuous -G c , Or, continuous -G a , Or, continuous +G a , Or continuous -G c , or continuous +G d , Or continuous -G d , or continuous -G b , or continuous +G b , or continuous -G d .
  • Figure 9 shows the PAPR value of the HE-LTF sequence in the 40MHz bandwidth. It can be seen from the PAPR value that the PAPR value is still low when the pilot subcarrier and other subcarriers introduce different rotational phases.
  • the first group of numbers is the PAPR value corresponding to the 26 subcarrier resource blocks from left to right, wherein the first row of data 2.76, 3.68, 2.76, 3.68... refers to the value of the data position multiplied by +1, the value of the pilot position
  • the PAPR value corresponding to the HELTF sequence is multiplied by +1, which is from left to right 2.76 is the first 26 subcarrier resource block corresponding PAPR value, and the next 3.68 refers to the second 26 subcarrier resources from left to right.
  • the block corresponds to the PAPR value, and so on; the second row of data 3.68, 2.76, 3.68, 2.76...
  • the first 26 subcarrier resource block corresponds to the PAPR value
  • the next 3.30 refers to the PAPR value corresponding to the second 26 subcarrier resource block from left to right, and so on;
  • the second group of numbers is the PAPR value corresponding to the second row 52 subcarrier resource block from left to right, wherein the first row data 4.68, 4.68, 4.34, 4.48... means that the value of the data position is multiplied by +1, pilot The value of the position is multiplied by the PAPR value corresponding to the HELTF sequence when it is +1, which is from left to right, the first 4.68 is the corresponding 52PR carrier resource block corresponding to the PAPR value, and the second 4.68 refers to the left to the right.
  • the second 52 subcarrier resource block corresponds to the PAPR value, and so on; the second row data 4.68, 4.68, 4.48, 4.34...
  • the PAPR value corresponding to the HELTF sequence is from left to right, the first 4.68 is the corresponding 52PR carrier resource block corresponding PAPR value, and the second 4.68 refers to the second 52 subcarrier resource block corresponding from left to right. PAPR value, and so on; third line data 4.69, 4.69, 4.35, 4.77... means that the value of the data position is multiplied by w, and the value of the pilot position is multiplied by +1.
  • the PAPR value corresponding to the HELTF sequence is sequentially Left to right, the first 4.69 is the first 52 subcarrier resource block corresponding to the PAPR value, and the second 4.69 is the second 52 from left to right.
  • the carrier resource block corresponds to the PAPR value, and so on; wherein the fourth row of data 4.69, 4.69, 4.77, 4.35 means that the value of the data position is multiplied by w 2 , and the value of the pilot position is multiplied by +1 when the HELTF sequence corresponds to the PAPR value.
  • the first 4.69 is the corresponding 52PR carrier resource block corresponding to the PAPR value
  • the second 4.69 refers to the second 52 subcarrier resource block corresponding to the PAPR value from left to right, and so on;
  • the third group of data is the PAPR value corresponding to the third row 106 subcarrier resource block from left to right, wherein the first row data 5.42, 4.34, 4.34, 5.42 means that the value of the data position is multiplied by +1, the pilot position The values are multiplied by the PAPR value corresponding to the HELTF sequence when +1, which is from left to right, 5.42 is the corresponding 106PR carrier resource block corresponding PAPR value, and 4.34 refers to the second 106 subcarrier resource block from left to right.
  • the second row of data 4.85, 5.50, 5.50, 4.85 means that the value of the data position is multiplied by -1, and the value of the pilot position is multiplied by the PALTF value corresponding to the HELTF sequence, which in turn From left to right, 4.85 is the PAPR value corresponding to the first 106 subcarrier resource block, 5.50 refers to the corresponding PAPR value of the second 106 subcarrier resource block from left to right, and so on;
  • the third row data is 4.94, 4.63, 4.63, 4.94 means that the value of the data position is multiplied by w, and the value of the pilot position is multiplied by the PAPR value corresponding to the HELTF sequence when it is +1, which is sequentially from left to right, and 4.94 is the corresponding PAPR value of the first 106 subcarrier resource block.
  • 4.63 refers to the PAPR value corresponding to the second 106 subcarrier resource block from left to right, and so on; the fourth row of data 4.6 8. 5.16, 5.16, 4.68 means that the value of the data position is multiplied by w 2 , and the value of the pilot position is multiplied by the PAPR value corresponding to the HELTF sequence, which is from left to right, and 4.68 is the first 106.
  • the carrier resource block corresponds to the PAPR value
  • 5.16 refers to the corresponding PAPR value of the second 106 subcarrier resource block from left to right.
  • the fourth group of data is the PAPR value corresponding to the third row 242 subcarrier resource block from left to right, wherein the first row data 5.32 and 5.32 means that the value of the data position is multiplied by +1, and the value of the pilot position is multiplied by The PALTF sequence corresponding to the HELTF sequence, which is from left to right, the first 5.32 is the PAPR value corresponding to the first 242 subcarrier resource block, and the second 5.32 refers to the second 242 subcarrier from left to right.
  • the resource block corresponds to the PAPR value;
  • the second row data 5.37 and 5.37 means that the value of the data position is multiplied by -1, and the value of the pilot position is multiplied by +1, and the PAPR value corresponding to the HELTF sequence is sequentially from left to right.
  • a 5.37 is the first 242 subcarrier resource block corresponding PAPR value
  • the second 5.37 refers to the second 242 subcarrier resource block corresponding to the PAPR value from left to right
  • the third row data 5.50, 5.50 refers to the data position
  • the values are multiplied by w, and the value of the pilot position is multiplied by the PAPR value corresponding to the HELTF sequence when it is +1, which is from left to right
  • the first 5.50 is the PAPR value corresponding to the first 242 subcarrier resource block
  • the second 5.50 means that the second 242 subcarrier resource block from left to right corresponds to the PAPR value
  • the fourth row data 5.39, 5.39 refers to the value of the data position.
  • PAPR sequence of values corresponding to time HELTF w 2 pilot position values are multiplied by +1 sequentially from left to right, the first 5.39 242 is the first subcarrier resource block corresponding PAPR value is 5.39 second Refers to the second 242 subcarrier resource block from left to right corresponding to the PAPR value;
  • the fifth group of data 6.00, 4.98, 6.15, 5.26 is the PAPR value corresponding to the fourth row 242 subcarrier resource block, wherein the first 6.00 means that the value of the data position is multiplied by +1, and the value of the pilot position is multiplied by + The PAPR value corresponding to the HELTF sequence at 1 o'clock; the second 4.98 means that the value of the data position is multiplied by -1, the value of the pilot position is multiplied by the PAPR value corresponding to the HELTF sequence when +1; the third 6.15 refers to the data position.
  • the values are multiplied by w, and the value of the pilot position is multiplied by the PAPR value corresponding to the HELTF sequence at +1; the first 5.26 means that the value of the data position is multiplied by w 2 , and the value of the pilot position is multiplied by +1.
  • the HE-LTF sequence includes a Ga and Gb sequence and a sequence G c generated by the Ga and Gb sequences, G d , +1 or -1 at the position of the spare leftover subcarrier,
  • it may contain continuous +G a , Or, continuous -G c , Or, continuous +G c , Or continuous -G a , or, continuous +G b , Or continuous -G d , or continuous +G d , or continuous +G b .
  • the PAPR value when the above HE-LTF sequence is used is the same as that shown in FIG. 9, and will not be described again.
  • the RU size may be 26, 52, 106, 242, 484, 996 subcarriers.
  • the first 80MHz 2X HE-LTF sequence The first 80MHz 2X HE-LTF sequence:
  • the HE-LTF sequence includes G a and G b sequences and sequences generated by the G a and G b sequences G c , G d , +1 or -1 at the position of the spare leftover subcarrier, further, may also contain consecutive -G a , Or, continuous +G c , +G b , or continuous -G a , or, continuous -G c , or, continuous -G c , Or, continuous -G a , -G d , or continuous -G c , or continuous +G a , continuous +G d , Or, continuous -G b , Or, continuous -G a , -G d , or, continuous -G a , -G d , or continuous -G b , or continuous G b , Or, continuous +G d , Or, continuous -G c , -G b , or continuous +G d .
  • Figure 10 shows the PAPR value of the HE-LTF sequence in the 80MHz bandwidth. It can be seen from the PAPR value that the PAPR value is still low when the pilot subcarrier and other subcarriers introduce different rotational phases.
  • the first group of numbers: from left to right is the PAPR value corresponding to the 26 subcarrier resource blocks, wherein the first row of data 2.76, 3.68, 2.76, 3.68... means that the value of the data position is multiplied by +1, the position of the pilot The value is multiplied by the PAPR value corresponding to the HELTF sequence when +1, which is from left to right 2.76 is the first 26 subcarrier resource block corresponding PAPR value, and the next 3.68 refers to the second 26 subcarrier from left to right.
  • the resource block corresponds to the PAPR value, and so on; the second row of data 3.68, 2.76, 3.68, 2.76...
  • the value of the data position is the value of the data position multiplied by +1, and the value of the pilot position is multiplied by -1 to the PAPR value corresponding to the HELTF sequence. It is from the left to the right 3.68 is the first 26 subcarrier resource block corresponding to the PAPR value, the next 2.76 refers to the second 26 subcarrier resource block corresponding to the PAPR value from left to right, and so on; the third row of data 3.30 4.46, 3.30, 4.46...
  • the value of the data position is multiplied by w, and the value of the pilot position is multiplied by the PAPR value corresponding to the HELTF sequence, which is the first 26 subcarrier resources from left to right.
  • the block corresponds to the PAPR value
  • the next 4.46 refers to the PAPR value corresponding to the second 26 subcarrier resource block from left to right.
  • Push; 4.46,3.30,4.46,3.30 ?? fourth line data is the value of the position data are multiplied by w 2, are multiplied by the value of PAPR of the pilot the position corresponding to the time sequence of values +1 HELTF, sequentially from left to right 4.46
  • the first 26 subcarrier resource block corresponds to the PAPR value
  • the next 3.30 refers to the PAPR value corresponding to the second 26 subcarrier resource block from left to right, and so on;
  • the second group of numbers is the PAPR value corresponding to the second row 52 subcarrier resource block from left to right, wherein the first row data 4.68, 4.68, 4.69, 4.69... means that the value of the data position is multiplied by +1, pilot The value of the position is multiplied by the PAPR value corresponding to the HELTF sequence when it is +1, which is from left to right, the first 4.68 is the corresponding 52PR carrier resource block corresponding to the PAPR value, and the second 4.68 refers to the left to the right.
  • the second 52 subcarrier resource block corresponds to the PAPR value, and so on; the second row data 4.68, 4.68, 4.69, 4.69...
  • the PAPR value corresponding to the HELTF sequence is from left to right, the first 4.68 is the corresponding 52PR carrier resource block corresponding PAPR value, and the second 4.68 refers to the second 52 subcarrier resource block corresponding from left to right.
  • the value of the data position is multiplied by w
  • the value of the pilot position is multiplied by the PALTF value corresponding to the HELTF sequence, which in turn Left to right
  • the first 4.68 is the first 52 subcarrier resource block corresponding PAPR value
  • the second 4.68 refers to the second 52 from left to right Carrier PAPR value corresponding to the resource blocks, and so on
  • 4.68,4.68,4.69,4.69 wherein the fourth row of data refers to the sequence corresponding to the PAPR value HELTF position value data are multiplied by w 2, pilot position values are multiplied by +1 , which is from left to right in sequence
  • the first 4.68 is the corresponding 52PR carrier resource block corresponding to the PAPR value
  • the second 4.68 refers to the second 52 subcarrier resource block corresponding to the PAPR value from left to right, and so on.
  • the third group of data is the PAPR value corresponding to the third row 106 subcarrier resource block from left to right, wherein the first row data 5.42, 5.33, 5.42, 5.33... refers to the value of the data position multiplied by +1.
  • the value of the pilot position is multiplied by the PAPR value corresponding to the HELTF sequence in the HELTF sequence when the HELTF sequence is +1, which is from left to right in sequence, 5.42 is the PAPR value corresponding to the first 106 subcarrier resource block, and 5.33 is from left to right.
  • the right second 106 subcarrier resource block corresponds to the PAPR value, and so on; the second row data 4.85, 5.41, 4.85, 5.41...
  • the PAPR value corresponding to the HELTF sequence in the HELTF sequence is from left to right, 4.85 is the PAPR value corresponding to the first 106 subcarrier resource block, and 5.50 refers to the corresponding PAPR value of the second 106 subcarrier resource block from left to right. , and so on; the third row of data 4.95, 5.18, 4.95, 5.18...
  • the PAPR value corresponding to the HELTF sequence is from left to right
  • 4.68 is the PAPR value corresponding to the first 106 subcarrier resource block
  • 4.97 refers to the corresponding PAPR value of the second 106 subcarrier resource block from left to right.
  • the fourth group of data is the PAPR value corresponding to the fourth row 242 subcarrier resource block from left to right, wherein the first row data 5.29 and 5.29 means that the value of the data position is multiplied by +1, and the value of the pilot position is multiplied by The PALTF value corresponding to the HELTF sequence at +1 +1 is from left to right, the first 5.29 is the PAPR value corresponding to the first 242 subcarrier resource block, and the second 5.29 is the second from left to right.
  • the 242 subcarrier resource block corresponds to the PAPR value
  • the second row data 5.58 and 5.58 means that the value of the data position is multiplied by -1, and the value of the pilot position is multiplied by +1, and the PAPR value corresponding to the HELTF sequence in the HELTF sequence is sequentially From left to right
  • the first 5.58 is the PAPR value corresponding to the first 242 subcarrier resource block
  • the second 5.58 refers to the PAPR value corresponding to the second 242 subcarrier resource block from left to right
  • the third row data is 5.40, 5.40 means that the value of the data position is multiplied by w, the value of the pilot position is multiplied by the PAPR value corresponding to the HELTF sequence, which is sequentially from left to right
  • the first 5.40 is the first 242 subcarrier resource block corresponding to PAPR value
  • the second 5.40 refers to the PAPR value corresponding to the second 242 subcarrier resource block from left to right
  • the fifth group of data is the PAPR value corresponding to the fifth row 484 subcarrier resource block from left to right, wherein the first row data 6.27, 6.13 means that the value of the data position is multiplied by +1, and the value of the pilot position is multiplied by +
  • the PAPR value corresponding to the HELTF sequence at 1 o'clock is from left to right
  • 6.27 is the corresponding PAPR value of the first 484 subcarrier resource block
  • 6.13 refers to the corresponding PAPR value of the second 484 subcarrier resource block from left to right
  • the two rows of data 6.11 and 6.40 mean that the values of the data positions are multiplied by -1, and the values of the pilot positions are multiplied by +1.
  • the PAPR values corresponding to the HELTF sequence in the HELTF sequence are sequentially left to right, and 6.11 is the first
  • the 242 subcarrier resource block corresponds to the PAPR value
  • 6.40 refers to the PAPR value corresponding to the second 484 subcarrier resource block from left to right
  • the third row data 6.24, 6.34 refers to the value of the data position multiplied by w, the value of the pilot position.
  • the PAPR value corresponding to the HELTF sequence is multiplied by +1, which is from left to right in sequence
  • 6.24 is the corresponding PAPR value of the first 484 subcarrier resource block
  • 6.34 refers to the second 484 subcarrier resource block corresponding from left to right.
  • PAPR value; the fourth row data 6.29, 6.25 means that the value of the data position is multiplied by w 2 , and the value of the pilot position is multiplied by +1.
  • the PAPR value corresponding to the HELTF sequence is from left to right in sequence, 6.29 is the corresponding PAPR value of the first 484 subcarrier resource block, and 6.25 refers to the corresponding PAPR value of the second 484 subcarrier resource block from left to right;
  • the sixth group of data 6.01, 5.68, 6.08, 5.92 is the PAPR value corresponding to the sixth row 996 subcarrier resource block, wherein the first 6.08 means that the value of the data position is multiplied by +1, and the value of the pilot position is multiplied by + The PAPR value corresponding to the HELTF sequence at 1 o'clock; the second 5.68 means that the value of the data position is multiplied by -1, the value of the pilot position is multiplied by the PAPR value corresponding to the HELTF sequence when +1; the third 6.08 refers to the data position.
  • the values are multiplied by w, the value of the pilot position is multiplied by the PAPR value corresponding to the HELTF sequence at +1; the fourth 5.92 is that the value of the data position is multiplied by w 2 , and the value of the pilot position is multiplied by +1.
  • the HE-LTF sequence includes G a and G b sequences and sequences generated by the G a and G b sequences G c , G d , Located at +1 or -1 at the position of the spare leftover subcarrier, further, may also contain consecutive +G c , Or, continuous +G a , +G d , or continuous +G c , or continuous -G a , or, continuous -G a , Or, continuous +G c , +G b , or continuous -G a , or, continuous -G c , continuous -G b , Or, continuous -G d , Or, continuous +G c , +G b , or continuous -G d , or continuous +G d , Or, continuous -G b , Or, continuous -G a , -G d , or continuous +G d , Or, continuous -G b , Or, continuous -G a ,
  • the corresponding PAPR value is the same as the PAPR value of the first HELTF sequence (shown in Figure 10).
  • the HE-LTF sequence includes G a and G b sequences and sequences generated by the G a and G b sequences G c , G d , +1 or -1 at the position of the spare leftover subcarrier, further, may also include a continuous -G a , Or, continuous +G c , +G b , or continuous -G a , or, continuous -G c , or continuous +G c , Or, continuous +G a , +G d , or continuous +G c , or continuous -G a , continuous -G d , Or, continuous +G b , Or, continuous +G a , Or, continuous +G a , +G d , or continuous +G b , or continuous +G b , Or, continuous +G d , Or, continuous -G c , -G b , or continuous +G d .
  • Figure 11 shows the PAPR value of the HE-LTF sequence in the 80MHz bandwidth. It can be seen from the PAPR value that the PAPR value is still low when the pilot subcarrier and other subcarriers introduce different rotational phases.
  • the first group of numbers: from left to right is the PAPR value corresponding to the 26 subcarrier resource blocks, wherein the first row of data 2.76, 3.68, 2.76, 3.68... means that the value of the data position is multiplied by +1, the position of the pilot The value is multiplied by the PAPR value corresponding to the HELTF sequence when +1, which is from left to right 2.76 is the first 26 subcarrier resource block corresponding PAPR value, and the next 3.68 refers to the second 26 subcarrier from left to right.
  • the resource block corresponds to the PAPR value, and so on; the second row of data 3.68, 2.76, 3.68, 2.76...
  • the value of the data position is the value of the data position multiplied by +1, and the value of the pilot position is multiplied by -1 to the PAPR value corresponding to the HELTF sequence. It is from the left to the right 3.68 is the first 26 subcarrier resource block corresponding to the PAPR value, the next 2.76 refers to the second 26 subcarrier resource block corresponding to the PAPR value from left to right, and so on; the third row of data 3.30 4.46, 3.30, 4.46...
  • the value of the data position is multiplied by w, and the value of the pilot position is multiplied by the PAPR value corresponding to the HELTF sequence, which is the first 26 subcarrier resources from left to right.
  • the block corresponds to the PAPR value
  • the next 4.46 refers to the PAPR value corresponding to the second 26 subcarrier resource block from left to right.
  • Push; 4.46,3.30,4.46,3.30 ?? fourth line data is the value of the position data are multiplied by w 2, are multiplied by the value of PAPR of the pilot the position corresponding to the time sequence of values +1 HELTF, sequentially from left to right 4.46
  • the first 26 subcarrier resource block corresponds to the PAPR value
  • the next 3.30 refers to the PAPR value corresponding to the second 26 subcarrier resource block from left to right, and so on;
  • the second group of numbers: from left to right is the PAPR value corresponding to the second row 52 subcarrier resource block, wherein the first row of data 4.68, 4.68, 4.69, 4.69, ... means that the value of the data position is multiplied by +1.
  • the value of the pilot position is multiplied by the PAPR value corresponding to the HELTF sequence at +1, which is from left to right, the first 4.68 is the corresponding 52PR carrier resource block corresponding to the PAPR value, and the second 4.68 refers to the left direction.
  • the second 52 subcarrier resource block corresponds to the PAPR value, and so on; the second row data 4.68, 4.68, 4.69, 4.69...
  • the PAPR value corresponding to the HELTF sequence is from left to right, the first 4.68 is the corresponding 52PR carrier resource block corresponding PAPR value, and the second 4.68 refers to the second 52 subcarrier resource block from left to right.
  • the value of the data position is multiplied by w, and the value of the pilot position is multiplied by the PALTF value corresponding to the HELTF sequence, which in turn From left to right, the first 4.68 is the first 52 subcarrier resource block corresponding to the PAPR value, and the second 4.68 refers to the second 52 from left to right.
  • the subcarrier resource block corresponds to the PAPR value, and so on; wherein the fourth row data 4.68, 4.68, 4.69, 4.69 refers to the value of the data position multiplied by w 2 , and the value of the pilot position is multiplied by +1 when the HELTF sequence corresponds to the PAPR
  • the third group of data from left to right is the PAPR value corresponding to the third row 106 subcarrier resource block, wherein the first row data 5.42, 5.33, 5.42, 5.33... refers to the value of the data position multiplied by +1.
  • the value of the pilot position is multiplied by the PAPR value corresponding to the HELTF sequence in the HELTF sequence when the HELTF sequence is +1, which is from left to right in sequence, 5.42 is the PAPR value corresponding to the first 106 subcarrier resource block, and 5.33 is from the left.
  • the second 106 subcarrier resource block to the right corresponds to the PAPR value, and so on; the second row data 4.85, 5.41, 4.85, 5.41...
  • the PALTF sequence corresponds to the PAPR value of the HELTF sequence, which is from left to right, 4.85 is the corresponding 106-subcarrier resource block corresponding to the PAPR value, and 5.50 refers to the second 106 subcarrier resource block corresponding to the PAPR from left to right. Value, and so on; third line data 4.95, 5.18, 4.95, 5.18... means that the value of the data position is multiplied by w, and the value of the pilot position is multiplied by +1.
  • the PAPR value corresponding to the HELTF sequence in the HELTF sequence is From left to right, 4.95 is the first 106 subcarrier resource block corresponding to the PAPR value, and 5.18 means from left to right.
  • the two 106 subcarrier resource blocks correspond to the PAPR value, and so on; the fourth row data 4.68, 4.97, 4.68, 4.97...
  • the PAPR value corresponding to the HELTF sequence in the sequence is from left to right, 4.68 is the PAPR value corresponding to the first 106 subcarrier resource block, and 4.97 refers to the corresponding PAPR value of the second 106 subcarrier resource block from left to right.
  • the fourth set of data is the fourth set of data.
  • the PAPR value corresponding to the fourth row 242 subcarrier resource block is sequentially, wherein the first row data 5.29 and 5.29 means that the value of the data position is multiplied by +1, and the value of the pilot position is multiplied by +1 when HELTF
  • the PAPR value corresponding to the HELTF sequence in the sequence is from left to right
  • the first 5.29 is the PAPR value corresponding to the first 242 subcarrier resource block
  • the second 5.29 refers to the second 242 subcarrier resource from left to right.
  • the block corresponds to the PAPR value
  • the second row data 5.58 and 5.58 means that the value of the data position is multiplied by -1, and the value of the pilot position is multiplied by +1.
  • the PAPR value corresponding to the HELTF sequence in the HELTF sequence is sequentially from left to right.
  • the first 5.58 is the PAPR value corresponding to the first 242 subcarrier resource block, and the second 5.58 refers to the corresponding PAPR value of the second 242 subcarrier resource block from left to right;
  • the third row data 5.40, 5.40 refers to data
  • the value of the position is multiplied by w, and the value of the pilot position is multiplied by the PAPR value corresponding to the HELTF sequence when it is +1, which is sequentially from left to right
  • the first 5.40 is the PAPR value corresponding to the first 242 subcarrier resource block
  • Two 5.40 refers to the PAPR value corresponding to the second 242 subcarrier resource block from left to right;
  • the fourth row data 5.46, 5.46 refers to the data bit.
  • the values are multiplied by w 2 , and the value of the pilot position is multiplied by the PAPR value corresponding to the HELTF sequence, which is from left to right, and the first 5.46 is the PAPR value corresponding to the first 242 subcarrier resource block.
  • the second 5.46 refers to the PAPR value corresponding to the second 242 subcarrier resource block from left to right;
  • the fifth group of data is the PAPR value corresponding to the fifth row 484 subcarrier resource block from left to right, wherein the first row data 6.13, 6.27 means that the value of the data position is multiplied by +1, and the value of the pilot position is multiplied by +
  • the PAPR value corresponding to the HELTF sequence at 1 o'clock, which is from left to right in sequence, 6.13 is the corresponding PAPR value of the first 484 subcarrier resource block, and 6.27 refers to the corresponding PAPR value of the second 484 subcarrier resource block from left to right;
  • the two rows of data 6.40 and 6.11 mean that the value of the data position is multiplied by -1, and the value of the pilot position is multiplied by +1.
  • the PAPR value corresponding to the HELTF sequence in the HELTF sequence is sequentially from left to right, and 6.40 is the first
  • the 242 subcarrier resource block corresponds to the PAPR value
  • 6.11 refers to the PAPR value corresponding to the second 484 subcarrier resource block from left to right
  • the third row data 6.34, 6.24 refers to the value of the data position multiplied by w, the value of the pilot position.
  • the PAPR value corresponding to the HELTF sequence is multiplied by +1, which is from left to right in sequence
  • 6.34 is the corresponding PAPR value of the first 484 subcarrier resource block
  • 6.24 refers to the second 484 subcarrier resource block corresponding from left to right.
  • PAPR value; the fourth row of data 6.25, 6.29 means that the value of the data position is multiplied by w 2 , and the value of the pilot position is multiplied by +1.
  • the PAPR value corresponding to the HELTF sequence is from left to right in sequence, 6.25 is the corresponding PAPR value of the first 484 subcarrier resource block, and 6.29 refers to the corresponding PAPR value of the second 484 subcarrier resource block from left to right.
  • the sixth group of data 6.01, 5.68, 6.08, 5.92 is the PAPR value corresponding to the sixth row 996 subcarrier resource block, wherein the first 6.08 means that the value of the data position is multiplied by +1, and the value of the pilot position is multiplied by + The PAPR value corresponding to the HELTF sequence at 1 o'clock; the second 5.68 means that the value of the data position is multiplied by -1, the value of the pilot position is multiplied by the PAPR value corresponding to the HELTF sequence when +1; the third 6.08 refers to the data position.
  • the values are multiplied by w, the value of the pilot position is multiplied by the PAPR value corresponding to the HELTF sequence at +1; the fourth 5.92 is that the value of the data position is multiplied by w 2 , and the value of the pilot position is multiplied by +1.
  • the HE-LTF sequence includes G a and G b sequences and sequences generated by the G a and G b sequences G c , G d , +1 or -1 at the position of the spare leftover subcarrier, further, may also include a continuous +G c , Or, continuous +G a , +G d , or continuous +G c , or continuous -G a or, continuous +G a Or, continuous -G c , -G b , or continuous +G a , or, continuous +G c , or continuous +G b , Or, continuous +G d , Or, continuous -G c , -G b , or continuous +G d , or, continuous +G d , Or, continuous -G b , Or, continuous -G a , -G d , or continuous -G b .
  • the corresponding PAPR value is the same as the PAPR value of the third HELTF sequence. See Figure 11 for details. It can be seen from the PAPR value of the group that when the pilot subcarrier and other subcarriers are introduced differently. When rotating the phase, the PAPR value is still very low.
  • the RU size shown in FIG. 1a may be 26, 52, 106, 242 subcarriers.
  • the HE-LTF sequence comprising the sequence G e and Ga and Gb generated sequence derived sequences G c, G d , -1 or +1 is located on leftover spare sub-carrier position, further, it may further contain consecutive -G c, Or, continuous +G d , Or, continuous -G c , Continuous +G d ,
  • Figure 12 shows the PAPR value of the HE-LTF sequence in the 20MHz bandwidth. It can be seen from the PAPR value that the PAPR value is still low when the pilot subcarrier and other subcarriers introduce different rotational phases.
  • the first group of numbers: from left to right is the PAPR value corresponding to the 26 subcarrier resource blocks, wherein the first row data 3.51, 3.78, 3.51, 3.78... refers to the value of the data position multiplied by +1, the pilot position
  • the value is multiplied by the PAPR value corresponding to the HELTF sequence when +1, which is from left to right, 3.51 is the corresponding 26PR carrier resource block corresponding PAPR value, and the next 3.78 refers to the second 26 subcarrier from left to right.
  • the resource block corresponds to the PAPR value, and so on; the second row data 3.78, 3.51, 3.78, 3.51...
  • the carrier resource block corresponds to the PAPR value
  • the next 3.48 refers to the PAPR value corresponding to the second 26 subcarrier resource block from left to right.
  • Times on; 3.48,3.28,3.48,3.28 & fourth line data refers PAPR value sequence corresponding to the value of the data position when HELTF are multiplied by w 2, pilot position values are multiplied by +1 sequentially from left to
  • the right 3.48 is the PAPR value corresponding to the first 26 subcarrier resource block
  • the next 3.28 refers to the PAPR value corresponding to the second 26 subcarrier resource block from left to right, and so on;
  • the second group of numbers: from left to right is the PAPR value corresponding to the second row 52 subcarrier resource block, wherein the first row data 4.42, 4.59, 4.63, 4.42 means that the value of the data position is multiplied by +1, the pilot position The values are multiplied by the PAPR value corresponding to the HELTF sequence, which is from left to right.
  • the first 4.42 is the corresponding 52PR carrier resource block corresponding PAPR value, and the second 4.59 refers to the left to right.
  • the two 52 subcarrier resource blocks correspond to the PAPR value, and so on;
  • the second row data 4.42, 4.63, 4.59, 4.42 means that the value of the data position is multiplied by -1, and the value of the pilot position is multiplied by +1 when the HELTF sequence corresponds.
  • the PAPR value is from left to right
  • the first 4.42 is the corresponding 52PR carrier resource block corresponding to the PAPR value
  • the second 4.63 is the second 52 subcarrier resource block corresponding to the PAPR value from left to right.
  • the third row of data 4.44, 4.86, 4.97, 4.42 means that the value of the data position is multiplied by w, and the value of the pilot position is multiplied by +1.
  • the PAPR value corresponding to the HELTF sequence is sequentially from left to right.
  • One 4.44 is the first 52 subcarrier resource block corresponding to the PAPR value
  • the second 4.86 is the second 52 subcarrier resource from left to right.
  • the third group of data from left to right is the PAPR value corresponding to the third row 106 subcarrier resource block, wherein the first row data 4.65, 4.90 means that the value of the data position is multiplied by +1, and the value of the pilot position is multiplied.
  • the second line of data 4.69, 5.01 means that the value of the data position is multiplied by -1, and the value of the pilot position is multiplied by the PAPR value of the HELTF sequence when it is +1, which is from left to right, and 4.69 is the first 106.
  • the subcarrier resource block corresponds to the PAPR value, and 5.01 refers to the PAPR value corresponding to the second 106 subcarrier resource block from left to right;
  • the third row data 4.90 and 4.95 means that the value of the data position is multiplied by w, and the value of the pilot position is
  • the PAPR value corresponding to the HELTF sequence is multiplied by +1, which is from left to right in sequence, 4.90 is the corresponding PAPR value of the first 106 subcarrier resource block, and 4.95 refers to the second 106 subcarrier resource block corresponding to PAPR from left to right.
  • the fourth row of data 4.92, 4.87 means that the value of the data position is multiplied by w 2 , and the value of the pilot position is multiplied by +1 when the HELTF sequence
  • the PAPR value corresponding to the column is from left to right in sequence
  • 4.92 is the PAPR value corresponding to the first 106 subcarrier resource block
  • 4.87 refers to the corresponding PAPR value of the second 106 subcarrier resource block from left to right.
  • the fourth group of data 5.26, 5.30, 5.29, 5.56 is the PAPR value corresponding to the fourth row 242 subcarrier resource block, wherein the first 5.26 means that the value of the data position is multiplied by +1, and the value of the pilot position is multiplied by + The PAPR value corresponding to the HELTF sequence at 1 o'clock; the second 5.30 means that the value of the data position is multiplied by -1, the value of the pilot position is multiplied by the PAPR value corresponding to the HELTF sequence when +1; the third 5.29 refers to the data position.
  • the values are multiplied by w, and the value of the pilot position is multiplied by the PAPR value corresponding to the HELTF sequence at +1; the first 5.56 means that the value of the data position is multiplied by w 2 , and the value of the pilot position is multiplied by +1.
  • the HE-LTF sequence comprises a sequence G e, Ga and Gb sequences and derived sequences Ga and Gb generated sequence +1 or -1 at the position of the spare leftover subcarrier. Further, the HE-LTF sequence may further include: continuous +G a , Or, continuous +G b , Or, continuous +G a , Or, continuous +G b , Or +G e (1:13), +G e (14:26).
  • the corresponding PAPR value is the same as the PAPR value of the first HELTF sequence. Referring to FIG. 12, it can be seen that the pilot subcarrier and other subcarriers introduce different rotations. At phase, the PAPR value is still very low.
  • the RU size may be 26, 52, 106, 242, 484 subcarriers as shown in FIG. 1b.
  • the HE-LTF sequence includes a Ga and Gb sequence and a sequence G c generated by the Ga and Gb sequences, G d , +1 or -1 at the position of the spare leftover subcarrier,
  • it may also include a continuous -G a , Or, continuous -G c , Or, continuous +G a , Or continuous +G b , or continuous +G d , or continuous -G b .
  • Figure 13 shows the PAPR value of the HE-LTF sequence in the 40 MHz bandwidth. It can be seen from the PAPR value of the group that the PAPR value is still low when the pilot subcarrier and other subcarriers introduce different rotational phases.
  • the data reading method in the table can refer to the previous implementation manner, and details are not described herein again.
  • the HE-LTF sequence includes a Ga and Gb sequence and a sequence G c generated by the Ga and Gb sequences, G d , +1 or -1 at the position of the spare leftover subcarrier,
  • it may also include a continuous G c , Or, continuous +G a , Or, continuous, -G c , Or continuous +G d , or continuous +G b , or continuous +G b .
  • the corresponding PAPR value is the same as the PAPR value of the first HELTF sequence. Referring to FIG. 13, it can be seen that the pilot subcarrier and other subcarriers introduce different rotations. Phase At the time, the PAPR value is still very low.
  • the 80 MHz bandwidth has 1024 subcarriers.
  • the RU size may be 26, 52, 106, 242, 484, and 996 subcarriers as shown in FIG. 1c.
  • the first 80MHz bandwidth 4x mode HE-LTF sequence is the first 80MHz bandwidth 4x mode HE-LTF sequence:
  • the HE-LTF sequence includes Ge, Ga and Gb sequences and a sequence G c generated by the Ga and Gb sequences, G d , +1 or -1 at the position of the spare leftover subcarrier,
  • it may also include a continuous +G c , Or, continuous +G a , Or, continuous -G c , Or, continuous +G a , Or, continuous -G c , Or, continuous +G a , Or, continuous -G c , Or, continuous -G a , Or, continuous -G d , Or, continuous -G b , Continuous +G d , Or, continuous -G b , Or, continuous +G d , Or, continuous +G b , Alternatively, -G e (1:13), - G e (14:26).
  • Figure 14 shows the PAPR value of the HE-LTF sequence in the 80MHz bandwidth. It can be seen from the PAPR value that the PAPR value is still low when the pilot subcarrier and other subcarriers introduce different rotational phases.
  • the HE-LTF sequence includes Ge, Ga and Gb sequences and a sequence G c generated by the Ga and Gb sequences, G d , +1 or -1 at the position of the spare leftover subcarrier,
  • it may also include a continuous -G a , Or, continuous -G c , Or, continuous +G a , Or, continuous -G c , Or, continuous +G a , Or, continuous +G c , Or, continuous -G b , Continuous -G d , Or, continuous +G b , Or, continuous -G d , Or, continuous +G b , Or, continuous +G d , Or -G e (1:13), - G e (14:26).
  • the corresponding PAPR value is the same as the PAPR value of the first HELTF sequence.
  • the PAPR value of the group can be seen as the pilot subcarrier. When different rotational phases are introduced with other subcarriers, the PAPR value is still very low.
  • the 4x symbol subcarrier design of 160MHz bandwidth can be spliced by two 80MHz bandwidth 4x symbol subcarrier designs.
  • the main 80M band and the auxiliary 80M band can be continuously spliced or separated by a certain bandwidth (for example, 100MHz interval), and the main 80M band and auxiliary 80M.
  • the frequency band can be flexibly adjusted according to the actual situation before and after the frequency band. Therefore, we can define the 4x HE-LTF sequence (LTF 80MHz_prime ) of the main 80M band and the 4x HE-LTF sequence (LTF 80MHz_second ) of the auxiliary 80M band, respectively , and adjust it flexibly according to the interval and band order. Polarity to achieve a lower PAPR.
  • HE-LTF 160MHz [P1*LTF 80MHz_prime , BI, P2*LTF 80MHz_second ]; when the relationship between the two 80M channels is [auxiliary 80M, main 80M]
  • BI refers to the frequency spacing between two 80M channel edge subcarriers.
  • BI zeros(1,23), that is, 23 zeros;
  • zeros(1,23) represents 23 zeros; the remaining undisplayed subcarrier indication numbers (eg: -1024:-1013 and 1013:1023, etc.) The value at the corresponding position defaults to 0.
  • the BI can be adjusted accordingly
  • the HE-LTF sequence on the 996 subcarrier 4X symbol corresponding to the main 80 MHz (LTF 80 MHz_prime ) bandwidth is the first 80 MHz bandwidth 4 ⁇ mode HE-LTF sequence in Embodiment 6, and the main 80 MHz bandwidth 996.
  • the HE-LTF sequence on the subcarrier 4X symbol can be expressed as:
  • LTF 80MHz_prime [ ⁇ 1st-484-RU ⁇ , ⁇ central-26-RU ⁇ , ⁇ 2nd-484-RU ⁇ ]
  • the central-26-RU is expressed as:
  • central-26-RU ⁇ -G e (1:13), +1,0,0,0,0,0,+1,-G e (14:26) ⁇
  • Auxiliary 80MHz (LTF 80MHz_second ) bandwidth 996 subcarrier 4X symbol HE-LTF sequence is composed of 1st-484-RU, 2nd-484-RU and the new central-26-RU (newCentral-26-RU), of which newCentral -26-RU can be expressed as:
  • newCentral-26-RU [+1,+1,+1,-1,-1,-1,+1,+1,-1,-1,-1,-1,+1,0 ,0,0,0,0,0,0,0,-1,-1,-1,+1,-1,+1,+1,+1,+1,-1,+1,+1,-1 ]
  • LTF 80MHz_second can be expressed as follows:
  • LTF 80MHz_second [ ⁇ 1st-484-RU ⁇ , newCentral-26-RU, (-1) * ⁇ 2nd-484-RU ⁇ ];
  • the polarity adjustment coefficients of the main 80MHz bandwidth and the auxiliary 80MHz bandwidth in the two frequency bands and various frequency intervals are shown in the following table, where the primary and secondary channel spacing refers to the center frequency interval of the two 80M bands (interval 80MHz refers to It is a mosaic of two adjacent 80M channels).
  • the corresponding PAPR values in various cases are also shown in the table, where the PAPR value is the maximum value of the phase difference between the data and the pilot.
  • the 2x symbol subcarrier design of 160MHz bandwidth can be spliced by two 80MHz bandwidth 2x symbol subcarrier designs.
  • the main 80M band and the auxiliary 80M band can be continuously spliced or separated by a certain bandwidth (for example, 100MHz interval), and the main 80M band and auxiliary 80M.
  • the frequency band can be flexibly adjusted according to the actual situation before and after the frequency band. Therefore, we can define the 2x HE-LTF sequence (LTF 80MHz_prime ) of the main 80M band and the 2x HE-LTF sequence (LTF 80MHz_second ) of the auxiliary 80M band, respectively , and adjust them flexibly according to the interval and band order as a whole in the 80M sequence. Polarity to achieve a lower PAPR.
  • HE-LTF 160MHz [P1*LTF 80MHz_prime , BI, P2*LTF 80MHz_second ]; when the relationship between the two 80M channels is [auxiliary 80M, main 80M]
  • BI refers to the frequency spacing between two 80M channel edge subcarriers.
  • BI zeros(1,11), that is, 11 zeros
  • the HE-LTF 160MHz sequence can be expressed as:
  • zeros(1,11) represents 11 zeros; the remaining undisplayed subcarrier indication numbers (eg: -1024: -1013, 1013:1023, and -1011:2:1011, etc.) have default values of 0. .
  • the BI can be adjusted accordingly
  • the HE-LTF sequence on the 2X symbol corresponding to the main 80 MHz (LTF 80 MHz_prime ) bandwidth is the second 80 MHz 2X HE-LTF sequence in Embodiment 3, and the HE in the main 80 MHz bandwidth 2X symbol.
  • the LTF sequence can be expressed as:
  • LTF 80MHz_prime [ ⁇ 1st-484-RU ⁇ , ⁇ central-26-RU ⁇ , ⁇ 2nd-484-RU ⁇ ]
  • the central-26-RU is expressed as:
  • central-26-RU ⁇ +1,-1,-1,-1,+1,+1,0,0,0,+1,-1,-1,+1,+1,- 1,+1 ⁇
  • the HE-LTF sequence on the 2X symbol of the auxiliary 80MHz (LTF 80MHz_second ) bandwidth is composed of 1st-484-RU, 2nd-484-RU, and new central-26-RU (newCentral-26-RU), of which newCentral-26- RU can be expressed as:
  • newCentral-26-RU [-1,-1,+1,-1,-1,-1,0,0,0,+1,+1,-1,-1,-1,+ 1,-1]
  • LTF 80MHz_second can be expressed as follows:
  • LTF 80MHz_second [ ⁇ 1st-484-RU ⁇ , newCentral-26-RU, (-1) * ⁇ 2nd-484-RU ⁇ ];

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Abstract

本发明实施例提供几种无线局域网中的遵循802.11ax的长训练序列。

Description

传输HE-LTF序列的方法和装置
本申请要求于2015年8月26日提交中国专利局、申请号为201510532381.2、发明名称为“传输信息的方法、接入点和站点”，以及，于2015年11月26日提交中国专利局、申请号为201510849062.4、发明名称为“传输HE-LTF序列的方法和装置”的中国专利申请的优先权，其全部内容通过引用结合在本申请中。
技术领域
本发明涉及无线通信技术领域，并且更具体地，涉及传输HE-LTF序列的方法和装置。
背景技术
随着移动互联网的发展和智能终端的普及，数据流量快速增长。无线局域网(WLAN，Wireless Local Area Network)凭借高速率和低成本方面的优势，成为主流的移动宽带接入技术之一。
为了大幅提升WLAN系统的业务传输速率，下一代电气和电子工程师协会(IEEE，Institute of Electrical and Electronics Engineers)802.11ax标准将会在现有正交频分复用(OFDM，Orthogonal Frequency Division Multiplexing)技术的基础上，进一步采用正交频分多址(OFDMA，Orthogonal Frequency Division Multiple Access)技术。OFDMA技术将空口无线信道时频资源划分成多个正交的时频资源块(RB，Resource Block)，RB之间在时间上可以是共享的，而在频域上是正交的。
在现有的WiFi系统(如11n或11ac)中，终端仍在使用载波侦听冲突避免的竞争方式进行信道接入。当用户数量增加时，由于信道接入冲突增加，使得系统平均吞吐量急速下降。在目前新的WiFi标准(11ax)工作中，已经决定将OFDMA技术引入到WiFi系统，以达成高密场景下提升系统平均吞吐量的目标。LTF作为现有WiFi系统中用于信道估计的重要部分，也被沿用到新WiFi标准中的OFDMA模式。因此，在OFDMA模式下，LTF的生成方式成为一个研究热点。
现有技术中，以802.11ac标准中80MHz的LTF或160MHz的LTF作为基本模板，从中抽取OFDMA模式中用户调度的资源块对应的载波部分的值，资源块未对应的载波部分的值用0填充，生成OFDMA模式下用户使用的LTF。然而，采用现有技术的方法，峰值平均功率比(Peak to Average Power Ratio，以下简称：PAPR)较高。
发明内容
本发明实施例提供一种发送无线局域网信息的方法，以降低峰值平均功率比。
一方面，提供了一种发送无线局域网信息的方法，包括：
根据带宽获得相应的HE-LTF序列,所述HE-LTF序列具体为各实施方式中的序列；
根据为站点分配的RU大小和RU位置，发送所述HE-LTF序列中的相应的序列段。
另一方面，一种接收无线局域网PPDU的方法，包括：
接收PPDU，获得PPDU中指示的传输总带宽；
根据带宽获得相应的HE-LTF序列,所述HE-LTF序列具体为各实施方式中的序列；
根据RU大小和RU位置，选择对应的HE-LTF序列段，作为接收端对应所述RU的信道估计参考序列。
相应的，提供了用于执行前述中方法的装置，例如AP或者STA,或者相应的芯片。
采用本发明实施方式提供的HE-LTF序列，在下一代无线局域网中，具有比较低的PAPR。
附图说明
为了更清楚地说明本发明实施例或现有技术中的技术方案，下面将对实施例或现有技术描述中所需要使用的附图作一简单地介绍，显而易见地，下面描述中的附图是本发明的一些实施例，对于本领域普通技术人员来讲，在不付出创造性劳动的前提下，还可以根据这些附图获得其他的附图。
图1a、1b、1c分别为本发明实施例采用OFDMA传输方式的不同带宽下的tone plan；
图2a、2b是如果沿用802.11ac的LTF仿真得到的PAPR的示意图。
图3为本发明实施例一种无线局域网的简单示意图；
图4为本发明实施例一种多用户传输方式下的PPDU的数据结构简单示意图；
图5a、5b、5c、5d分别为本发明实施例发明实施例采用OFDMA传输方式的不同带宽下包含导频位置的tone plan；
图6为一种较差实施方式下仿真得到的PAPR的示意图。
图7a，7b分别为本发明实施方式在上下行方向上的简单示意图。
图8a、图8b分别为20MHz带宽下一种采用较优2x HE-LTF序列仿真得到的PAPR值。
图9为40MHz下一种采用较优2x HE-LTF序列仿真得到的PAPR值。
图10、图11分别为80MHz下一种采用较优2x HE-LTF序列仿真得到的PAPR值。
图12为20MHz带宽下一种采用较优4x HE-LTF序列仿真得到的PAPR值。
图13为40MHz带宽下一种采用较优4x HE-LTF序列仿真得到的PAPR值。
图14为80MHz带宽下一种采用较优4x HE-LTF序列仿真得到的PAPR值。
图15是本发明一实施例的接入点的框图。
图16是本发明一实施例的站点的框图。
具体实施方式
下面将结合本发明实施例中的附图，对本发明实施例中的技术方案进行清楚、完整地描述，显然，所描述的实施例是本发明的一部分实施例，而不是全部实施例。基于本发明中的实施例，本领域普通技术人员在没有做出创造性劳动的前提下所获得的所有其他实施例，都应属于本发明保护的范围。
为方便理解，将下面实施方式中可能出现的术语解释如下：
AP    Access point    接入点
HEW    High efficiency WLAN    高效无线局域网
HE-LTF High efficiency Long training field    高效长训练序列
OFDMA    Orthogonal Frequency Division Multiple Access    正交频分多址
STA    Station                   站点
WLAN    Wireless Local Area Networks    无线局域网
接入点(AP，Access Point)，也可称之为无线访问接入点或桥接器或热点等，其可以接入服务器或通信网络。
站点(STA，Station)，还可以称为用户，可以是无线传感器、无线通信终端或移动终端，如支持WiFi通讯功能的移动电话(或称为“蜂窝”电话)和具有无线通信功能的计算机。例如，可以是支持WiFi通讯功能的便携式、袖珍式、手持式、计算机内置的，可穿戴的，或者车载的无线通信装置，它们与无线接入网交换语音、数据等通信数据。
下一代无线局域网标准802.11ax致力于进一步提升WLAN频谱效率、区域吞吐量、实际用户体验以及各种室内外密集网络部署环境下的性能，同时该方案还要求能够抑制设备间干扰，满足大规模、高负载组网需求等。传统WiFi主要应用于室内信道，OFDM传输方式，符号长度为3.2us,子载波间隔为1/3.2us＝312.5kHz。20MHz内用64-FFT构造OFDM符号，总共56个子载波中有52个数据子载波和4个子载波，40MHz内用128-FFT构造OFDM符号，总共128个子载波中有108个数据子载波和6个子载波，而256-FFT构造OFDM符号，总共256个子载波中有234个数据子载波和8个子载波。
802.11ax系统为了支持室内室外场景，可以采用4倍于802.11ac的符号长度(4x3.2us＝12.8us)，子载波间隔为312.5/4＝78.125kHz。并且为了支持OFDMA传输，采用以下tone plan(承载数据的子载波分布)，不同资源块(RU:resource unit)的位置关系如图1a-1c，其中箭头表示RU间残留子载波(leftover tone)的位置，大的RU子载波个数和对应其中可容纳的多个小RU以及小RU间残留子载波个数总和相同。
参考图1a，为20MHz内OFDMA可分配的资源块(英文为tone plan，或者称为资源块分布)的简单示意图，图1b，为40MHz内OFDMA资源块位置的简单示意图，图1c，为80MHz内OFDMA资源块位置的简单示意图。802.11ax中OFDMA多用户数据包是多种大小的资源块(RU:resource unit)组合而成，AP分配给每个用户一个RU，可能分配给用户的可选RU有：
1)连续26个子载波组成的RU，包括：24个数据子载波和2个pilot导频子载波；
2)连续52个子载波组成的RU，包括：48个数据子载波和4个pilot导频子载波；
3)连续106个子载波组成的RU，包括：24个数据子载波和2个pilot导频子载波；
4)连续242个子载波组成的RU，包括：234个数据子载波和8个pilot导频子载波；
5)连续484个子载波组成的RU，包括：468个数据子载波和16个pilot导频子载波；
6)连续996个子载波组成的RU，包括：980个数据子载波和16个pilot导频子载波。
其中484-RU是在40MHz的多用户传输中使用，而996-RU是在80/160MHz的多用户传输中使用。160MHz可以看作2个80MHz的tone plan组成。图1a，1b，1c中箭头所指的子载波位置是前述导频子载波的位置。
另外，802.11ax系统中用于信道估计的HE-LTF采用2x和4x两种模式，4x模式是指，HE-LTF序列映射的子载波号index和数据部分的资源块分布tone plan中的子载波的序号相同；而2x模式是指，HE-LTF序列号对应于4x HE-LTF的序号数除以2，即HE-LTF序列映射的子载波号index和数据部分的资源块分布tone plan中的子载波的序号的一半相同。
802.11ax系统中OFDMA传输的tone plan(子载波分布)，和现有的802.11ac系统中OFDM的tone plan不同。所以802.11ac中定义的20/40的VHT-LTF序列本身不能适用。具体一个情况下，802.11ac中80MHz的子载波总数242和802.11ax中20MHz的子载波总数相同，但是直接在802.11ax 20MHz带宽内采用VHT-LTF序列发现能量峰值和均值比(PAPR：Peak-to-average power ratio)比较高。
参考图2a、2b，可以看出，如果802.11ac 80MHz的VHT-LTF用于802.11ax 20MHz，其 PAPR和传统LTF序列的PAPR相比显著提高，影响功控效率，进而降低信道估计精度。
另外，802.11ax在40/80MHz的tone plan，子载波个数已经超过传统序列，无法重用802.11ac的VHT-LTF序列。
图3为一个本发明实施方式应用的WLAN系统的简单示意图。图3的系统包括一个或者多个接入点AP101和一个或者多个站点STA102。接入点101和站点102之间采用OFDMA技术进行无线通信。
参考图4，为上述下行WLAN系统一种可能的的AP发送数据包PPDU的帧结构，具体例子中，其遵循802.11ax的相关规定。
根据图4所示的PPDU的数据结构，对于AP发送的下行多用户PPDU，在HE-SIG-A中包含用于指示下行用户STA传输带宽的信息，在HE-SIG-B中包含用于指示下行被调度的用户所分配的RU大小以及位置的信息，或者，还包含每个被调度用户对应的STA ID以及其他空间流号或者调制编码等调度信息。其中一个例子中，在HE-SIG-A或者HE-SIG-B中还可以包含：用于指示多个用户对齐的HE-LTF长度，即HE-LTF的符号数N。
另外的实施方式中，针对HE-LTF的OFDMA的子载波分布tone plan中每个RU，给出了导频子载波的个数，导频子载波的位置以及发送方式。相应的内容可以参考《Motion#3,October 29,2014,Removed with Motion 10,March 6,2015 below》
例如，参考图5a，5b，5c，图5d，在图1a，1b，1c所示的tone plan基础上，指出了导频子载波的位置，即图5a，5b，5c，图5d中长箭头所示的位置。例如，发送方式为：802.11ax的HE-LTF中导频在单用户，上下行OFDMA以及下行MU-MIMO传输时按照单流发送(类似802.11ac)。
具体的例子中，上行MU-MIMO传输时，每个STA的HE-LTF序列在频率上乘以AP分配的识别码，AP可以依靠每个STA的频率识别码估计出每个STA的CFO，所以上行MU-MIMO的HE-LTF序列中没有特殊的导频子载波，和下行MU-MIMO的HE-LTF序列不同。
在一些较差的实施方式中，提供了一些HE-LTF或者构造HE-LTF的方法，但是都没有考虑pilot的影响，相应的方法中PAPR比较高。
例如，一种较差的实施方式中，提供一组长度为13的Barker序列即x，根据该Barker序列生成长度为121序列，用M1表示，同时找到长度分别为13和7的Barker序列，分别用M2和M3表示。具体序列的表示如下：
x＝[+1 +1 +1 -1 -1 -1 +1 -1 -1 +1 -1]；％Barker 11 tones
M1＝[-x,x,-x,-x,x,-x,-x,-x,x,x,x]；％121 tones
M2＝[+1 +1 +1 +1 +1 -1 -1 +1 +1 -1 +1 -1 +1]；％Barker 13 tones
M3＝[+1 +1 +1 -1 -1 +1 -1]；％Barker 7 tones
接着，使用x、M1、M2、M3序列构造2x/4x模式下的HELTF序列。构造的HELTF序列如下：
2x模式下的HELTF序列：
20MHz 122 tones 2X sequence:
LTF242(-122:2:122)＝[M1(61:121),0,M1(1:61)]；
40MHz 242tones 2X sequence:
LTF484(-244:2:244)＝[M1,0,0,0,M1]；
80MHz 498 tones 2X sequence:
LTF996(-500:2:500)＝[-M1,-M1,M3,0,0,0,M3,M1,-M1]；
4x模式下的HELTF序列：
20MHz 242tones 4X sequence:
LTF242(-122:122)＝[M1,0,0,0,M1]；
40MHz 484 tones 4X sequence:
LTF484＝[M1,M1,0,0,0,0,0,M1,-M1]；
80MHz 996 tones 4X sequence:
LTF996＝
[M1,-M1,-M1,-M1,M2,1,0,0,0,0,0,1,M2,M1,-M1,M1,M1]；
但是，分析前述图5a，5b，5c或者5d中HE-LTF中的导频子载波和其他子载波乘以不同相位的所有情况，可以看出不同情况下的PAPR变动幅度大，有些情况下PAPR比较大。前面提到的情况指：导频子载波相位变化对应于P-maxtrix中的第一行，其他子载波相位变化随着空间流对应P-matrix中的对应行。这些情况可以概括成为下面四种情况：在导频子载波不改变相位，固定乘以'+1’的情况下，其他子载波改变相位，分别乘以‘+1’，‘-1’，‘w’或者‘w2’，其中w＝exp(-1i*2*pi/6)。
比如，现有技术方案一中时候PAPR的结果如下，其中导频子载波不改变相位，固定乘以’+1’，而其他子载波改变相位，分别乘以‘+1’，‘-1’，‘w’或者‘w2’，对应每一行的PAPR如图6所示。可以看出，PAPR变动幅度大，有的PAPR已经超过了7dB。
下面提供一些实施方式，相应的HE-LTF序列在由于pilot位置设置不同的值的情况下，PAPR都比较低。
在有一些较优实施方式中，同时还可以使得硬件实现中存储量低，容易实现等需求。
一方面，提供了一种发送HE-LTF序列的方法，包括：
根据带宽获得相应的HE-LTF序列,所述HE-LTF序列具体为后续各实施方式中的序列；
根据资源分配信息中的RU大小和RU位置，发送所述HE-LTF序列相应位置的序列段。
参考图7a，7b，为上述方法在上下行方向上的简单示意图。
为了使上述方法更为清楚，下面针对上行、下行的传输流程详细介绍：
下行的传输过程：
AP发送数据包PPDU，其中，所述PPDU可以参考图4所示的结构，其中包括：
101：AP根据传输总带宽获得对应该带宽的HE-LTF序列。
该HE-LTF序列可以是存储在AP上的，也可以是根据一定的原则构造得到的。其具体举例可以参考后续各实例。
102：根据被调度的用户被分配的资源块RU大小和RU位置，从HE-LTF序列中获得对应的HE-LTF序列段，将该HE-LTF序列段映射在该分配的RU子载波位置上发送出去。
较优的例子中，该PPDU包含多流/多用户传输，HE-LTF需要在N个符号上发送，其中N应该大于等于在每个RU上对应所分配用户的总流数的最大值M，记为N>＝M,其中，N＝1,2,4,6或8，M＝1～8。AP给RU上的每个流顺序分配大小为NxN的P-matrix矩阵中的一行作为用于区分流的特征码。具体的：发送RU上每个流的HE-LTF序列时，HE-LTF的第n个符号上的tone plan除去导频子载波位置以外长度值，需乘以对应用于区分该流的特征码的第n位码字。本领域技术人员知道，导频子载波位置的处理按照已有的技术方案进行处理，此处不再赘述。
下行被调度的STA在接收802.11ax的数据包PPDU的方法，包括：
201：被调度的STA接收PPDU，得到HE-SIG-A中AP所指示的传输总带宽。
202：根据传输总带宽获得对应该带宽的HE-LTF序列。
该HE-LTF序列可以是存储在AP或者STA上的，也可以是根据一定的原则构造得到的。其具体举例可以参考后续各实施例。
203：被调度的STA根据PPDU中的HE-SIG-B，用自己的STA ID识别出自己被调度的指示信息，其中得到AP给该用户分配的RU大小以及RU位置。按照指示的RU大小和位置，从对应所述传输总带宽的大小的HE-LTF序列中，选择对应的HE-LTF序列段，作为接收端对应该RU的信道估计参考序列，以进行后续的信道估计操作，其原理在此不在赘述。
上行的传输过程：
上行STA发送802.11ax的数据包PPDU可以参考前述的图4，AP通过触发帧指示上行调度信息，包含上行用户STA传输带宽，上行被调度的STA ID以及为该STA所分配的RU大小以及位置，或者，上行多个用户对齐的HE-LTF长度。其中，HE-LTF长度即符号数N，在每个RU上对应所分配用户的总流数的最大值为M，N>＝M,N＝1,2,4,6或8，M＝1～8。
上行STA发送802.11ax的数据包PPDU时
301：STA根据指示的传输总带宽大小获得对应该带宽的HE-LTF序列。
该HE-LTF序列可以是存储在AP或者STA上的，也可以是根据一定的原则构造得到的。其具体举例可以参考后续各实施例。
302：STA根据所分配的资源块RU大小和RU位置，从HE-LTF序列中选择对应位置的HE-LTF序列段，以便于映射在所述分配的RU子载波位置上发送出去。
303：按照指示的HE-LTF长度发送N个符号，其中每个符号上都承载了HE-LTF。
相应的，上行AP接收802.11ax的数据包PPDU时，包括：
401：AP根据传输总带宽获得对应该带宽的HE-LTF序列。
该HE-LTF序列可以是存储在AP上的，也可以是根据一定的原则构造得到的。其具体举例可以参考后续各实施例。
402：AP根据每一个上行被调度的用户(站点)所分配的资源块RU大小和RU位置，从HE-LTF序列中选择对应的HE-LTF序列段，作为该RU的参考序列，进行信道估计。
本领域技术人员知道，遵循802.11ax的数据包可以有SU，MU，或者OFDMA等传输模式或者数据结构。本发明各实施方式提出的HE-LTF序列不限于应用在特定数据结构，而是可以应用于各种遵循802.11ax标准的的数据包的传输。例如，当SU的传输模式下，前述各实施方式提到的为站点分配的资源块RU大小和RU位置即为当前传输使用的整个带宽， 本文不再赘述。
本发明一个实施方式中，提供了一种构造HE-LTF序列的方法，可以应用于前述各实施方式中，特别的，针对802.11ax OFDMA tone plan中不同资源块RU的大小以及位置：
501：选取OFDMA子载波布局中小RU长度的一个或者一组基本HE-LTF序列。这里的小RU，可以指前面提到的子载波数量为26的RU。针对4x模式，该基本HE-LTF序列为长度为26的子序列，对于2x模式，因为HE-LTF序列号对应于4x HE-LTF的序号数除以2，2x模式下的基本HE-LTF序列为长度为13的子序列。
502：根据OFDMA tone plan中不同RU的大小和位置，重复该基本HE-LTF序列，或者重复该一组基本HE-LTF序列中的一个，并以该基本HE-LTF序列为单位进行+1或者-1相位旋转。
503：将通过相位旋转后的若干基本HE-LTF序列级联，构造出针对大RU的HE-LTF序列，进一步根据大RU对应的若干小RU之间的残留子载波的个数和位置，在相应的位置上填充+1或者-1。
504：在传输带宽内从小RU级联到大RU，选择各种RU的PAPR最优的PAPR序列，作为该带宽对应的HE-LTF序列。
需要说明的是，对于不同带宽，按照上述方法所构造完成的HE-LTF序列可以分别存储在无线局域网中的AP和STA端，以便于直接在前面提到的上下行传输过程中使用。
下面进行一些更具体的实施方式的说明。前面各实施方式中，提到不同OFDMA的子载波映射方式下，发射机(AP或者STA)根据不同的带宽大小、RU位置以及RU大小，发送不同的HE-LTF序列。包括：
601根据带宽大小选个一个HE-LTF序列，所述一个HE-LTF序列有两种形式，分别对应802.11ax中的2x和4x模式。
较优的，2x模式下HE-LTF包含：子序列Ga与子序列Gb、位于空余leftover子载波位置上的+1或者-1；所述Ga与Gb是由+1或-1组成的长度为13的序列。具体的例子中，Ga和Gb分别为：
Ga＝{+1,+1,+1,-1,+1,+1,+1,-1,+1,-1,-1,+1,-1}
Gb＝{+1,+1,+1,-1,-1,-1,-1,+1,-1,-1,-1,+1,-1}
该2x模式下HE-LTF，还可以包含根据Ga与Gb生成的序列。这里我们将根据Ga与Gb生成的序列称作衍生序列，具体包括但不限于：
Ga序列导频位置上的值反转相位后得到的序列，可以表示为
Figure PCTCN2016096973-appb-000001
Gb序列导频位置上的值反转相位后得到的序列，可以表示为
Figure PCTCN2016096973-appb-000002
Ga序列偶数位的子载波上的值反转相位后得到的序列，可以表示为Gc。
Gb序列偶数位的子载波上的值反转相位后得到的序列，可以表示为Gd。
另外，还一个进一步包括：Gc序列导频位置上的值反转相位后得到的序列，可以表达为
Figure PCTCN2016096973-appb-000003
以及，Gd序列导频位置上的值反转相位后得到的序列，可以表示为
Figure PCTCN2016096973-appb-000004
上述衍生序列可以通过如下公式生成：
Figure PCTCN2016096973-appb-000005
Gc＝Ga·*Gxp    Gd＝Gb·*Gxp
Figure PCTCN2016096973-appb-000006
其中，Gap＝{+1,+1,-1,+1,+1,+1,+1,+1,+1,-1,+1,+1,+1}，意味着在导频位置(即序号为第3、第10的子载波位置)取反。
Gbp＝{+1,+1,+1,-1,+1,+1,+1,+1,+1,+1,-1,+1,+1}，意味着在导频位置(即序号为第4、第11的子载波位置)取反。
Gxp＝{+1,-1,+1,-1,+1,-1,+1,-1,+1,-1,+1,-1,+1}，意味着在偶数的位置上取反。
需要说明的是，上述Ga，Gc，
Figure PCTCN2016096973-appb-000007
Gb，Gd，
Figure PCTCN2016096973-appb-000008
具有如下的关系。
1、Ga序列IFFT后的PAPR值与Gc序列IFFT后的PAPR值相等。
2、序列Ga，Gc，
Figure PCTCN2016096973-appb-000009
和
Figure PCTCN2016096973-appb-000010
的导频位置上的值经过不同的相位变换后，IFFT后的最大的PAPR值是相同的。
3、Gb及其衍生序列与Ga及其衍生序列一样，具有上述1、2描述的相同的性质
本领域技术人员可以知道，前述衍生序列可以有不同的表达方式，例如，前述Gc替 换为
Figure PCTCN2016096973-appb-000011
Gd替换为
Figure PCTCN2016096973-appb-000012
替换为
Figure PCTCN2016096973-appb-000013
替换为
Figure PCTCN2016096973-appb-000014
其本质没有不同。或者，全部基础子序列以及相应的衍生序列有不同的表达方式。
4x模式下HELTF包含：序列Ga、子序列Gb以及位于空余leftover子载波位置上的+1或者-1；所述Ga或者Gb是由+1或-1组成的长度为26的序列。具体的：
Ga＝[+1 +1 +1 +1 +1 +1 -1 +1 +1 +1 -1 +1 +1 -1 -1 -1 +1 -1 +1 -1 -1 +1 +1 -1 +1 -1]；
Gb＝[+1 +1 +1 +1 -1 -1 +1 +1 +1 +1 +1 -1 +1 +1 -1 -1 -1 +1 -1 -1 -1 +1 -1 +1 -1 +1]；
该4x模式下HE-LTF，还可以包含根据Ga或者Gb生成的序列。这里我们将Ga或者Gb生成的序列称作衍生序列，包括但不限于：
Ga序列导频位置上的值反转相位后得到的序列，可以记为
Figure PCTCN2016096973-appb-000015
Gb序列导频位置上的值反转相位后得到的序列，可以记为
Figure PCTCN2016096973-appb-000016
Ga序列偶数位的子载波上的值反转相位后得到的序列，可以记为Gc。
Gb序列偶数位的子载波上的值反转相位后得到的序列，可以记为Gd。
Gc序列导频位置上的值反转相位后得到的序列，可以记为
Figure PCTCN2016096973-appb-000017
Gd序列导频位置上的值反转相位后得到的序列，可以记为
Figure PCTCN2016096973-appb-000018
其中，上述衍生序列可以通过如下公式生成：
Figure PCTCN2016096973-appb-000019
Gc＝Ga·*Gxp    Gd＝Gb·*Gxp
Figure PCTCN2016096973-appb-000020
其中，
Gap＝{1,1,1,1,1,-1,1,1,1,1,1,1,1,1,1,1,1,1,1,-1,1,1,1,1,1,1}意味着在
导频位置(即序号为第6、第20的子载波)上取反。
Gbp＝{1,1,1,1,1,1,-1,1,1,1,1,1,1,1,1,1,1,1,1,1,-1,1,1,1,1,1}意味着在导频位置(即序号为第7、第21的子载波)上取反。
Gxp＝{+1,-1,+1,-1,+1,-1,+1,-1,+1,-1,+1,-1,+1-1,+1,-1,+1,-1,+1,-1,+1,-1,+1,-1,+1,-1}意味着在偶数的位置上取反。
需要说明的是，上述Ga，Gc，
Figure PCTCN2016096973-appb-000021
Gb，Gd，
Figure PCTCN2016096973-appb-000022
具有如下的关系。
1、Ga序列IFFT后的PAPR值与Gc序列IFFT后的PAPR值相等。
2、序列Ga，Gc，
Figure PCTCN2016096973-appb-000023
和
Figure PCTCN2016096973-appb-000024
的导频位置上的值经过不同的相位变换后，IFFT后的最大的PAPR值是相同的。
3、Gb及其衍生序列与Ga及其衍生序列一样，具有上述1、2描述的相同的性质。
本领域技术人员可以知道，前述各子序列以及衍生序列可以有不同的表达方式，例如，前述Gc替换为
Figure PCTCN2016096973-appb-000025
Gd替换为
Figure PCTCN2016096973-appb-000026
替换为
Figure PCTCN2016096973-appb-000027
替换为
Figure PCTCN2016096973-appb-000028
其本质没有不同。或者，全部基础子序列以及相应的衍生序列有不同的表达方式，其本质没有不同。
较优的实施方式中，所述HE-LTF序列对于不同的2x/4x模式，进一步包含不同的衍生序列的组合。
针对Ga、Gb序列以及其生成的不同的衍生序列，2x模式下的级联组合包含但不限于下述序列之一或者任意组合：
Figure PCTCN2016096973-appb-000029
针对Ga、Gb序列以及其生成的不同的衍生序列，4x模式下的级联组合包含但不限于下述序列之一或者任意组合：
Figure PCTCN2016096973-appb-000030
当然，根据序列的不同的表达方式，上述级联组合也可以有相应的不同的表达方式，其内容没有实质不同。
这里需要说明下，在无线局域网的AP或者STA中，可以仅存储子序列Ga与子序列Gb，在需要发送PPDU时，构造HE-LTF序列后发送，也可以直接把前述的HE-LTF序列存储在AP或者STA中，在需要时在相应的子载波上发送。
602，根据资源分配信息中的RU大小和RU位置，发送所述HE-LTF序列。
具体的，参考图1a，1b，1c等tone plan，将HE-LTF序列相应位置上的子序列段，放在对应位置的子载波上发送出去。
下面，提供一些更为具体的HE-LTF序列，这些序列都具有前述的PAPR较低的特性。
实例一
2x模式下20MHz带宽2x符号上有128个子载波，按照不同的资源块大小，如图1a所示，RU大小可以是13、26、54、121个子载波。
针对20MHz 121子载波2X模式上HE-LTF序列有很多种，下面仅罗列出其中较优的几种：
Figure PCTCN2016096973-appb-000031
本领域技术人员知道，-122:2:122指的是序号为-122～122的子载波中的偶数位置的子载波，即具体为序号是{-122,-120,...,-2,0,+2,...,+120,+122}的那些载波，在这些子载波的位置上的值是上面的序列中相应位置的元素，其他位置上的子载波的值是0，后续不再赘述上述表达方式。
该HE-LTF序列中包括Ga与Gb序列以及由Ga与Gb序列生成的序列
Figure PCTCN2016096973-appb-000032
Gc，
Figure PCTCN2016096973-appb-000033
(具体内容参考前面的陈述)，位于空余leftover子载波位置上的+1或者-1，进一步的，还可以包含连续的+Ga,
Figure PCTCN2016096973-appb-000034
或者，连续的+Gb,
Figure PCTCN2016096973-appb-000035
或者，连续的+Gc,
Figure PCTCN2016096973-appb-000036
连续的
Figure PCTCN2016096973-appb-000037
-Gb等。其中，Ga＝{+1,+1,+1,-1,+1,+1,+1,-1,+1,-1,-1,+1,-1}
Gb＝{+1,+1,+1,-1,-1,-1,-1,+1,-1,-1,-1,+1,-1}
上述序列的细节以及构造的过程参考前面的2x模式下HE-LTF序列的说明。
更具体的，上述2X模式上HE-LTF序列可以直接存储为：
HELTF2x(-122:2:122)＝
[+1，+1，+1，+1，-1，+1，+1，+1，-1，+1，-1，-1，+1，-1，-1，
-1，+1，+1，-1，-1，-1，+1，-1，-1，+1，-1，+1，+1，+1，+1，
-1，-1，-1，-1，+1，-1，-1，-1，+1，-1，+1，+1，+1，+1，-1，
-1，-1，+1，-1，-1，+1，+1，-1，-1，-1，+1，-1，-1，+1，-1，
+1，0，-1，-1，-1，+1，+1，-1，-1，-1，+1，-1，+1，+1，+1，
-1，+1，+1，+1，+1，-1，-1，-1，-1，+1，+1，-1，-1，+1，-1，
-1，-1，+1，+1，+1，+1，-1，-1，-1，-1，+1，+1，+1，-1，+1，
+1，-1，-1，+1，-1，-1，-1，+1，+1，+1，+1，-1，+1，+1，+1，
-1，+1，-1]
图8a为20MHz带宽下采用上述HE-LTF序列的PAPR值，通过该组PAPR值可以看出，当导频子载波和其他子载波引入不同的旋转相位时，PAPR值仍然很低。
第一组PAPR值从左向右依次是26子载波资源块对应的PAPR值，其中第一行数据2.76、3.68、2.76、3.68……是指data位置的值都乘以+1，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右2.76是第一个26子载波资源块对应PAPR值，接下来的3.68是指从左向右第二个26子载波资源块对应PAPR值，依次类推；第二 行数据3.67、2.76、3.68、2.76……是指data位置的值都乘以-1，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右3.68是第一个26子载波资源块对应PAPR值，接下来的2.76是指从左向右第二个26子载波资源块对应PAPR值，依次类推；第三行数据3.30、4.46、3.30、4.46……是指data位置的值都乘以w，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右3.30是第一个26子载波资源块对应PAPR值，接下来的4.46是指从左向右第二个26子载波资源块对应PAPR值，依次类推；第四行数据4.46、3.30、4.46、3.30……是指data位置的值都乘以w2，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右4.46是第一个26子载波资源块对应PAPR值，接下来的3.30是指从左向右第二个26子载波资源块对应PAPR值，依次类推；
第二组PAPR值：从左向右依次是第二行52子载波资源块对应的PAPR值，其中第一行数据4.68、4.68、4.33、4.68…是指data位置的值都乘以+1，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右，第一个4.68是第一个52子载波资源块对应PAPR值，第二个4.68是指从左向右第二个52子载波资源块对应PAPR值，依次类推；
其中第二行数据4.68、4.68、4.48、4.68是指data位置的值都乘以-1，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右，第一个4.68是第一个52子载波资源块对应PAPR值，第二个4.68是指从左向右第二个52子载波资源块对应PAPR值，依次类推；其中第三行数据4.69、4.69、4.35、4.69是指data位置的值都乘以w，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右，第一个4.69是第一个52子载波资源块对应PAPR值，第二个4.69是指从左向右第二个52子载波资源块对应PAPR值，依次类推；其中第四行数据4.69、4.69、4.77、4.69是指指data位置的值都乘以w2，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右，第一个4.69是第一个52子载波资源块对应PAPR值，第二个4.69是指从左向右第二个52子载波资源块对应PAPR值，依次类推；
第三组PAPR值从左向右依次是第三行106子载波资源块对应的PAPR值，其中第一行数据4.89、3.93是指data位置的值都乘以+1，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右，4.89是第一个106子载波资源块对应PAPR值，3.93是指从左向右第二个106子载波资源块对应PAPR值；第二行数据4.23、4.76是指data 位置的值都乘以-1，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右，4.23是第一个106子载波资源块对应PAPR值，4.76是指从左向右第二个106子载波资源块对应PAPR值；第三行数据4.79、4.73是指data位置的值都乘以w，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右，4.79是第一个106子载波资源块对应PAPR值，4.73是指从左向右第二个106子载波资源块对应PAPR值；第四行数据4.38、4.87是指data位置的值都乘以w2，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右，4.38是第一个106子载波资源块对应PAPR值，4.87是指从左向右第二个106子载波资源块对应PAPR值。
第四组数据5.31、5.32、5.48、5.46是第四行242子载波资源块对应的PAPR值，其中第一个5.31是指data位置的值都乘以+1，pilot位置的值都乘以+1时HELTF序列对应的PAPR值；第二个5.32是指data位置的值都乘以-1，pilot位置的值都乘以+1时HELTF序列对应的PAPR值；第三个5.48是指data位置的值都乘以w，pilot位置的值都乘以+1时HELTF序列对应的PAPR值；第一个5.46是指data位置的值都乘以w2，pilot位置的值都乘以+1时HELTF序列对应的PAPR值。
第二种2x模式下的HE-LTF序列：
Figure PCTCN2016096973-appb-000038
该2x模式下的HE-LTF序列中包括Ga序列以及由Ga与Gb序列生成的序列Gc，
Figure PCTCN2016096973-appb-000039
Figure PCTCN2016096973-appb-000040
Gd，
Figure PCTCN2016096973-appb-000041
位于空余leftover子载波位置上的+1或者-1。前述各序列的内容参考前面的实施方式，不再赘述。
进一步的，还包含连续的-Gc,
Figure PCTCN2016096973-appb-000042
或者，连续的+Ga,
Figure PCTCN2016096973-appb-000043
(或者，如上述序列中列出的连续的-Gd,
Figure PCTCN2016096973-appb-000044
或者，连续的+Ga,
Figure PCTCN2016096973-appb-000045
连续的
Figure PCTCN2016096973-appb-000046
+Gd。
当然，前述2x模式下的HE-LTF序列可以直接存储为
HELTF2x(-122:2:122)＝
[+1，-1，+1，-1，-1，-1，+1，-1，-1，-1，-1，+1，+1，+1，-1，
+1，+1，-1，-1，+1，-1，-1，-1，+1，+1，+1，+1，-1，+1，-1，
-1，+1，-1，+1，+1，+1，-1，+1，+1，+1，+1，-1，+1，-1，-1，
+1，-1，-1，-1，+1，+1，-1，-1，+1，-1，-1，-1，+1，+1，+1，
+1，0，-1，+1，-1，-1，+1，+1，-1，+1，+1，+1，+1，-1，+1，
+1，+1，-1，+1，-1，-1，+1，-1，+1，+1，-1，-1，+1，+1，+1，
-1，+1，+1，-1，+1，-1，-1，+1，-1，+1，+1，-1，+1，+1，+1，
-1，-1，+1，+1，+1，-1，+1，+1，-1，+1，-1，-1，-1，+1，-1，
-1，-1，-1]
采用上述HE-LTF序列的PAPR值与图8a中所示相同。
第三种2x模式下的HE-LTF序列：
Figure PCTCN2016096973-appb-000047
该HE-LTF序列中包括Ga与Gb序列以及由Ga与Gb序列生成的序列
Figure PCTCN2016096973-appb-000048
Gd，
Figure PCTCN2016096973-appb-000049
位于空余leftover子载波位置上的+1或者-1，进一步的，还可以包含连续的+Ga,
Figure PCTCN2016096973-appb-000050
或者，连续的
Figure PCTCN2016096973-appb-000051
+Gd，或者，连续的-Ga，连续的
Figure PCTCN2016096973-appb-000053
-Gb。各序列的具体内容参考前述实施方式，不再赘述。
前述2x模式下的HE-LTF序列可以直接存储为
HELTF2x(-122:2:122)＝
[+1，+1，+1，+1，-1，+1，+1，+1，-1，+1，-1，-1，+1，-1，-1，
-1，+1，+1，-1，-1，-1，+1，-1，-1，+1，-1，+1，+1，-1，+1，
-1，-1，+1，-1，-1，-1，+1，+1，-1，-1，+1，-1，+1，+1，-1，
+1，-1，-1，-1，+1，-1，-1，-1，-1，+1，-1，-1，+1，+1，-1，
+1，0，-1，-1，-1，-1，+1，+1，+1，-1，+1，+1，-1，-1，+1，
+1，+1，-1，+1，+1，-1，+1，-1，-1，-1，-1，+1，-1，-1，-1，
+1，-1，+1，+1，-1，+1，-1，-1，-1，-1，+1，+1，+1，-1，+1，
+1，-1，-1，+1，-1，-1，-1，+1，+1，+1，+1，-1，+1，+1，+1，
-1，+1，-1]
。
图8b给出20MHz带宽下HE-LTF序列的PAPR值，通过该组PAPR值可以看出，当导频子载波和其他子载波引入不同的旋转相位时，PAPR值仍然很低。
第一组数字从左向右依次是26子载波资源块对应的PAPR值，其中第一行数据2.76、3.68、2.76、3.68……是指data位置的值都乘以+1，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右2.76是第一个26子载波资源块对应PAPR值，接下来的3.68是指从左向右第二个26子载波资源块对应PAPR值，依次类推；第二行数据3.68、2.76、3.68、2.76……是data位置的值都乘以-1，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右3.68是第一个26子载波资源块对应PAPR值，接下来的2.76是指从左向右第二个26子载波资源块对应PAPR值，依次类推；第三行数据3.30、4.46、4.46、3.30……是data位置的值都乘以w，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右3.30是第一个26子载波资源块对应PAPR值，接下来的4.46是指从左向右第二个26子载波资源块对应PAPR值，依次类推；第四行数据4.46、3.30、3.30、4.46……是data位置的值都乘以w2，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右4.46是第一个26子载波资源块对应PAPR值，接下来的3.30是指从左向右第二个26子载波资源块对应PAPR值，依次类推；
第二组数字从左向右依次是第二行52子载波资源块对应的PAPR值，其中第一行数据4.68、4.33、4.68、4.68是指data位置的值都乘以+1，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右，第一个4.68是第一个52子载波资源块对应PAPR值，第二个4.33是指从左向右第二个52子载波资源块对应PAPR值，依次类推；
其中第二行数据4.68、4.48、4.68、4.68是指data位置的值都乘以-1，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右，第一个4.48是第一个52子载波资源块对应PAPR值，第二个4.68是指从左向右第二个52子载波资源块对应PAPR值，依次类推；其中第三行数据4.69、4.35、4.69、4.69是指data位置的值都乘以w，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右，第一个4.69是第一个52子载波资源块对应PAPR值，第二个4.35是指从左向右第二个52子载波资源块对应PAPR值，依次类推；其中第四行数据4.69、4.77、4.69、4.69是指data位置的值都乘以w2，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右，第一个4.69是第一个52子载波资源块对应PAPR值，第二个4.77是指从左向右第二个 52子载波资源块对应PAPR值，依次类推；
第三组数据从左向右依次是第三行106子载波资源块对应的PAPR值，其中第一行数据3.93、4.89是指data位置的值都乘以+1，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右，3.93是第一个106子载波资源块对应PAPR值，4.89是指从左向右第二个106子载波资源块对应PAPR值；第二行数据4.76、4.23是指data位置的值都乘以-1，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右，4.76是第一个106子载波资源块对应PAPR值，4.23是指从左向右第二个106子载波资源块对应PAPR值；第三行数据4.73、4.79是指data位置的值都乘以w，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右，4.73是第一个106子载波资源块对应PAPR值，4.79是指从左向右第二个106子载波资源块对应PAPR值；第四行数据4.87、4.38是指data位置的值都乘以w2，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右，4.87是第一个106子载波资源块对应PAPR值，4.38是指从左向右第二个106子载波资源块对应PAPR值。
第四组数据5.31、5.32、5.48、5.46是第四行242子载波资源块对应的PAPR值，其中第一个5.31是指data位置的值都乘以+1，pilot位置的值都乘以+1时HELTF序列对应的PAPR值；第二个5.32是指data位置的值都乘以-1，pilot位置的值都乘以+1时HELTF序列对应的PAPR值；第三个5.48是指data位置的值都乘以w，pilot位置的值都乘以+1时HELTF序列对应的PAPR值；第一个5.46是指data位置的值都乘以w2，pilot位置的值都乘以+1时HELTF序列对应的PAPR值。
第四种2x模式下的HE-LTF序列：
Figure PCTCN2016096973-appb-000054
该HE-LTF序列中包括Gb序列以及由Ga与Gb序列生成的序列Gc，
Figure PCTCN2016096973-appb-000055
Gd，位于空余leftover子载波位置上的+1或者-1，进一步的，还可以包含连续的-Gc,
Figure PCTCN2016096973-appb-000056
或者，连续的
Figure PCTCN2016096973-appb-000057
+Gb，或者，连续的
Figure PCTCN2016096973-appb-000058
+Gc，连续的
Figure PCTCN2016096973-appb-000059
+Gd。
除了可以采用其他的序列表达方式外
也可以直接存储为：
HELTF2x(-122：2：122)＝
[+1，-1，+1，-1，-1，-1，+1，-1，-1，-1，-1，+1，+1，+1，-1，
+1，+1，-1，-1，+1，-1，-1，-1，+1，+1，+1，+1，-1，-1，-1，
-1，+1，+1，+1，-1，+1，+1，-1，-1，+1，+1，+1，+1，-1，-1，
-1，-1，+1，-1，-1，-1，+1，-1，+1，+1，+1，-1，-1，+1，+1，
+1，0，-1，+1，-1，+1，+1，-1，+1，+1，+1，-1，-1，+1，+1，
-1，+1，+1，+1，-1，-1，-1，-1，+1，-1，+1，+1，+1，-1，+1，
+1，+1，+1，-1，-1，-1，-1，+1，-1，+1，+1，-1，+1，+1，+1，
-1，-1，+1，+1，+1，-1，+1，+1，-1，+1，-1，-1，-1，+1，-1，
-1，-1，-1]
。
采用上述HE-LTF序列的PAPR值，和图8b所示相同，此处不再赘述。
实例二
40MHz带宽2x符号上有512个子载波，按照不同的资源块大小，如图1b。所示RU大小可以是26、52、106、242、484个子载波。
40MHz 484子载波2X模式下的HE-LTF序列有很多种，下面仅罗列出其中的几种：
第一种40MHz2X模式下HE-LTF序列：
Figure PCTCN2016096973-appb-000060
该HE-LTF序列中包括Ga与Gb序列以及由Ga与Gb序列生成的序列Gc，
Figure PCTCN2016096973-appb-000061
Figure PCTCN2016096973-appb-000062
Gd，位于空余leftover子载波位置上的+1或者-1，进一步的，还可以包含：连续的-Gc,
Figure PCTCN2016096973-appb-000063
或者，连续的-Ga,
Figure PCTCN2016096973-appb-000064
或者，连续的+Ga,
Figure PCTCN2016096973-appb-000065
或者，连续的
Figure PCTCN2016096973-appb-000066
-Gc，或者，连续的+Gd,
Figure PCTCN2016096973-appb-000067
或者，连续的
Figure PCTCN2016096973-appb-000068
-Gd，或者，连续的
Figure PCTCN2016096973-appb-000069
-Gb，或者，连续的
Figure PCTCN2016096973-appb-000070
+Gb，或者，连续的
Figure PCTCN2016096973-appb-000071
-Gd。上述序列的内容可以参考前述40MHz带宽2x 符号上的各序列。
除上述序列可以有其他表达方式外，还可以直接存储为
HELTF2x(-244：2：244)＝
[+1，-1，+1，-1，-1，-1，+1，-1，-1，-1，-1，+1，+1，+1，-1，
+1，+1，-1，-1，+1，-1，-1，-1，+1，+1，+1，+1，-1，-1，-1，
-1，+1，-1，-1，-1，+1，-1，+1，+1，-1，+1，+1，+1，-1，-1，
+1，+1，+1，-1，+1，+1，-1，+1，-1，-1，+1，-1，+1，+1，-1，
+1，+1，+1，-1，-1，+1，+1，+1，+1，+1，+1，-1，+1，+1，+1，
-1，+1，-1，-1，+1，-1，+1，+1，-1，-1，+1，+1，+1，-1，+1，
+1，-1，+1，-1，+1，+1，-1，-1，+1，+1，-1，+1，+1，+1，-1，
-1，-1，-1，-1，+1，-1，-1，-1，+1，-1，-1，-1，-1，+1，+1，
+1，0，0，0，+1，-1，+1，+1，-1，+1，-1，-1，-1，+1，-1，
-1，-1，+1，-1，+1，-1，-1，+1，-1，-1，-1，+1，+1，-1，-1，
+1，+1，+1，+1，+1，-1，-1，-1，+1，-1，-1，+1，+1，-1，-1，
-1，-1，+1，+1，+1，+1，-1，+1，+1，+1，-1，+1，-1，+1，-1，
-1，+1，+1，-1，+1，+1，+1，-1，-1，-1，-1，+1，+1，+1，+1，
-1，-1，-1，+1，-1，-1，+1，+1，-1，+1，+1，+1，-1，-1，-1，
-1，+1，-1，-1，-1，+1，-1，+1，+1，-1，+1，-1，-1，+1，-1，
-1，-1，+1，+1，-1，-1，-1，+1，-1，-1，+1，-1，+1，+1，+1，
-1，+1，+1，+1，+1]
。
本领域技术人员知道，上面的序列用前述表达式简要表达应该为：
Figure PCTCN2016096973-appb-000072
图9给出40MHz带宽下HE-LTF序列的PAPR值，通过该组PAPR值可以看出，当导频子载波和其他子载波引入不同的旋转相位时，PAPR值仍然很低
第一组数字从左向右依次是26子载波资源块对应的PAPR值，其中第一行数据2.76、3.68、2.76、3.68……是指data位置的值都乘以+1，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右2.76是第一个26子载波资源块对应PAPR值，接下来的3.68是指从左向右第二个26子载波资源块对应PAPR值，依次类推；第二行数据3.68、2.76、3.68、2.76……是data位置的值都乘以-1，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右3.68是第一个26子载波资源块对应PAPR值，接 下来的2.76是指从左向右第二个26子载波资源块对应PAPR值，依次类推；第三行数据3.30、4.46、3.30、4.46……是data位置的值都乘以w，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右3.30是第一个26子载波资源块对应PAPR值，接下来的4.46是指从左向右第二个26子载波资源块对应PAPR值，依次类推；第四行数据4.46、3.30、4.46、3.30……是data位置的值都乘以w2，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右4.46是第一个26子载波资源块对应PAPR值，接下来的3.30是指从左向右第二个26子载波资源块对应PAPR值，依次类推；
第二组数字从左向右依次是第二行52子载波资源块对应的PAPR值，其中第一行数据4.68、4.68、4.34、4.48……是指data位置的值都乘以+1，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右，第一个4.68是第一个52子载波资源块对应PAPR值，第二个4.68是指从左向右第二个52子载波资源块对应PAPR值，依次类推；第二行数据4.68、4.68、4.48、4.34……是指data位置的值都乘以-1，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右，第一个4.68是第一个52子载波资源块对应PAPR值，第二个4.68是指从左向右第二个52子载波资源块对应PAPR值，依次类推；第三行数据4.69、4.69、4.35、4.77……是指data位置的值都乘以w，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右，第一个4.69是第一个52子载波资源块对应PAPR值，第二个4.69是指从左向右第二个52子载波资源块对应PAPR值，依次类推；其中第四行数据4.69、4.69、4.77、4.35是指data位置的值都乘以w2，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右，第一个4.69是第一个52子载波资源块对应PAPR值，第二个4.69是指从左向右第二个52子载波资源块对应PAPR值，依次类推；
第三组数据从左向右依次是第三行106子载波资源块对应的PAPR值，其中第一行数据5.42、4.34、4.34、5.42是指data位置的值都乘以+1，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右，5.42是第一个106子载波资源块对应PAPR值，4.34是指从左向右第二个106子载波资源块对应PAPR值，依次类推；第二行数据4.85、5.50、5.50、4.85是指data位置的值都乘以-1，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右，4.85是第一个106子载波资源块对应PAPR值，5.50是指从左向右第二个106子载波资源块对应PAPR值，依次类推；第三行数据4.94、4.63、4.63、4.94是指data位置的值都乘以w，pilot位置的值都乘以+1时HELTF序列 对应的PAPR值，其依次从左向右，4.94是第一个106子载波资源块对应PAPR值，4.63是指从左向右第二个106子载波资源块对应PAPR值，依次类推；第四行数据4.68、5.16、5.16、4.68是指data位置的值都乘以w2，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右，4.68是第一个106子载波资源块对应PAPR值，5.16是指从左向右第二个106子载波资源块对应PAPR值。
第四组数据从左向右依次是第三行242子载波资源块对应的PAPR值，其中第一行数据5.32、5.32是指data位置的值都乘以+1，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右，第一个5.32是第一个242子载波资源块对应PAPR值，第二个5.32是指从左向右第二个242子载波资源块对应PAPR值；第二行数据5.37、5.37是指data位置的值都乘以-1，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右，第一个5.37是第一个242子载波资源块对应PAPR值，第二个5.37是指从左向右第二个242子载波资源块对应PAPR值；第三行数据5.50、5.50是指data位置的值都乘以w，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右，第一个5.50是第一个242子载波资源块对应PAPR值，第二个5.50是指从左向右第二个242子载波资源块对应PAPR值；第四行数据5.39、5.39是指data位置的值都乘以w2，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右，第一个5.39是第一个242子载波资源块对应PAPR值，第二个5.39是指从左向右第二个242子载波资源块对应PAPR值；
第五组数据6.00、4.98、6.15、5.26是第四行242子载波资源块对应的PAPR值，其中第一个6.00是指data位置的值都乘以+1，pilot位置的值都乘以+1时HELTF序列对应的PAPR值；第二个4.98是指data位置的值都乘以-1，pilot位置的值都乘以+1时HELTF序列对应的PAPR值；第三个6.15是指data位置的值都乘以w，pilot位置的值都乘以+1时HELTF序列对应的PAPR值；第一个5.26是指data位置的值都乘以w2，pilot位置的值都乘以+1时HELTF序列对应的PAPR值。
第二种40MHz的2x模式下的HE-LTF序列：
Figure PCTCN2016096973-appb-000073
该HE-LTF序列中包括Ga与Gb序列以及由Ga与Gb序列生成的序列Gc，
Figure PCTCN2016096973-appb-000074
Figure PCTCN2016096973-appb-000075
Gd，位于空余leftover子载波位置上的+1或者-1，
进一步的，可以包含连续的+Ga,
Figure PCTCN2016096973-appb-000076
或者，连续的-Gc,
Figure PCTCN2016096973-appb-000077
或者，连续的+Gc,
Figure PCTCN2016096973-appb-000078
或者，连续的
Figure PCTCN2016096973-appb-000079
-Ga，或者，连续的+Gb,
Figure PCTCN2016096973-appb-000080
或者，连续的
Figure PCTCN2016096973-appb-000081
-Gd，或者，连续的+Gd，或者，连续的
Figure PCTCN2016096973-appb-000083
+Gb。
类似的，可以直接存储为
HELTF2x(-244:2:244)＝
[+1，+1，+1，+1，-1，+1，+1，+1，-1，+1，-1，-1，+1，-1，-1，
-1，+1，+1，-1，-1，-1，+1，-1，-1，+1，-1，+1，+1，-1，+1，
-1，-1，-1，+1，-1，-1，-1，-1，+1，+1，+1，-1，+1，+1，-1，
-1，+1，-1，-1，-1，+1，+1，+1，+1，-1，-1，-1，-1，+1，+1，
+1，-1，+1，+1，-1，-1，+1，-1，+1，-1，+1，+1，+1，-1，+1，
+1，+1，+1，-1，-1，-1，-1，+1，+1，-1，-1，+1，-1，-1，-1，
+1，+1，+1，+1，+1，-1，-1，+1，+1，-1，-1，-1，+1，-1，-1，
+1，-1，+1，-1，-1，-1，+1，-1，-1，-1，+1，-1，+1，+1，-1，
+1，0，0，0，+1，+1，+1，-1，-1，-1，-1，+1，-1，-1，-1，
+1，-1，-1，-1，-1，-1，+1，+1，+1，-1，+1，+1，-1，-1，+1，
+1，-1，+1，-1，+1，+1，-1，+1，+1，+1，-1，-1，+1，+1，-1，
+1，-1，-1，+1，-1，+1，+1，+1，-1，+1，+1，+1，+1，+1，+1，
-1，-1，+1，+1，+1，-1，+1，+1，-1，+1，-1，-1，+1，-1，+1，
+1，-1，+1，+1，+1，-1，-1，+1，+1，+1，-1，+1，+1，-1，+1，
-1，-1，-1，+1，-1，-1，-1，-1，+1，+1，+1，+1，-1，-1，-1，
+1，-1，-1，+1，+1，-1，+1，+1，+1，-1，-1，-1，-1，+1，-1，
-1，-1，+1，-1，+1]
。
本领域技术人员知道，上面的序列用前述表达式简要表达应该为：
Figure PCTCN2016096973-appb-000084
采用上述HE-LTF序列时的PAPR值与图9所示相同，不再赘述。
实例三
80MHz带宽2x符号上有256个子载波，按照不同的资源块大小，如图1c所示，RU大小可以是26、52、106、242、484、996个子载波。
80MHz 996子载波2X符号上的HE-LTF序列有很多种，下面罗列中几种：
第一种80MHz的2X HE-LTF序列：
Figure PCTCN2016096973-appb-000085
该HE-LTF序列中包括Ga与Gb序列以及由Ga与Gb序列生成的序列
Figure PCTCN2016096973-appb-000086
Gc，
Figure PCTCN2016096973-appb-000087
Figure PCTCN2016096973-appb-000088
Gd，
Figure PCTCN2016096973-appb-000089
位于空余leftover子载波位置上的+1或者-1，进一步的，还可以包含连续的-Ga,
Figure PCTCN2016096973-appb-000090
或者，连续的+Gc,
Figure PCTCN2016096973-appb-000091
+Gb，或者，连续的
Figure PCTCN2016096973-appb-000092
-Ga，或者，连续的
Figure PCTCN2016096973-appb-000093
-Gc，或者，连续的-Gc,
Figure PCTCN2016096973-appb-000094
或者，连续的-Ga,
Figure PCTCN2016096973-appb-000095
-Gd，或者，连续的
Figure PCTCN2016096973-appb-000096
-Gc，或者，连续的
Figure PCTCN2016096973-appb-000097
+Ga，连续的+Gd,
Figure PCTCN2016096973-appb-000098
或者，连续的-Gb,
Figure PCTCN2016096973-appb-000099
或者，连续的-Ga,
Figure PCTCN2016096973-appb-000100
-Gd，或者，连续的-Ga,
Figure PCTCN2016096973-appb-000101
-Gd，或者，连续的
Figure PCTCN2016096973-appb-000102
-Gb，或者，连续的Gb,
Figure PCTCN2016096973-appb-000103
或者，连续的+Gd,
Figure PCTCN2016096973-appb-000104
或者，连续的-Gc,
Figure PCTCN2016096973-appb-000105
-Gb，或者，连续的
Figure PCTCN2016096973-appb-000106
+Gd。
当然，也可以存储为：
HELTF2x(-500:2:500)＝
[+1，-1，-1，-1，+1，-1，-1，-1，+1，-1，+1，+1，-1，+1，+1，
+1，-1，-1，+1，+1，+1，-1，+1，+1，-1，+1，-1，-1，+1，-1，
+1，+1，+1，-1，+1，+1，+1，+1，-1，-1，-1，+1，-1，-1，+1，
+1，-1，+1，+1，+1，-1，-1，-1，-1，+1，+1，+1，-1，-1，-1，
-1，+1，-1，-1，-1，+1，-1，+1，+1，+1，-1，-1，+1，+1，+1，
-1，+1，+1，-1，+1，-1，-1，-1，-1，+1，-1，-1，-1，+1，-1，
+1，+1，-1，+1，+1，-1，+1，+1，-1，-1，+1，-1，-1，-1，+1，
+1，+1，+1，-1，+1，-1，-1，-1，+1，-1，-1，-1，-1，+1，+1，
+1，-1，-1，+1，-1，-1，-1，+1，-1，-1，-1，-1，+1，+1，+1，
-1，+1，+1，-1，-1，+1，-1，-1，-1，+1，+1，+1，+1，-1，-1，
-1，-1，+1，-1，-1，-1，+1，-1，+1，+1，-1，+1，+1，+1，-1，
-1，+1，+1，+1，-1，+1，+1，-1，+1，-1，-1，+1，-1，-1，+1，
-1，+1，+1，+1，-1，+1，+1，+1，+1，-1，+1，+1，-1，-1，+1，
-1，-1，-1，+1，+1，+1，+1，-1，+1，-1，-1，-1，+1，-1，-1，
-1，-1，+1，+1，+1，-1，-1，-1，+1，+1，-1，-1，-1，+1，-1，
-1，+1，-1，+1，+1，+1，+1，-1，+1，+1，+1，-1，+1，-1，-1，
+1，-1，+1，+1，-1，+1，+1，-1，+1，0，0，0，+1，+1，-1，
-1，+1，+1，+1，+1，-1，+1，+1，-1，+1，-1，-1，-1，+1，-1，
-1，-1，-1，+1，-1，+1，+1，-1，+1，+1，+1，-1，-1，+1，+1，
+1，-1，-1，-1，+1，+1，+1，+1，-1，+1，+1，+1，-1，+1，-1，
-1，-1，-1，+1，+1，+1，-1，+1，+1，-1，-1，+1，-1，-1，-1，
-1，+1，-1，-1，-1，+1，-1，+1，+1，-1，+1，+1，-1，+1，-1，
-1，+1，-1，-1，-1，+1，+1，-1，-1，-1，+1，-1，-1，+1，-1，
+1，+1，+1，-1，+1，+1，+1，+1，-1，-1，-1，-1，+1，+1，+1，
-1，+1，+1，-1，-1，+1，-1，-1，-1，+1，+1，+1，+1，-1，+1，
+1，+1，-1，+1，+1，+1，+1，+1，-1，-1，-1，-1，+1，-1，-1，
-1，+1，-1，+1，+1，+1，+1，-1，-1，-1，+1，-1，-1，+1，+1，
-1，+1，+1，-1，+1，+1，-1，+1，-1，-1，-1，+1，-1，-1，-1，
-1，+1，-1，+1，+1，-1，+1，+1，+1，-1，-1，+1，+1，+1，-1，
+1，-1，-1，-1，+1，-1，-1，-1，-1，+1，+1，+1，-1，-1，-1，
-1，+1，+1，+1，-1，+1，+1，-1，-1，+1，-1，-1，-1，+1，+1，
+1，+1，-1，+1，+1，+1，-1，+1，-1，-1，+1，-1，+1，+1，-1，
+1，+1，+1，-1，-1，+1，+1，+1，-1，+1，+1，-1，+1，-1，-1，
-1，+1，-1，-1，-1，+1]
本领域技术人员知道，上面的序列用前述表达式简要表达应该为：
Figure PCTCN2016096973-appb-000107
图10给出80MHz带宽下HE-LTF序列的PAPR值，通过该组PAPR值可以看出，当导频子载波和其他子载波引入不同的旋转相位时，PAPR值仍然很低
第一组数字：从左向右依次是26子载波资源块对应的PAPR值，其中第一行数据2.76、3.68、2.76、3.68……是指data位置的值都乘以+1，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右2.76是第一个26子载波资源块对应PAPR值，接下来的3.68是指从左向右第二个26子载波资源块对应PAPR值，依次类推；第二行数据3.68、2.76、3.68、2.76……是data位置的值都乘以+1，pilot位置的值都乘以-1时HELTF序列对应的PAPR值，其依次从左向右3.68是第一个26子载波资源块对应PAPR值，接下来的2.76是指从左向右第二个26子载波资源块对应PAPR值，依次类推；第三行数据3.30、4.46、3.30、4.46……是data位置的值都乘以w，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右3.30是第一个26子载波资源块对应PAPR值，接下来的4.46是指从左向右第二个26子载波资源块对应PAPR值，依次类推；第四行数据4.46、3.30、4.46、3.30……是data位置的值都乘以w2，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右4.46是第一个26子载波资源块对应PAPR值，接下来的3.30是指从左向右第二个26子载波资源块对应PAPR值，依次类推；
第二组数字从左向右依次是第二行52子载波资源块对应的PAPR值，其中第一行数据4.68、4.68、4.69、4.69……是指data位置的值都乘以+1，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右，第一个4.68是第一个52子载波资源块对应PAPR值，第二个4.68是指从左向右第二个52子载波资源块对应PAPR值，依次类推；第二行数据4.68、4.68、4.69、4.69……是指data位置的值都乘以-1，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右，第一个4.68是第一个52子载波资源块对应PAPR值，第二个4.68是指从左向右第二个52子载波资源块对应PAPR值，依次类推；第三行数据4.68、4.68、4.69、4.69……是指data位置的值都乘以w，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右，第一个4.68 是第一个52子载波资源块对应PAPR值，第二个4.68是指从左向右第二个52子载波资源块对应PAPR值，依次类推；其中第四行数据4.68、4.68、4.69、4.69是指data位置的值都乘以w2，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右，第一个4.68是第一个52子载波资源块对应PAPR值，第二个4.68是指从左向右第二个52子载波资源块对应PAPR值，依次类推。
第三组数据从左向右依次是第三行106子载波资源块对应的PAPR值，其中第一行数据5.42、5.33、5.42、5.33……是指指data位置的值都乘以+1，pilot位置的值都乘以+1时HELTF序列时HELTF序列时HELTF序列对应的PAPR值，其依次从左向右，5.42是第一个106子载波资源块对应PAPR值，5.33是指从左向右第二个106子载波资源块对应PAPR值，依次类推；第二行数据4.85、5.41、4.85、5.41……是指data位置的值都乘以-1，pilot位置的值都乘以+1时HELTF序列时HELTF序列对应的PAPR值，其依次从左向右，4.85是第一个106子载波资源块对应PAPR值，5.50是指从左向右第二个106子载波资源块对应PAPR值，依次类推；第三行数据4.95、5.18、4.95、5.18……是指data位置的值都乘以w，pilot位置的值都乘以+1时HELTF序列时HELTF序列对应的PAPR值，其依次从左向右4.95是第一个106子载波资源块对应PAPR值，5.18是指从左向右第二个106子载波资源块对应PAPR值，依次类推；第四行数据4.68、4.97、4.68、4.97……是指data位置的值都乘以w2，pilot位置的值都乘以+1时HELTF序列时HELTF序列对应的PAPR值，其依次从左向右，4.68是第一个106子载波资源块对应PAPR值，4.97是指从左向右第二个106子载波资源块对应PAPR值。
第四组数据从左向右依次是第四行242子载波资源块对应的PAPR值，其中第一行数据5.29、5.29是指data位置的值都乘以+1，pilot位置的值都乘以+1时HELTF序列时HELTF序列对应的PAPR值，其依次从左向右，第一个5.29是第一个242子载波资源块对应PAPR值，第二个5.29是指从左向右第二个242子载波资源块对应PAPR值；第二行数据5.58、5.58是指data位置的值都乘以-1，pilot位置的值都乘以+1时HELTF序列时HELTF序列对应的PAPR值，其依次从左向右，第一个5.58是第一个242子载波资源块对应PAPR值，第二个5.58是指从左向右第二个242子载波资源块对应PAPR值；第三行数据5.40、5.40是指data位置的值都乘以w，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右，第一个5.40是第一个242子载波资源块对应PAPR值，第二个5.40是指从左向右第二个242子载波资源块对应PAPR值；第四行数据5.46、 5.46是指data位置的值都乘以w2，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右，第一个5.46是第一个242子载波资源块对应PAPR值，第二个5.46是指从左向右第二个242子载波资源块对应PAPR值；
第五组数据从左向右依次是第五行484子载波资源块对应的PAPR值，其中第一行数据6.27、6.13是指data位置的值都乘以+1，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右，6.27是第一个484子载波资源块对应PAPR值，6.13是指从左向右第二个484子载波资源块对应PAPR值；第二行数据6.11、6.40是指data位置的值都乘以-1，pilot位置的值都乘以+1时HELTF序列时HELTF序列对应的PAPR值，其依次从左向右，6.11是第一个242子载波资源块对应PAPR值，6.40是指从左向右第二个484子载波资源块对应PAPR值；第三行数据6.24、6.34是指data位置的值都乘以w，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右，6.24是第一个484子载波资源块对应PAPR值，6.34是指从左向右第二个484子载波资源块对应PAPR值；第四行数据6.29、6.25是指data位置的值都乘以w2，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右，6.29是第一个484子载波资源块对应PAPR值，6.25是指从左向右第二个484子载波资源块对应PAPR值；
第六组数据6.01、5.68、6.08、5.92是第六行996子载波资源块对应的PAPR值，其中第一个6.08是指data位置的值都乘以+1，pilot位置的值都乘以+1时HELTF序列对应的PAPR值；第二个5.68是指data位置的值都乘以-1，pilot位置的值都乘以+1时HELTF序列对应的PAPR值；第三个6.08是指data位置的值都乘以w，pilot位置的值都乘以+1时HELTF序列对应的PAPR值；第四个5.92是指data位置的值都乘以w2，pilot位置的值都乘以+1时HELTF序列对应的PAPR值。
第二种80MHz的2X HE-LTF序列：
Figure PCTCN2016096973-appb-000108
该HE-LTF序列中包括Ga与Gb序列以及由Ga与Gb序列生成的序列
Figure PCTCN2016096973-appb-000109
Gc，
Figure PCTCN2016096973-appb-000110
Figure PCTCN2016096973-appb-000111
Gd，
Figure PCTCN2016096973-appb-000112
位于，位于空余leftover子载波位置上的+1或者-1，进一步的，还可以包含连续的+Gc,
Figure PCTCN2016096973-appb-000113
或者，连续的+Ga,
Figure PCTCN2016096973-appb-000114
+Gd，或者，连续的
Figure PCTCN2016096973-appb-000115
+Gc，或者，连续的
Figure PCTCN2016096973-appb-000116
-Ga，或者，连续的-Ga,
Figure PCTCN2016096973-appb-000117
或者，连续的+Gc,
Figure PCTCN2016096973-appb-000118
+Gb，或者，连续的
Figure PCTCN2016096973-appb-000119
-Ga，或者，连续的
Figure PCTCN2016096973-appb-000120
-Gc，连续的-Gb,
Figure PCTCN2016096973-appb-000121
或者，连续的-Gd,
Figure PCTCN2016096973-appb-000122
或者，连续的+Gc,
Figure PCTCN2016096973-appb-000123
+Gb，或者，连续的
Figure PCTCN2016096973-appb-000124
-Gd，或者，连续的+Gd,
Figure PCTCN2016096973-appb-000125
或者，连续的-Gb,
Figure PCTCN2016096973-appb-000126
或者，连续的-Ga,
Figure PCTCN2016096973-appb-000127
-Gd，或者，连续的
Figure PCTCN2016096973-appb-000128
-Gb。
也可以直接存储为：
HELTF2x(-500:2:500)＝
[+1,+1,-1,+1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,+1,
-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,-1,-1,+1,+1,+1,
+1,-1,+1,+1,+1,-1,+1,-1,-1,+1,-1,-1,-1,+1,+1,
-1,-1,-1,+1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,
-1,-1,-1,+1,-1,-1,-1,-1,+1,-1,-1,+1,+1,-1,+1,
+1,+1,-1,-1,-1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,
+1,-1,-1,-1,+1,+1,+1,-1,-1,+1,+1,+1,-1,+1,+1,
-1,+1,-1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,+1,-1,
+1,+1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,
+1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,+1,-1,-1,+1,
-1,+1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,+1,-1,-1,
+1,+1,-1,+1,+1,+1,-1,-1,-1,-1,+1,+1,+1,-1,-1,
-1,-1,+1,-1,-1,-1,+1,-1,+1,+1,+1,-1,-1,+1,+1,
+1,-1,+1,+1,-1,+1,-1,-1,-1,-1,+1,-1,-1,-1,+1,
-1,+1,+1,-1,+1,+1,-1,+1,+1,-1,-1,+1,-1,-1,-1,
+1,+1,+1,+1,-1,+1,-1,-1,-1,+1,-1,-1,-1,-1,+1,
+1,+1,+1,-1,-1,-1,+1,+1,+1,0,0,0,+1,-1,-1,
+1,+1,-1,+1,-1,-1,-1,+1,+1,+1,+1,-1,+1,+1,+1,
-1,+1,-1,-1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,+1,
-1,-1,+1,-1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,+1,
-1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,-1,-1,+1,-1,
+1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,+1,+1,+1,+1,
-1,-1,-1,+1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,-1,
-1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,-1,-1,+1,-1,
-1,-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,-1,+1,+1,+1,
-1,+1,+1,+1,-1,+1,-1,+1,+1,-1,+1,-1,-1,-1,+1,
-1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,+1,-1,-1,+1,
+1,+1,-1,-1,-1,+1,+1,+1,+1,-1,+1,+1,+1,-1,+1,
-1,-1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,+1,-1,-1,
-1,-1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,
-1,-1,+1,-1,-1,-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,
-1,+1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,-1,+1,+1,
+1,-1,+1,+1,-1,-1,+1,-1,-1,-1,+1,+1,+1,+1,-1,
+1,+1,+1,-1,+1,+1]
采用第二种HELTF序列后，其对应的PAPR值与第一种HELTF序列的PAPR值(图10所示)相同。
第三种80MHz的2X HE-LTF序列：
Figure PCTCN2016096973-appb-000129
该HE-LTF序列中包括Ga与Gb序列以及由Ga与Gb序列生成的序列
Figure PCTCN2016096973-appb-000130
Gc，
Figure PCTCN2016096973-appb-000131
Figure PCTCN2016096973-appb-000132
Gd，
Figure PCTCN2016096973-appb-000133
位于空余leftover子载波位置上的+1或者-1，进一步的，还可以包含连 续的-Ga,
Figure PCTCN2016096973-appb-000134
或者，连续的+Gc,
Figure PCTCN2016096973-appb-000135
+Gb，或者，连续的
Figure PCTCN2016096973-appb-000136
-Ga，或者，连续的
Figure PCTCN2016096973-appb-000137
-Gc，或者，连续的+Gc,
Figure PCTCN2016096973-appb-000138
或者，连续的+Ga,
Figure PCTCN2016096973-appb-000139
+Gd，或者，连续的
Figure PCTCN2016096973-appb-000140
+Gc，或者，连续的
Figure PCTCN2016096973-appb-000141
-Ga，连续的-Gd,
Figure PCTCN2016096973-appb-000142
或者，连续的+Gb,
Figure PCTCN2016096973-appb-000143
或者，连续的+Ga,
Figure PCTCN2016096973-appb-000144
或者，连续的+Ga,
Figure PCTCN2016096973-appb-000145
+Gd，或者，连续的
Figure PCTCN2016096973-appb-000146
+Gb，或者，连续的+Gb,
Figure PCTCN2016096973-appb-000147
或者，连续的+Gd,
Figure PCTCN2016096973-appb-000148
或者，连续的-Gc,
Figure PCTCN2016096973-appb-000149
-Gb，或者，连续的
Figure PCTCN2016096973-appb-000150
+Gd。
也可以直接存储下述序列：
HELTF2x(-500:2:500)＝
[+1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,
+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,+1,-1,-1,+1,-1,
+1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,+1,-1,-1,+1,
+1,-1,+1,+1,+1,-1,-1,-1,-1,+1,+1,+1,-1,-1,-1,
-1,+1,-1,-1,-1,+1,-1,+1,+1,+1,-1,-1,+1,+1,+1,
-1,+1,+1,-1,+1,-1,-1,-1,-1,+1,-1,-1,-1,+1,-1,
+1,+1,-1,+1,+1,-1,+1,+1,-1,-1,+1,-1,-1,-1,+1,
+1,+1,+1,-1,+1,-1,-1,-1,+1,-1,-1,-1,-1,+1,+1,
+1,+1,+1,-1,+1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,
+1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,-1,-1,+1,+1,
+1,+1,-1,+1,+1,+1,-1,+1,-1,-1,+1,-1,-1,-1,+1,
+1,-1,-1,-1,+1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,
+1,-1,-1,-1,+1,-1,-1,-1,-1,+1,-1,-1,+1,+1,-1,
+1,+1,+1,-1,-1,-1,-1,+1,-1,+1,+1,+1,-1,+1,+1,
+1,+1,-1,-1,-1,+1,+1,+1,-1,-1,+1,+1,+1,-1,+1,
+1,-1,+1,-1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,+1,
-1,+1,+1,+1,+1,-1,-1,+1,+1,0,0,0,+1,-1,+1,
+1,-1,+1,+1,-1,+1,-1,-1,+1,-1,+1,+1,+1,-1,+1,
+1,+1,+1,-1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,-1,
-1,+1,+1,+1,-1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,
+1,+1,+1,-1,-1,-1,+1,-1,-1,+1,+1,-1,+1,+1,+1,
+1,-1,+1,+1,+1,-1,+1,-1,-1,+1,-1,-1,+1,-1,+1,
+1,-1,+1,+1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,+1,
-1,-1,-1,+1,-1,-1,-1,-1,+1,+1,+1,+1,-1,-1,-1,
+1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,-1,-1,+1,-1,
-1,-1,+1,-1,-1,+1,+1,+1,-1,-1,-1,-1,+1,-1,-1,
-1,+1,-1,+1,+1,+1,+1,-1,-1,-1,+1,-1,-1,+1,+1,
-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,-1,+1,-1,-1,-1,
-1,+1,-1,+1,+1,-1,+1,+1,+1,-1,-1,+1,+1,+1,-1,
+1,-1,-1,-1,+1,-1,-1,-1,-1,+1,+1,+1,-1,-1,-1,
-1,+1,+1,+1,-1,+1,+1,-1,-1,+1,-1,-1,-1,+1,+1,
+1,+1,-1,+1,+1,+1,-1,+1,-1,-1,+1,-1,+1,+1,-1,
+1,+1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,+1,-1,-1,
-1,+1,-1,-1,-1,+1]。
图11给出80MHz带宽下HE-LTF序列的PAPR值，通过该组PAPR值可以看出，当导频子载波和其他子载波引入不同的旋转相位时，PAPR值仍然很低。
第一组数字：从左向右依次是26子载波资源块对应的PAPR值，其中第一行数据2.76、3.68、2.76、3.68……是指data位置的值都乘以+1，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右2.76是第一个26子载波资源块对应PAPR值，接下来的3.68是指从左向右第二个26子载波资源块对应PAPR值，依次类推；第二行数据3.68、2.76、3.68、2.76……是data位置的值都乘以+1，pilot位置的值都乘以-1时HELTF序列对应的PAPR值，其依次从左向右3.68是第一个26子载波资源块对应PAPR值，接下来的2.76是指从左向右第二个26子载波资源块对应PAPR值，依次类推；第三行数据3.30、4.46、3.30、4.46……是data位置的值都乘以w，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右3.30是第一个26子载波资源块对应PAPR值，接下来的4.46是指从左向右第二个26子载波资源块对应PAPR值，依次类推；第四行数据4.46、3.30、4.46、3.30……是data位置的值都乘以w2，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右4.46是第一个26子载波资源块对应PAPR值，接下来的3.30是指从左向右第二个26子载波资源块对应PAPR值，依次类推；
第二组数字：从左向右依次是第二行52子载波资源块对应的PAPR值，其中第一行数据4.68、4.68、4.69、4.69……是指data位置的值都乘以+1，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右，第一个4.68是第一个52子载波资源块对应PAPR值，第二个4.68是指从左向右第二个52子载波资源块对应PAPR值，依次类推；第二行数据4.68、4.68、4.69、4.69……是指data位置的值都乘以-1，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右，第一个4.68是第一个52子载波资源块对应PAPR值，第二个4.68是指从左向右第二个52子载波资源块对应PAPR值，依次类推；第三行数据4.68、4.68、4.69、4.69……是指data位置的值都乘以w，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右，第一个4.68是第一个52子载波资源块对应PAPR值，第二个4.68是指从左向右第二个52子载波资源块对应PAPR值，依次类推；其中第四行数据4.68、4.68、4.69、4.69是指data位置的值都乘以w2，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右，第一个4.68是第一个52子载波资源块对应PAPR值，第二个4.68是指从左向右第二个52子载波资源块对应PAPR值，依次类推；
第三组数据：从左向右依次是第三行106子载波资源块对应的PAPR值，其中第一行数据5.42、5.33、5.42、5.33……是指指data位置的值都乘以+1，pilot位置的值都乘以+1时HELTF序列时HELTF序列时HELTF序列对应的PAPR值，其依次从左向右，5.42是第一个106子载波资源块对应PAPR值，5.33是指从左向右第二个106子载波资源块对应PAPR值，依次类推；第二行数据4.85、5.41、4.85、5.41……是指data位置的值都乘以-1，pilot位置的值都乘以+1时HELTF序列时HELTF序列对应的PAPR值，其依次从左向右，4.85是第一个106子载波资源块对应PAPR值，5.50是指从左向右第二个106子载波资源块对应PAPR值，依次类推；第三行数据4.95、5.18、4.95、5.18……是指data位置的值都乘以w，pilot位置的值都乘以+1时HELTF序列时HELTF序列对应的PAPR值，其依次从左向右4.95是第一个106子载波资源块对应PAPR值，5.18是指从左向右第二个106子载波资源块对应PAPR值，依次类推；第四行数据4.68、4.97、4.68、4.97……是指data位置的值都乘以w2，pilot位置的值都乘以+1时HELTF序列时HELTF序列对应的PAPR值，其依次从左向右，4.68是第一个106子载波资源块对应PAPR值，4.97是指从左向右第二个106子载波资源块对应PAPR值。
第四组数据：
从左向右依次是第四行242子载波资源块对应的PAPR值，其中第一行数据5.29、5.29是指data位置的值都乘以+1，pilot位置的值都乘以+1时HELTF序列时HELTF序列对应的PAPR值，其依次从左向右，第一个5.29是第一个242子载波资源块对应PAPR值，第二个5.29是指从左向右第二个242子载波资源块对应PAPR值；第二行数据5.58、5.58是指data位置的值都乘以-1，pilot位置的值都乘以+1时HELTF序列时HELTF序列对应的PAPR值，其依次从左向右，第一个5.58是第一个242子载波资源块对应PAPR值，第二个5.58是指从左向右第二个242子载波资源块对应PAPR值；第三行数据5.40、5.40是指data位置的值都乘以w，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右，第一个5.40是第一个242子载波资源块对应PAPR值，第二个5.40是指从左向右第二个242子载波资源块对应PAPR值；第四行数据5.46、5.46是指data位置的值都乘以w2，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右，第一个5.46是第一个242子载波资源块对应PAPR值，第二个5.46是指从左向右第二个242子载波资源块对应PAPR值；
第五组数据从左向右依次是第五行484子载波资源块对应的PAPR值，其中第一行数据6.13、6.27是指data位置的值都乘以+1，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右，6.13是第一个484子载波资源块对应PAPR值，6.27是指从左向右第二个484子载波资源块对应PAPR值；第二行数据6.40、6.11是指data位置的值都乘以-1，pilot位置的值都乘以+1时HELTF序列时HELTF序列对应的PAPR值，其依次从左向右，6.40是第一个242子载波资源块对应PAPR值，6.11是指从左向右第二个484子载波资源块对应PAPR值；第三行数据6.34、6.24是指data位置的值都乘以w，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右，6.34是第一个484子载波资源块对应PAPR值，6.24是指从左向右第二个484子载波资源块对应PAPR值；第四行数据6.25、6.29是指data位置的值都乘以w2，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右，6.25是第一个484子载波资源块对应PAPR值，6.29是指从左向右第二个484子载波资源块对应PAPR值。
第六组数据6.01、5.68、6.08、5.92是第六行996子载波资源块对应的PAPR值，其中第一个6.08是指data位置的值都乘以+1，pilot位置的值都乘以+1时HELTF序列对应的PAPR值；第二个5.68是指data位置的值都乘以-1，pilot位置的值都乘以+1时HELTF序列对应的PAPR值；第三个6.08是指data位置的值都乘以w，pilot位置的值都 乘以+1时HELTF序列对应的PAPR值；第四个5.92是指data位置的值都乘以w2，pilot位置的值都乘以+1时HELTF序列对应的PAPR值。
第四种80MHz 2x模式下HE-LTF序列：
Figure PCTCN2016096973-appb-000151
该HE-LTF序列中包括Ga与Gb序列以及由Ga与Gb序列生成的序列
Figure PCTCN2016096973-appb-000152
Gc，
Figure PCTCN2016096973-appb-000153
Figure PCTCN2016096973-appb-000154
Gd，
Figure PCTCN2016096973-appb-000155
位于空余leftover子载波位置上的+1或者-1，进一步的，还可以包括连续的+Gc,
Figure PCTCN2016096973-appb-000156
或者，连续的+Ga,
Figure PCTCN2016096973-appb-000157
+Gd，或者，连续的
Figure PCTCN2016096973-appb-000158
+Gc，或者，连续的
Figure PCTCN2016096973-appb-000159
-Ga或者，连续的+Ga
Figure PCTCN2016096973-appb-000160
或者，连续的-Gc,
Figure PCTCN2016096973-appb-000161
-Gb，或者，连续的
Figure PCTCN2016096973-appb-000162
+Ga，或者，连续的
Figure PCTCN2016096973-appb-000163
+Gc，或者，连续的+Gb,
Figure PCTCN2016096973-appb-000164
或者，连续的+Gd,
Figure PCTCN2016096973-appb-000165
或者，连续的-Gc,
Figure PCTCN2016096973-appb-000166
-Gb，或者，连续的
Figure PCTCN2016096973-appb-000167
+Gd，或者，连续的+Gd,
Figure PCTCN2016096973-appb-000168
或者，连续的-Gb,
Figure PCTCN2016096973-appb-000169
或者，连续的-Ga,
Figure PCTCN2016096973-appb-000170
-Gd，或者，连续的
Figure PCTCN2016096973-appb-000171
-Gb。
HELTF2x(-500:2:500)＝
[+1,+1,-1,+1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,+1,
-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,-1,-1,+1,+1,+1,
+1,-1,+1,+1,+1,-1,+1,-1,-1,+1,-1,-1,-1,+1,+1,
-1,-1,-1,+1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,
-1,-1,-1,+1,-1,-1,-1,-1,+1,-1,-1,+1,+1,-1,+1,
+1,+1,-1,-1,-1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,
+1,-1,-1,-1,+1,+1,+1,-1,-1,+1,+1,+1,-1,+1,+1,
-1,+1,-1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,+1,-1,
+1,-1,+1,+1,+1,-1,+1,+1,+1,-1,+1,-1,-1,+1,-1,
-1,-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,-1,+1,+1,-1,
+1,-1,-1,-1,+1,-1,-1,-1,-1,+1,+1,+1,-1,+1,+1,
-1,-1,+1,-1,-1,-1,+1,+1,+1,+1,-1,-1,-1,+1,+1,
+1,+1,-1,+1,+1,+1,-1,+1,-1,-1,-1,+1,+1,-1,-1,
-1,+1,-1,-1,+1,-1,+1,+1,+1,+1,-1,+1,+1,+1,-1,
+1,-1,-1,+1,-1,-1,+1,-1,-1,+1,+1,-1,+1,+1,+1,
-1,-1,-1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,+1,-1,
-1,-1,+1,-1,+1,+1,-1,-1,+1,0,0,0,+1,+1,+1,
-1,-1,-1,+1,+1,+1,+1,-1,-1,-1,-1,+1,-1,-1,-1,
+1,-1,+1,+1,+1,+1,-1,-1,-1,+1,-1,-1,+1,+1,-1,
+1,+1,-1,+1,+1,-1,+1,-1,-1,-1,+1,-1,-1,-1,-1,
+1,-1,+1,+1,-1,+1,+1,+1,-1,-1,+1,+1,+1,-1,+1,
-1,-1,-1,+1,-1,-1,-1,-1,+1,+1,+1,-1,-1,-1,-1,
+1,+1,+1,-1,+1,+1,-1,-1,+1,-1,-1,-1,+1,+1,+1,
+1,-1,+1,+1,+1,-1,+1,-1,-1,+1,-1,+1,+1,-1,+1,
+1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,+1,-1,-1,-1,
+1,-1,-1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,-1,+1,
-1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,+1,-1,-1,+1,
+1,+1,-1,-1,-1,+1,+1,+1,+1,-1,+1,+1,+1,-1,+1,
-1,-1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,+1,-1,-1,
-1,-1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,
-1,-1,+1,-1,-1,-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,
-1,+1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,-1,+1,+1,
+1,-1,+1,+1,-1,-1,+1,-1,-1,-1,+1,+1,+1,+1,-1,
+1,+1,+1,-1,+1,+1]。
采用第四种HELTF序列后，其对应的PAPR值与第三种HELTF序列的PAPR值相同，详见图11，通过该组PAPR值可以看出，当导频子载波和其他子载波引入不同的旋转相位时，PAPR值仍然很低。
实例四
4x模式下20MHz带宽4x符号上有256个子载波，按照不同的资源块大小，图1a所示RU大小可以是26、52、106、242个子载波。
针对20MHz 242子载波4X模式上的HE-LTF序列有很多种，下面仅罗列出其中的几种：
第一种20MHz 242子载波4X模式的HE-LTF序列
Figure PCTCN2016096973-appb-000172
其中Ge＝{1,-1,1,-1,1,1,1,1,-1,-1,-1,1,1,1,1,1,1,1,1,-1,1,-1,-1,1,1,-1}
该HE-LTF序列中包括Ge序列以及Ga与Gb序列生成的衍生序列Gc、
Figure PCTCN2016096973-appb-000173
Gd、
Figure PCTCN2016096973-appb-000174
位于空余leftover子载波位置上的+1或者-1，进一步的，还可以包含连续的-Gc,
Figure PCTCN2016096973-appb-000175
或者，连续的+Gd,
Figure PCTCN2016096973-appb-000176
或者，连续的-Gc,
Figure PCTCN2016096973-appb-000177
连续的+Gd,
Figure PCTCN2016096973-appb-000178
也可以直接存储为：
HELTF4x(-122:122)＝
[+1,-1,+1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,-1,-1,
+1,-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,-1,-1,+1,-1,
+1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,
-1,+1,+1,+1,-1,-1,-1,-1,+1,+1,-1,+1,-1,-1,+1,
+1,-1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,+1,-1,
-1,-1,-1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,
-1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,+1,+1,+1,+1,
+1,+1,-1,+1,-1,+1,+1,+1,+1,-1,-1,-1,+1,+1,+1,
-1,0,0,0,+1,-1,+1,+1,+1,+1,+1,+1,-1,+1,-1,
-1,+1,+1,-1,-1,+1,-1,+1,-1,+1,+1,+1,-1,+1,+1,
+1,-1,-1,+1,-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,-1,
+1,-1,+1,-1,+1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,
+1,+1,+1,+1,-1,-1,-1,+1,+1,+1,+1,+1,+1,-1,+1,
-1,-1,+1,+1,-1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,
-1,+1,-1,-1,-1,-1,-1,-1,+1,-1,+1,-1,-1,+1,-1,
-1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,
-1,-1,-1,-1,+1]。
图12给出20MHz带宽下HE-LTF序列的PAPR值，通过该组PAPR值可以看出，当导频子载波和其他子载波引入不同的旋转相位时，PAPR值仍然很低。
第一组数字：从左向右依次是26子载波资源块对应的PAPR值，其中第一行数据3.51、3.78、3.51、3.78……是指data位置的值都乘以+1，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右3.51是第一个26子载波资源块对应PAPR值，接下来的3.78是指从左向右第二个26子载波资源块对应PAPR值，依次类推；第二行数据3.78、3.51、3.78、3.51……是指data位置的值都乘以-1，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右3.78是第一个26子载波资源块对应PAPR值，接下来的3.51是指从左向右第二个26子载波资源块对应PAPR值，依次类推；第三行数据3.28、3.48、3.28、3.48……是指data位置的值都乘以w，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右3.28是第一个26子载波资源块对应PAPR值，接下来的3.48是指从左向右第二个26子载波资源块对应PAPR值，依次类推；第四行数据3.48、3.28、3.48、3.28……是指data位置的值都乘以w2，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右3.48是第一个26子载波资源块对应PAPR值，接下来的3.28是指从左向右第二个26子载波资源块对应PAPR值，依次类推；
第二组数字：从左向右依次是第二行52子载波资源块对应的PAPR值，其中第一行数据4.42、4.59、4.63、4.42是指data位置的值都乘以+1，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右，第一个4.42是第一个52子载波资源块对应PAPR值，第二个4.59是指从左向右第二个52子载波资源块对应PAPR值，依次类推；第二行数据4.42、4.63、4.59、4.42是指data位置的值都乘以-1，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右，第一个4.42是第一个52子载波资源块对应PAPR值，第二个4.63是指从左向右第二个52子载波资源块对应PAPR值，依次类推；第三行数据4.44、4.86、4.97、4.42是指data位置的值都乘以w，pilot位 置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右，第一个4.44是第一个52子载波资源块对应PAPR值，第二个4.86是指从左向右第二个52子载波资源块对应PAPR值，依次类推；其中第四行数据4.42、4.97、4.86、4.44是指指data位置的值都乘以w2，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右，第一个4.42是第一个52子载波资源块对应PAPR值，第二个4.97是指从左向右第二个52子载波资源块对应PAPR值，依次类推；
第三组数据：从左向右依次是第三行106子载波资源块对应的PAPR值，其中第一行数据4.65、4.90是指data位置的值都乘以+1，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右，4.65是第一个106子载波资源块对应PAPR值，4.90是指从左向右第二个106子载波资源块对应PAPR值；第二行数据4.69、5.01是指data位置的值都乘以-1，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右，4.69是第一个106子载波资源块对应PAPR值，5.01是指从左向右第二个106子载波资源块对应PAPR值；第三行数据4.90、4.95是指data位置的值都乘以w，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右，4.90是第一个106子载波资源块对应PAPR值，4.95是指从左向右第二个106子载波资源块对应PAPR值；第四行数据4.92、4.87是指data位置的值都乘以w2，pilot位置的值都乘以+1时HELTF序列对应的PAPR值，其依次从左向右，4.92是第一个106子载波资源块对应PAPR值，4.87是指从左向右第二个106子载波资源块对应PAPR值。
第四组数据5.26、5.30、5.29、5.56是第四行242子载波资源块对应的PAPR值，其中第一个5.26是指data位置的值都乘以+1，pilot位置的值都乘以+1时HELTF序列对应的PAPR值；第二个5.30是指data位置的值都乘以-1，pilot位置的值都乘以+1时HELTF序列对应的PAPR值；第三个5.29是指data位置的值都乘以w，pilot位置的值都乘以+1时HELTF序列对应的PAPR值；第一个5.56是指data位置的值都乘以w2，pilot位置的值都乘以+1时HELTF序列对应的PAPR值。
第二种20MHz 242子载波4X模式的HE-LTF序列：
Figure PCTCN2016096973-appb-000179
其中Ge＝{1,1,1,1,1,-1,1,-1,-1,1,-1,-1,1,1,-1,1,-1,1,-1,-1,-1,-1,1,1,-1,-1}
该HE-LTF序列中包括Ge序列、Ga与Gb序列以及Ga与Gb序列生成的衍生序列
Figure PCTCN2016096973-appb-000180
Figure PCTCN2016096973-appb-000181
位于空余leftover子载波位置上的+1或者-1，进一步的，该HE-LTF序列还可以包含：连续的+Ga,
Figure PCTCN2016096973-appb-000182
或者，连续的+Gb,
Figure PCTCN2016096973-appb-000183
或者，连续的+Ga,
Figure PCTCN2016096973-appb-000184
或者，连续的+Gb,
Figure PCTCN2016096973-appb-000185
或者+Ge(1:13)，+Ge(14:26)。
也可以直接存储为：
HELTF4x(-122:122)＝
[+1,+1,+1,+1,+1,+1,+1,-1,+1,+1,+1,-1,+1,+1,-1,
-1,-1,+1,-1,+1,-1,-1,+1,+1,-1,+1,-1,+1,+1,+1,
+1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,
+1,+1,-1,+1,+1,-1,+1,-1,-1,+1,+1,+1,+1,-1,-1,
+1,+1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,-1,-1,
+1,-1,+1,-1,+1,-1,-1,-1,-1,+1,+1,+1,-1,-1,-1,
-1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,+1,-1,+1,
-1,+1,+1,+1,+1,+1,-1,+1,-1,-1,+1,-1,-1,+1,-1,
-1,0,0,0,+1,+1,+1,-1,+1,-1,+1,-1,-1,-1,-1,
+1,+1,-1,-1,+1,+1,+1,+1,+1,+1,-1,+1,+1,+1,-1,
+1,+1,-1,-1,-1,+1,-1,+1,-1,-1,+1,+1,-1,+1,-1,
-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,+1,
+1,-1,+1,-1,-1,+1,-1,-1,+1,-1,+1,-1,+1,+1,+1,
+1,-1,-1,+1,+1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,
-1,-1,-1,+1,-1,+1,-1,+1,+1,+1,+1,+1,-1,-1,-1,
+1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,+1,
-1,+1,-1,+1,+1]。
本领域技术人员知道，上述序列如果用前述简要表达式表达应该为：
Figure PCTCN2016096973-appb-000186
采用第二种HELTF序列后，其对应的PAPR值与第一种HELTF序列的PAPR值相同，参见图12，通过该组PAPR值可以看出，当导频子载波和其他子载波引入不同的旋转相位时，PAPR值仍然很低。
实例五
4x模式下40MHz带宽4x符号上有512个子载波，按照不同的资源块大小，如图1b所示RU大小可以是26、52、106、242、484个子载波。
针对40MHz 484子载波4X模式上的HE-LTF序列有很多种，下面仅罗列出其中的几种：
第一种40MHz4x模式下的HELTF序列
Figure PCTCN2016096973-appb-000187
该HE-LTF序列中包括Ga与Gb序列以及由Ga与Gb序列生成的序列Gc，
Figure PCTCN2016096973-appb-000188
Figure PCTCN2016096973-appb-000189
Gd，位于空余leftover子载波位置上的+1或者-1，
进一步的，还可以包含连续的-Ga,
Figure PCTCN2016096973-appb-000190
或者，连续的-Gc,
Figure PCTCN2016096973-appb-000191
或者，连续的+Ga,
Figure PCTCN2016096973-appb-000192
或者，连续的
Figure PCTCN2016096973-appb-000193
+Gb，或者，连续的
Figure PCTCN2016096973-appb-000194
+Gd，或者，连续的
Figure PCTCN2016096973-appb-000195
-Gb。
也可以直接存储为：
HELTF4x(-244:244)＝
[+1,-1,-1,-1,-1,-1,-1,+1,-1,-1,-1,+1,-1,-1,+1,
+1,+1,-1,+1,-1,+1,+1,-1,-1,+1,-1,+1,+1,+1,+1,
+1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,
+1,+1,-1,+1,+1,-1,+1,-1,+1,-1,-1,+1,-1,+1,-1,
+1,+1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,-1,-1,
+1,+1,-1,-1,-1,-1,-1,+1,-1,+1,-1,-1,+1,+1,-1,
+1,+1,+1,-1,-1,+1,-1,-1,-1,-1,+1,+1,+1,-1,-1,
-1,-1,+1,+1,-1,+1,-1,-1,+1,+1,-1,+1,-1,+1,+1,
+1,-1,-1,+1,-1,-1,-1,+1,-1,-1,-1,-1,-1,-1,+1,
+1,+1,+1,+1,+1,+1,-1,+1,+1,+1,-1,+1,+1,-1,-1,
-1,+1,-1,+1,-1,-1,+1,+1,-1,+1,-1,-1,-1,-1,-1,
-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,-1,
-1,+1,-1,-1,+1,-1,+1,-1,+1,-1,+1,-1,+1,-1,+1,
+1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,-1,-1,+1,
+1,-1,-1,-1,-1,-1,+1,-1,+1,-1,-1,+1,+1,-1,+1,
+1,+1,-1,-1,+1,-1,-1,-1,-1,+1,+1,+1,-1,-1,-1,
-1,+1,0,0,0,0,0,-1,+1,+1,+1,+1,-1,-1,-1,
+1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,+1,
-1,+1,-1,+1,+1,+1,+1,+1,-1,-1,+1,+1,+1,+1,+1,
-1,+1,+1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,-1,+1,
-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,-1,
+1,+1,-1,+1,+1,+1,-1,-1,+1,+1,+1,+1,+1,+1,-1,
+1,-1,-1,+1,+1,-1,+1,-1,+1,+1,+1,-1,-1,+1,-1,
-1,-1,+1,-1,-1,-1,-1,-1,-1,+1,+1,-1,+1,-1,+1,
+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,+1,-1,
-1,-1,+1,+1,+1,+1,+1,-1,-1,-1,-1,+1,+1,+1,-1,
-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,+1,
-1,+1,-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,-1,-1,+1,
-1,-1,+1,+1,+1,-1,+1,+1,+1,-1,+1,-1,+1,-1,+1,
-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,-1,+1,
+1,-1,+1,+1,+1,-1,-1,+1,+1,+1,+1,+1,+1,-1,+1,
-1,-1,+1,+1,-1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,
-1,+1,-1,-1,-1,-1,-1,-1,+1]。
本领域技术人员知道，上述序列如果用前述简要表达式表达应该为：
Figure PCTCN2016096973-appb-000196
图13出40MHz带宽下HE-LTF序列的PAPR值，通过该组PAPR值可以看出，当导频子载波和其他子载波引入不同的旋转相位时，PAPR值仍然很低。表中数据读法可以参考前面的实施方式，此处不再赘述。
第二种40MHz4x模式下的HELTF序列：
Figure PCTCN2016096973-appb-000197
该HE-LTF序列中包括Ga与Gb序列以及由Ga与Gb序列生成的序列Gc，
Figure PCTCN2016096973-appb-000198
Figure PCTCN2016096973-appb-000199
Gd，位于空余leftover子载波位置上的+1或者-1，
进一步的，还可以包含连续的Gc,
Figure PCTCN2016096973-appb-000200
或者，连续的+Ga,
Figure PCTCN2016096973-appb-000201
或者，连续的，-Gc,
Figure PCTCN2016096973-appb-000202
或者，连续的+Gd，或者，连续的
Figure PCTCN2016096973-appb-000204
+Gb，或者，连续的
Figure PCTCN2016096973-appb-000205
+Gb。
也可以直接存储为：
HELTF4x(-244:244)＝
[+1,+1,-1,+1,-1,+1,-1,-1,-1,+1,-1,-1,-1,+1,+1,
-1,+1,+1,+1,+1,+1,-1,-1,+1,+1,+1,+1,-1,+1,-1,
+1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,
-1,+1,+1,+1,-1,-1,-1,-1,-1,-1,+1,+1,+1,+1,+1,
+1,-1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,+1,-1,
-1,+1,+1,-1,+1,-1,+1,+1,+1,+1,+1,-1,-1,+1,+1,
+1,-1,+1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,
+1,-1,-1,+1,+1,+1,+1,-1,-1,+1,+1,+1,+1,+1,-1,
+1,+1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,-1,+1,+1,
-1,+1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,-1,-1,+1,
-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,-1,+1,-1,+1,-1,
+1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,+1,
-1,-1,-1,+1,+1,+1,+1,+1,+1,+1,+1,+1,+1,+1,+1,
-1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,+1,-1,-1,
+1,+1,-1,+1,-1,+1,+1,+1,+1,+1,-1,-1,+1,+1,+1,
-1,+1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,
-1,-1,0,0,0,0,0,+1,+1,-1,+1,-1,-1,+1,-1,
-1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,
-1,-1,-1,-1,+1,-1,+1,-1,-1,+1,+1,-1,+1,-1,+1,
+1,+1,-1,-1,+1,-1,-1,-1,+1,-1,-1,-1,-1,-1,-1,
-1,+1,-1,-1,-1,-1,+1,+1,+1,-1,-1,-1,-1,+1,-1,
-1,+1,+1,+1,-1,+1,+1,-1,-1,+1,-1,+1,-1,+1,+1,
+1,+1,-1,-1,+1,+1,+1,+1,+1,-1,+1,+1,-1,-1,-1,
+1,-1,-1,-1,+1,-1,+1,-1,+1,+1,-1,-1,-1,-1,-1,
+1,+1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,-1,-1,
+1,-1,-1,+1,-1,+1,-1,-1,+1,-1,+1,+1,-1,+1,+1,
-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,+1,+1,
+1,+1,+1,-1,+1,-1,+1,+1,-1,-1,+1,-1,+1,-1,-1,
-1,+1,+1,-1,+1,+1,+1,-1,+1,+1,+1,+1,+1,+1,+1,
+1,-1,-1,-1,-1,+1,+1,+1,-1,-1,-1,-1,+1,-1,-1,
+1,+1,+1,-1,+1,+1,-1,-1,+1,-1,+1,-1,+1,+1,+1,
+1,-1,-1,+1,+1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,
-1,-1,-1,+1,-1,+1,-1,+1,+1]
。
采用第二种HELTF序列后，其对应的PAPR值与第一种HELTF序列的PAPR值相同，参见图13，通过该组PAPR值可以看出，当导频子载波和其他子载波引入不同的旋转相位 时，PAPR值仍然很低。
实例六
80MHz带宽有1024个子载波，按照不同的资源块大小，如图1c所示RU大小可以是26、52、106、242、484、996个子载波。
80MHz 996子载波4X符号上的HE-LTF序列有很多种，下面罗列中几种：
第一种80MHz带宽的4x模式的HE-LTF序列：
Figure PCTCN2016096973-appb-000206
其中Ge＝{1,-1,1,-1,1,1,1,1,-1,-1,-1,1,1,1,1,1,1,1,1,-1,1,-1,-1,1,1,-1}
该HE-LTF序列中包括Ge、Ga与Gb序列以及由Ga与Gb序列生成的序列Gc，
Figure PCTCN2016096973-appb-000207
Figure PCTCN2016096973-appb-000208
Gd，位于空余leftover子载波位置上的+1或者-1，
进一步的，还可以包含连续的+Gc,
Figure PCTCN2016096973-appb-000209
或者，连续的+Ga,
Figure PCTCN2016096973-appb-000210
或者，连续的-Gc,
Figure PCTCN2016096973-appb-000211
或者，连续的+Ga,
Figure PCTCN2016096973-appb-000212
或者，连续的-Gc,
Figure PCTCN2016096973-appb-000213
或者，连续的-Ga,
Figure PCTCN2016096973-appb-000214
或者，连续的-Gd,
Figure PCTCN2016096973-appb-000215
或者，连续的-Gb,
Figure PCTCN2016096973-appb-000216
连续的+Gd,
Figure PCTCN2016096973-appb-000217
或者，连续的-Gb,
Figure PCTCN2016096973-appb-000218
或者，连续的+Gd,
Figure PCTCN2016096973-appb-000219
或者，连续的+Gb,
Figure PCTCN2016096973-appb-000220
或者，-Ge(1:13)，-Ge(14:26)。
也可以直接存储为：
HELTF4x(-500:500)＝
[+1,+1,-1,+1,-1,+1,-1,-1,-1,+1,-1,-1,-1,+1,+1,
-1,+1,+1,+1,+1,+1,-1,-1,+1,+1,+1,+1,-1,+1,-1,
+1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,
-1,+1,+1,+1,-1,-1,-1,-1,-1,-1,+1,+1,+1,+1,+1,
+1,-1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,+1,-1,
-1,+1,+1,-1,+1,-1,+1,+1,+1,+1,+1,-1,-1,+1,+1,
+1,-1,+1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,
+1,-1,-1,+1,+1,+1,+1,-1,-1,+1,+1,+1,+1,+1,-1,
+1,+1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,-1,+1,+1,
-1,+1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,-1,-1,+1,
-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,-1,+1,-1,+1,-1,
+1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,+1,
-1,-1,-1,+1,+1,+1,+1,-1,+1,+1,+1,+1,+1,+1,+1,
-1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,+1,-1,-1,
+1,+1,-1,+1,-1,+1,+1,+1,+1,+1,-1,-1,+1,+1,+1,
-1,+1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,
-1,-1,+1,-1,+1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,
-1,-1,+1,-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,-1,+1,
-1,+1,-1,+1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,+1,
+1,+1,+1,-1,-1,-1,+1,+1,+1,+1,-1,+1,-1,-1,-1,
-1,-1,-1,+1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,
-1,+1,+1,-1,-1,+1,-1,+1,-1,-1,-1,-1,-1,+1,+1,
-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,-1,-1,+1,-1,
-1,+1,-1,+1,+1,+1,+1,+1,+1,-1,-1,+1,+1,+1,+1,
+1,-1,+1,+1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,-1,
+1,+1,-1,+1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,-1,
-1,+1,-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,-1,+1,-1,
+1,-1,+1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,
+1,+1,-1,-1,-1,+1,+1,+1,+1,-1,-1,+1,+1,+1,+1,
+1,+1,-1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,+1,
-1,-1,+1,+1,-1,+1,-1,+1,+1,+1,+1,+1,-1,-1,+1,
+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,
-1,+1,-1,-1,-1,+1,-1,+1,-1,-1,-1,-1,+1,+1,+1,
-1,-1,+1,0,0,0,0,0,+1,-1,-1,-1,-1,-1,-1,
+1,-1,+1,+1,-1,-1,+1,+1,-1,+1,-1,+1,+1,-1,-1,
+1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,-1,+1,+1,
+1,+1,+1,+1,+1,-1,+1,-1,-1,+1,-1,-1,+1,-1,+1,
+1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,-1,-1,-1,-1,
+1,-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,-1,-1,+1,-1,
-1,+1,+1,+1,-1,+1,+1,+1,-1,+1,-1,+1,-1,-1,-1,
-1,-1,+1,+1,+1,-1,-1,-1,-1,+1,-1,-1,+1,+1,+1,
-1,+1,+1,-1,-1,+1,-1,+1,-1,-1,-1,-1,-1,-1,-1,
+1,+1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,-1,-1,
+1,-1,-1,+1,-1,+1,+1,+1,-1,+1,-1,-1,+1,+1,-1,
+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,+1,-1,-1,-1,
-1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,
-1,+1,+1,-1,+1,+1,+1,-1,-1,+1,+1,+1,+1,+1,-1,
+1,-1,-1,-1,-1,+1,+1,-1,-1,-1,-1,-1,+1,-1,-1,
+1,+1,+1,-1,+1,+1,+1,-1,+1,-1,+1,-1,-1,-1,-1,
-1,+1,+1,+1,-1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,
+1,+1,-1,-1,+1,-1,+1,-1,+1,+1,+1,-1,+1,-1,-1,
+1,+1,-1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,+1,
-1,-1,-1,-1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,
+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,+1,+1,+1,
+1,+1,-1,+1,+1,+1,+1,+1,-1,-1,+1,+1,+1,+1,+1,
-1,+1,+1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,-1,+1,
+1,+1,+1,+1,-1,-1,-1,+1,+1,+1,+1,-1,+1,+1,-1,
-1,-1,+1,-1,-1,+1,+1,-1,+1,-1,+1,-1,-1,-1,-1,
-1,-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,
-1,-1,+1,-1,-1,+1,-1,+1,-1,+1,-1,+1,-1,-1,+1,
+1,-1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,+1,-1,
-1,-1,-1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,
-1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,+1,+1,+1,+1,
+1,-1,+1,-1,-1,-1,-1,+1,+1,-1,-1,-1,-1,-1,+1,
-1,-1,+1,+1,+1,-1,+1,+1,+1,-1,+1,-1,+1,-1,-1,
-1,-1,-1,+1,+1,+1,-1,-1,-1,-1,+1,-1,-1,+1,+1,
+1,-1,+1,+1,-1,-1,+1,-1,+1,-1,+1]。
图14给出80MHz带宽下HE-LTF序列的PAPR值，通过该组PAPR值可以看出，当导频子载波和其他子载波引入不同的旋转相位时，PAPR值仍然很低.
第二种80MHz带宽下4x模式的HE-LTF序列：
Figure PCTCN2016096973-appb-000221
其中Ge＝{1,1,1,1,1,-1,1,-1,-1,1,-1,-1,1,1,-1,1,-1,1,-1,-1,-1,-1,1,1,-1,-1}
该HE-LTF序列中包括Ge、Ga与Gb序列以及由Ga与Gb序列生成的序列Gc，
Figure PCTCN2016096973-appb-000222
Figure PCTCN2016096973-appb-000223
Gd，位于空余leftover子载波位置上的+1或者-1，
进一步的，还可以包含连续的-Ga,
Figure PCTCN2016096973-appb-000224
或者，连续的-Gc,
Figure PCTCN2016096973-appb-000225
或者，连续的+Ga,
Figure PCTCN2016096973-appb-000226
或者，连续的-Gc,
Figure PCTCN2016096973-appb-000227
或者，连续的+Ga,
Figure PCTCN2016096973-appb-000228
或者，连续的+Gc,
Figure PCTCN2016096973-appb-000229
或者，连续的-Gb,
Figure PCTCN2016096973-appb-000230
连续的-Gd,
Figure PCTCN2016096973-appb-000231
或者，连续的+Gb,
Figure PCTCN2016096973-appb-000232
或者，连续的-Gd,
Figure PCTCN2016096973-appb-000233
或者，连续的+Gb,
Figure PCTCN2016096973-appb-000234
或者，连续的+Gd,
Figure PCTCN2016096973-appb-000235
或者-Ge(1:13)，-Ge(14:26)。
也可以直接存储为：
HELTF4x(-500:500)＝
[+1,-1,-1,-1,-1,-1,-1,+1,-1,-1,-1,+1,-1,-1,+1,
+1,+1,-1,+1,-1,+1,+1,-1,-1,+1,-1,+1,+1,+1,+1,
+1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,
+1,+1,-1,+1,+1,-1,+1,-1,+1,-1,-1,+1,-1,+1,-1,
+1,+1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,-1,-1,
+1,+1,-1,-1,-1,-1,-1,+1,-1,+1,-1,-1,+1,+1,-1,
+1,+1,+1,-1,-1,+1,-1,-1,-1,-1,+1,+1,+1,-1,-1,
-1,-1,+1,+1,-1,+1,-1,-1,+1,+1,-1,+1,-1,+1,+1,
+1,-1,-1,+1,-1,-1,-1,+1,-1,-1,-1,-1,-1,-1,+1,
+1,+1,+1,+1,+1,+1,-1,+1,+1,+1,-1,+1,+1,-1,-1,
-1,+1,-1,+1,-1,-1,+1,+1,-1,+1,-1,-1,-1,-1,-1,
-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,-1,
-1,+1,-1,-1,+1,-1,+1,+1,+1,-1,+1,-1,+1,-1,+1,
+1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,-1,-1,+1,
+1,-1,-1,-1,-1,-1,+1,-1,+1,-1,-1,+1,+1,-1,+1,
+1,+1,-1,-1,+1,-1,-1,-1,-1,+1,+1,+1,-1,-1,-1,
-1,+1,+1,+1,+1,+1,+1,+1,+1,-1,+1,+1,+1,-1,+1,
+1,-1,-1,-1,+1,-1,+1,-1,-1,+1,+1,-1,+1,-1,-1,
-1,-1,-1,-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,+1,+1,
-1,+1,-1,-1,+1,-1,-1,+1,-1,+1,+1,+1,+1,-1,+1,
-1,+1,-1,-1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,
+1,+1,-1,-1,+1,+1,+1,+1,+1,-1,+1,-1,+1,+1,-1,
-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,
+1,+1,+1,+1,-1,+1,-1,+1,-1,-1,+1,+1,-1,+1,-1,
+1,+1,+1,-1,-1,+1,-1,-1,-1,+1,-1,-1,-1,-1,-1,
-1,+1,+1,+1,+1,+1,+1,+1,-1,+1,+1,+1,-1,+1,+1,
-1,-1,-1,+1,-1,+1,-1,-1,+1,+1,-1,+1,-1,-1,-1,
-1,-1,-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,
+1,-1,-1,+1,-1,-1,+1,-1,+1,+1,-1,-1,+1,-1,+1,
-1,+1,+1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,-1,
-1,+1,+1,-1,-1,-1,-1,-1,+1,-1,+1,-1,-1,+1,+1,
-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,-1,+1,+1,+1,-1,
-1，-1，-1，+1，-1，-1，-1，-1，-1，+1，-1，+1，+1，-1，+1，
+1，-1，-1，0，0，0，0，0，-1，-1，+1，-1，+1，-1，+1，
+1，+1，+1，-1，-1，+1，+1，-1，-1，-1，-1，-1，+1，+1，-1，
-1，-1，-1，-1，+1，-1，-1，+1，+1，+1，-1，+1，+1，+1，-1，
+1，-1，+1，-1，+1，+1，+1，+1，-1，-1，-1，+1，+1，+1，+1，
-1，+1，+1，-1，-1，-1，+1，-1，-1，+1，+1，-1，+1，-1，+1，
+1，+1，-1，+1，-1，+1，+1，-1，-1，+1，-1，+1，-1，-1，-1，
+1，+1，-1，+1，+1，+1，-1，+1，+1，+1，+1，+1，+1，-1，+1，
-1，+1，+1，-1，+1，+1，-1，+1，-1，-1，-1，+1，+1，-1，+1，
+1，+1，-1，-1，+1，+1，+1，+1，+1，-1，+1，-1，+1，-1，+1，
+1，-1，-1，+1，-1，-1，-1，+1，+1，-1，+1，+1，+1，+1，-1，
-1，-1，+1，+1，+1，+1，-1，+1，+1，+1，+1，-1，-1，+1，+1，
+1，+1，+1，-1，+1，+1，-1，-1，-1，+1，-1，-1，-1，+1，-1，
+1，-1，+1，-1，-1，-1，-1，+1，+1，+1，-1，-1，-1，-1，+1，
-1，-1，+1，+1，+1，-1，+1，+1，-1，-1，+1，-1，+1，-1，-1，
-1，-1，+1，-1，+1，+1，-1，-1，+1，-1，+1，-1，-1，-1，+1，
+1，-1，+1，+1，+1，-1，+1，+1，+1，+1，+1，+1，-1，+1，-1，
+1，+1，-1，+1，+1，-1，+1，-1，-1，-1，+1，+1，-1，+1，+1，
+1，-1，-1，+1，+1，+1，+1，+1，+1，-1，+1，+1，+1，+1，-1，
-1，+1，+1，+1，+1，+1，-1，+1，+1，-1，-1，-1，+1，-1，-1，
-1，+1，-1，+1，-1，+1，-1，-1，-1，-1，+1，+1，+1，-1，-1，
-1，-1，+1，-1，-1，+1，+1，+1，-1，+1，+1，-1，-1，+1，-1，
+1，-1，-1，-1，+1，-1，+1，-1，-1，+1，+1，-1，+1，-1，+1，
+1，+1，-1，-1，+1，-1，-1，-1，+1，-1，-1，-1，-1，-1，-1，
+1，-1，+1，-1，-1，+1，-1，-1，+1，-1，+1，+1，+1，-1，-1，
+1，-1，-1，-1，+1，+1，-1，-1，-1，-1，-1，-1，+1，-1，+1，
-1，+1，+1，-1，-1，+1，-1，-1，-1，+1，+1，-1，+1，+1，+1，
+1，-1，-1，-1，+1，+1，+1，+1，+1，+1，+1，+1，+1，-1，-1，
+1，+1，+1，+1，+1，-1，+1，+1，-1，-1，-1，+1，-1，-1，-1，
+1,-1,+1,-1,+1,-1,-1,-1,-1,+1,+1,+1,-1,-1,-1,
-1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,+1,-1,+1,
-1,-1,-1,-1,+1,-1,+1,+1,-1,-1,+1,-1,+1,-1,-1,
-1,+1,+1,-1,+1,+1,+1,-1,+1,+1,+1,+1,+1,+1,-1,
+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,-1,+1,+1,-1,
+1,+1,+1,-1,-1,+1,+1,+1,+1,+1,+1]
采用第二种80MHz带宽下4x模式的HE-LTF序列后，其对应的PAPR值与第一种HELTF序列的PAPR值相同，参见图14，通过该组PAPR值可以看出，当导频子载波和其他子载波引入不同的旋转相位时，PAPR值仍然很低。
实例七
160MHz带宽的4x符号子载波设计可由两个80MHz带宽4x符号的子载波设计拼接而得，主80M频带和辅80M频带可以连续拼接或间隔一定带宽(例如间隔100MHz)，另外主80M频带和辅80M频带在频带的前后位置可根据实际情况进行灵活调整。因此，我们可分别定义主80M频带的4x HE-LTF序列(LTF80MHz_prime)和辅80M频带的4x HE-LTF序列(LTF80MHz_second)，并根据其间隔和频带先后顺序灵活以80M序列整体为单位调整极性以获得更低的PAPR。
为方便描述，令P1表示主80M序列的极性调整系数，P2表示辅80M序列的极性调整系数，我们固定P1为+1，P2则可为+1或-1，则当两个80M信道放置关系为[主80M,辅80M]时，160M序列为：HE-LTF160MHz＝[P1*LTF80MHz_prime,BI,P2*LTF80MHz_second]；当两个80M信道放置关系为[辅80M,主80M]时，160M序列为：HE-LTF160MHz＝[P2*LTF80MHz_second,BI,P1*LTF80MHz_prime]。其中，BI指两个80M信道边缘子载波之间的频率间隔。
当主80M和辅80M信道相邻时，BI＝zeros(1,23),即23个0；HE-LTF160MHz序列可以表示为：
[主80M,辅80M]情况下：
HE-LTF160MHz(-1012:1012)＝[P1*LTF80MHz_prime,zeros(1,23),P2*LTF80MHz_second]
[辅80M,主80M]情况下：
HE-LTF160MHz(-1012:1012)＝[P2*LTF80MHz_second,zeros(1,23),P1*LTF80MHz_prime]
其中,zeros(1,23)表示23个0；其余未显示的子载波指示号(如：-1024:-1013以及 1013:1023等)对应位置上的值默认为0。
如果主80M和辅80M信道不相邻时，BI可相应进行调整；
在本实施例中，主80MHz(LTF80MHz_prime)带宽对应的996子载波4X符号上的HE-LTF序列为实施例6中第一种80MHz带宽的4x模式的HE-LTF序列，则主80MHz带宽996子载波4X符号上的HE-LTF序列可以表示为：
Figure PCTCN2016096973-appb-000236
又可以表示为：
LTF80MHz_prime＝
[+1,+1,-1,+1,-1,+1,-1,-1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,+1,+1,-1,-1,+1,+1,+1,+1,-1,+1,-1,+1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,-1,+1,+1,+1,-1,-1,-1,-1,-1,-1,+1,+1,+1,+1,+1,+1,-1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,+1,-1,-1,+1,+1,-1,+1,-1,+1,+1,+1,+1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,+1,+1,+1,+1,-1,-1,+1,+1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,-1,+1,+1,-1,+1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,-1,+1,-1,+1,-1,+1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,+1,+1,+1,+1,-1,+1,+1,+1,+1,+1,+1,+1,-1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,+1,-1,-1,+1,+1,-1,+1,-1,+1,+1,+1,+1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,+1,-1,+1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,-1,+1,-1,+1,-1,+1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,+1,+1,+1,+1,-1,+1,-1,-1,-1,-1,-1,-1,+1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,-1,+1,+1,-1,-1,+1,-1,+1,-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,+1, +1，-1，+1，-1，-1，+1，-1，-1，+1，-1，+1，+1，+1，+1，+1，+1，-1，-1，+1，+1，+1，+1，+1，-1，+1，+1，-1，-1，-1，+1，-1，-1，-1，+1，-1，+1，-1，+1，+1，-1，+1，-1，+1，-1，+1，+1，+1，-1，+1，+1，+1，-1，-1，+1，-1，-1，-1，-1，-1，+1，+1，-1，-1，-1，-1，+1，-1，+1，-1，+1，+1，-1，-1，+1，-1，-1，-1，+1，+1，-1，+1，+1，+1，+1，-1，-1，-1，+1，+1，+1，+1，-1，-1，+1，+1，+1，+1，+1，+1，-1，+1，+1，+1，-1，+1，+1，-1，-1，-1，+1，-1，+1，-1，-1，+1，+1，-1，+1，-1，+1，+1，+1，+1，+1，-1，-1，+1，+1，+1，-1，+1，+1，-1，-1，-1，+1，-1，+1，+1，-1，+1，+1，-1，+1，-1，-1，-1，+1，-1，+1，-1，-1，-1，-1，+1，+1，+1，-1，-1，+1，0，0，0，0，0，+1，-1，-1，-1，-1，-1，-1，+1，-1，+1，+1，-1，-1，+1，+1，-1，+1，-1，+1，+1，-1，-1，+1，-1，+1，-1，-1，-1，+1，+1，-1，+1，+1，+1，-1，+1，+1，+1，+1，+1，+1，+1，-1，+1，-1，-1，+1，-1，-1，+1，-1，+1，+1，+1，-1，-1，+1，-1，-1，-1，+1，+1，-1，-1，-1，-1，-1，+1，-1，-1，-1，-1，-1，+1，+1，-1，-1，-1，-1，-1，+1，-1，-1，+1，+1，+1，-1，+1，+1，+1，-1，+1，-1，+1，-1，-1，-1，-1，-1，+1，+1，+1，-1，-1，-1，-1，+1，-1，-1，+1，+1，+1，-1，+1，+1，-1，-1，+1，-1，+1，-1，-1，-1，-1，-1，-1，-1，+1，+1，-1，-1，-1，+1，-1，-1，+1，+1，+1，-1，+1，-1，-1，+1，-1，-1，+1，-1，+1，+1，+1，-1，+1，-1，-1，+1，+1，-1，+1，-1，+1，+1，+1，-1，-1，+1，-1，-1，-1，+1，-1，-1，-1，-1，-1，-1，-1，+1，-1，+1，+1，-1，+1，+1，-1，+1，-1，-1，-1，+1，+1，-1，+1，+1，+1，-1，-1，+1，+1，+1，+1，+1，-1，+1，-1，-1，-1，-1，+1，+1，-1，-1，-1，-1，-1，+1，-1，-1，+1，+1，+1，-1，+1，+1，+1，-1，+1，-1，+1，-1，-1，-1，-1，-1，+1，+1，+1，-1，-1，-1，-1，+1，-1，-1，+1，+1，+1，-1，+1，+1，-1，-1，+1，-1，+1，-1，+1，+1，+1，-1，+1，-1，-1，+1，+1，-1，+1，-1，+1，+1，+1，-1，-1，+1，-1，-1，-1，+1，-1，-1，-1，-1，-1，-1，-1，+1，-1，+1，+1，-1，+1，+1，-1，+1，-1，-1，-1，+1，+1，-1，+1，+1，+1，-1，-1，+1，+1，+1，+1，+1，-1，+1，+1，+1，+1，+1，-1，-1，+1，+1，+1，+1，+1，-1，+1，+1，-1，-1，-1，+1，-1，-1，-1，+1，-1，+1，-1，+1，+1，+1，+1，+1，-1，-1，-1，+1，+1，+1，+1，-1，+1，+1，-1，-1，-1，+1，-1，-1，+1，+1，-1，+1，-1，+1，-1，-1，-1，-1，-1，-1，+1，+1，-1，-1，-1，+1，-1，-1，+1，+1，+1，-1，+1，-1，-1，+1，-1，-1，+1，-1，+1，-1，+1，-1，+1，-1，-1，+1，+1，-1，+1，-1，+1，+1，+1，-1，-1，+1，-1，-1，-1，+1，-1，-1， -1,-1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,+1,+1,+1,+1,+1,-1,+1,-1,-1,-1,-1,+1,+1,-1,-1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,+1,+1,-1,+1,-1,+1,-1,-1,-1,-1,-1,+1,+1,+1,-1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,+1,-1,+1,-1,+1]
上述的LTF80MHz_prime又可以表示为：
LTF80MHz_prime＝[{1st-484-RU}，{central-26-RU}，{2nd-484-RU}]
其中1st-484-RU表示为：
Figure PCTCN2016096973-appb-000237
central-26-RU表示为：
central-26-RU＝{-Ge(1:13),+1,0,0,0,0,0,+1,-Ge(14:26)}
2nd-484-RU表示为：
Figure PCTCN2016096973-appb-000238
辅80MHz(LTF80MHz_second)带宽996子载波4X符号上的HE-LTF序列是由1st-484-RU、2nd-484-RU和新的central-26-RU(newCentral-26-RU)组成，其中newCentral-26-RU可以表示为:
newCentral-26-RU＝[+1,+1,+1,-1,-1,-1,+1,+1,-1,-1,-1,-1,-1,+1,0,0,0,0,0,-1,-1,-1,-1,+1,-1,+1,+1,+1,+1,-1,+1,+1,-1]
LTF80MHz_second可以表示如下：
LTF80MHz_second＝[{1st-484-RU},newCentral-26-RU,(-1)*{2nd-484-RU}]；
也可以表示为：
LTF80MHz_second＝
[+1,+1,-1,+1,-1,+1,-1,-1,-1,+1,-1,-1,-1,+1,+1,-1,
+1,+1,+1,+1,+1,-1,-1,+1,+1,+1,+1,-1,+1,-1,+1,-1,
-1,+1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,-1,+1,+1,
+1,-1,-1,-1,-1,-1,-1,+1,+1,+1,+1,+1,+1,-1,+1,+1,
+1,-1,+1,+1,-1,-1,-1,+1,-1,+1,-1,-1,+1,+1,-1,+1,
-1,+1,+1,+1,+1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,
-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,+1,+1,+1,+1,
-1,-1,+1,+1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,-1,
-1,+1,-1,+1,-1,+1,+1,-1,+1,-1,+1,-1,+1,+1,+1,-1,
+1,+1,+1,-1,-1,+1,-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,
-1,+1,-1,+1,-1,+1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,
+1,+1,+1,+1,-1,-1,-1,+1,+1,+1,+1,-1,+1,+1,+1,+1,
+1,+1,+1,-1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,+1,
-1,-1,+1,+1,-1,+1,-1,+1,+1,+1,+1,+1,-1,-1,+1,+1,
+1,-1,+1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,
-1,-1,+1,-1,+1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,-1,
-1,+1,-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,-1,+1,-1,+1,
-1,+1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,+1,
-1,-1,-1,+1,+1,+1,+1,-1,+1,-1,-1,-1,-1,-1,-1,+1,
-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,-1,+1,+1,-1,-1,
+1,-1,+1,-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,+1,-1,-1,
+1,+1,+1,-1,+1,-1,-1,+1,-1,-1,+1,-1,+1,+1,+1,+1,
+1,+1,-1,-1,+1,+1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,
-1,-1,-1,+1,-1,+1,-1,+1,+1,-1,+1,-1,+1,-1,+1,+1,
+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,-1,-1,+1,+1,-1,
-1,-1,-1,+1,-1,+1,-1,+1,+1,-1,-1,+1,-1,-1,-1,+1,
+1,-1,+1,+1,+1,+1,-1,-1,-1,+1,+1,+1,+1,-1,-1,+1,
+1,+1,+1,+1,+1,-1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,
-1,+1,-1,-1,+1,+1,-1,+1,-1,+1,+1,+1,+1,+1,-1,-1,
+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,
-1,+1,-1,-1,+1,+1,+1,-1,-1,-1,+1,+1,-1,-1,-1,-1,
-1,+1,+0,+0,+0,+0,+0,-1,-1,-1,-1,+1,-1,+1,+1,+1,
+1,-1,+1,+1,-1,-1,+1,-1,+1,-1,-1,+1,+1,-1,+1,-1,
+1,+1,+1,-1,-1,+1,-1,-1,-1,+1,-1,-1,-1,-1,-1,-1,
-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,-1,+1,+1,-1,
+1,+1,+1,-1,-1,+1,+1,+1,+1,+1,-1,+1,+1,+1,+1,+1,
-1,-1,+1,+1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,-1,
-1,+1,-1,+1,-1,+1,+1,+1,+1,+1,-1,-1,-1,+1,+1,+1,
+1,-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,+1,-1,+1,-1,+1,
+1,+1,+1,+1,+1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,
-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,-1,+1,-1,+1,
+1,-1,-1,+1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,-1,
+1,+1,+1,+1,+1,+1,+1,-1,+1,-1,-1,+1,-1,-1,+1,-1,
+1,+1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,-1,-1,-1,-1,
+1,-1,+1,+1,+1,+1,-1,-1,+1,+1,+1,+1,+1,-1,+1,+1,
-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,-1,+1,+1,+1,+1,+1,
-1,-1,-1,+1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,-1,
+1,+1,-1,+1,-1,+1,-1,-1,-1,+1,-1,+1,+1,-1,-1,+1,
-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,-1,+1,+1,+1,+1,
+1,+1,+1,-1,+1,-1,-1,+1,-1,-1,+1,-1,+1,+1,+1,-1,
-1,+1,-1,-1,-1,+1,+1,-1,-1,-1,-1,-1,+1,-1,-1,-1,
-1,-1,+1,+1,-1,-1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,
+1,+1,+1,-1,+1,-1,+1,-1,-1,-1,-1,-1,+1,+1,+1,-1,
-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,+1,-1,
+1,-1,+1,+1,+1,+1,+1,+1,-1,-1,+1,+1,+1,-1,+1,+1,
-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,+1,-1,+1,
-1,+1,+1,-1,-1,+1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,
+1,-1,+1,+1,+1,+1,+1,+1,+1,-1,+1,-1,-1,+1,-1,-1,
+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,-1,-1,
-1,-1,+1,-1,+1,+1,+1,+1,-1,-1,+1,+1,+1,+1,+1,-1,
+1,+1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,-1,+1,+1,+1,
+1,+1,-1,-1,-1,+1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,
-1,-1,+1,+1,-1,+1,-1,+1,-1]
主80MHz带宽和辅80MHz带宽在两种频带先后顺序及各种频率间隔下的极性调整系数如下表所示，其中主辅信道间隔指的是两个80M频带的中心频率间隔(间隔80MHz指的是两个相邻80M信道拼接而成)。各种情况下相应的PAPR值也具体见表格，其中PAPR值为数据与导频4种相位差下的最大值。
Figure PCTCN2016096973-appb-000239
另外，为了降低系统实现复杂度，也可选择牺牲一定的PAPR性能，在各种情况下直 接拼接主80M序列和辅80M序列得到160M带宽下4x HE-LTF序列，即：所有[主80M,辅80M]情况下均使用[P1,P2]＝[+1,+1]或[P1,P2]＝[+1,-1]的极性调整系数；所有[辅80M,主80M]均使用[P2,P1]＝[+1,+1]或[P2,P1]＝[-1,+1]极性调整系数。
实施例八
160MHz带宽的2x符号子载波设计可由两个80MHz带宽2x符号的子载波设计拼接而得，主80M频带和辅80M频带可以连续拼接或间隔一定带宽(例如间隔100MHz)，另外主80M频带和辅80M频带在频带的前后位置可根据实际情况进行灵活调整。因此，我们可分别定义主80M频带的2x HE-LTF序列(LTF80MHz_prime)和辅80M频带的2x HE-LTF序列(LTF80MHz_second)，并根据其间隔和频带先后顺序灵活以80M序列整体为单位调整极性以获得更低的PAPR。
为方便描述，令P1表示主80M序列的极性调整系数，P2表示辅80M序列的极性调整系数，我们固定P1为+1，P2则可为+1或-1，则当两个80M信道放置关系为[主80M,辅80M]时，160M序列为：HE-LTF160MHz＝[P1*LTF80MHz_prime,BI,P2*LTF80MHz_second]；当两个80M信道放置关系为[辅80M,主80M]时，160M序列为：HE-LTF160MHz＝[P2*LTF80MHz_second,BI,P1*LTF80MHz_prime]。其中，BI指两个80M信道边缘子载波之间的频率间隔。
当主80M和辅80M信道相邻时，BI＝zeros(1,11),即11个0；HE-LTF160MHz序列可以表示为：
[主80M,辅80M]情况下：
HE-LTF160MHz(-1012:2:1012)＝[P1*LTF80MHz_prime,zeros(1,11),P2*LTF80MHz_second]
[辅80M,主80M]情况下：
HE-LTF160MHz(-1012:2:1012)＝[P2*LTF80MHz_second,zeros(1,11),P1*LTF80MHz_prime]
其中,zeros(1,11)表示11个0；其余未显示的子载波指示号(如：-1024:-1013，1013:1023以及-1011:2:1011等)对应位置上的值默认为0。
如果主80M和辅80M信道不相邻时，BI可相应进行调整；
在本实施例中，主80MHz(LTF80MHz_prime)带宽对应的2X符号上的HE-LTF序列为实施例3中的第二种80MHz的2X HE-LTF序列，则主80MHz带宽2X符号上的HE-LTF序列可以表示为：
Figure PCTCN2016096973-appb-000240
又可以表示为：
LTF80MHz_prime＝
[+1,+1,-1,+1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,+1,
-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,-1,-1,+1,+1,+1,
+1,-1,+1,+1,+1,-1,+1,-1,-1,+1,-1,-1,-1,+1,+1,
-1,-1,-1,+1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,
-1,-1,-1,+1,-1,-1,-1,-1,+1,-1,-1,+1,+1,-1,+1,
+1,+1,-1,-1,-1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,
+1,-1,-1,-1,+1,+1,+1,-1,-1,+1,+1,+1,-1,+1,+1,
-1,+1,-1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,+1,-1,
+1,+1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,
+1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,+1,-1,-1,+1,
-1,+1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,+1,-1,-1,
+1,+1,-1,+1,+1,+1,-1,-1,-1,-1,+1,+1,+1,-1,-1,
-1,-1,+1,-1,-1,-1,+1,-1,+1,+1,+1,-1,-1,+1,+1,
+1,-1,+1,+1,-1,+1,-1,-1,-1,-1,+1,-1,-1,-1,+1,
-1,+1,+1,-1,+1,+1,-1,+1,+1,-1,-1,+1,-1,-1,-1,
+1,+1,+1,+1,-1,+1,-1,-1,-1,+1,-1,-1,-1,-1,+1,
+1,+1,+1,-1,-1,-1,+1,+1,+1,0,0,0,+1,-1,-1,
+1,+1,-1,+1,-1,-1,-1,+1,+1,+1,+1,-1,+1,+1,+1,
-1,+1,-1,-1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,+1,
-1,-1,+1,-1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,+1,
-1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,-1,-1,+1,-1,
+1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,+1,+1,+1,+1,
-1,-1,-1,+1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,-1,
-1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,-1,-1,+1,-1,
-1,-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,-1,+1,+1,+1,
-1,+1,+1,+1,-1,+1,-1,+1,+1,-1,+1,-1,-1,-1,+1,
-1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,+1,-1,-1,+1,
+1,+1,-1,-1,-1,+1,+1,+1,+1,-1,+1,+1,+1,-1,+1,
-1,-1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,+1,-1,-1,
-1,-1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,
-1,-1,+1,-1,-1,-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,
-1,+1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,-1,+1,+1,
+1,-1,+1,+1,-1,-1,+1,-1,-1,-1,+1,+1,+1,+1,-1,
+1,+1,+1,-1,+1,+1]
上述的LTF80MHz_prime又可以表示为：
LTF80MHz_prime＝[{1st-484-RU}，{central-26-RU}，{2nd-484-RU}]
其中1st-484-RU表示为：
Figure PCTCN2016096973-appb-000241
central-26-RU表示为：
central-26-RU＝{+1,-1,-1,-1,+1,+1,+1,0,0,0,+1,-1,-1,+1,+1,-1,+1}
2nd-484-RU表示为：
Figure PCTCN2016096973-appb-000242
辅80MHz(LTF80MHz_second)带宽2X符号上的HE-LTF序列是由1st-484-RU、2nd-484-RU、新的central-26-RU(newCentral-26-RU)组成，其中newCentral-26-RU可以表示为:
newCentral-26-RU＝[-1,-1,+1,-1,-1,-1,-1,0,0,0,+1,+1,-1,-1,-1,+1,-1]
则LTF80MHz_second可以表示如下：
LTF80MHz_second＝[{1st-484-RU},newCentral-26-RU,(-1)*{2nd-484-RU}]；
也可以表示为：
LTF80MHz_second＝
[+1,+1,-1,+1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,+1,-1,
-1,+1,+1,-1,+1,+1,+1,-1,-1,-1,-1,+1,+1,+1,+1,-1,
+1,+1,+1,-1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,-1,-1,
+1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,-1,+1,
-1,-1,-1,-1,+1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,-1,
-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,+1,+1,
+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,+1,-1,-1,-1,-1,+1,
-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,-1,
-1,+1,-1,+1,+1,-1,+1,+1,+1,-1,-1,+1,+1,+1,-1,+1,
+1,-1,+1,-1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,+1,-1,
-1,-1,+1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,-1,-1,+1,
+1,+1,-1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,+1,+1,-1,
-1,+1,+1,+1,-1,+1,+1,-1,+1,-1,-1,-1,-1,+1,-1,-1,
-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,+1,-1,-1,+1,-1,-1,
-1,+1,+1,+1,+1,-1,+1,-1,-1,-1,+1,-1,-1,-1,-1,+1,
+1,+1,-1,-1,+1,-1,-1,-1,-1,+0,+0,+0,+1,+1,-1,-1,
-1,+1,-1,+1,+1,+1,-1,-1,-1,-1,+1,-1,-1,-1,+1,-1,
+1,+1,+1,+1,-1,-1,-1,+1,-1,-1,+1,+1,-1,+1,+1,-1,
+1,+1,-1,+1,-1,-1,-1,+1,-1,-1,-1,-1,+1,-1,+1,+1,
-1,+1,+1,+1,-1,-1,+1,+1,+1,-1,+1,-1,-1,-1,+1,-1,
-1,-1,-1,+1,+1,+1,-1,-1,-1,-1,+1,+1,+1,-1,+1,+1,
-1,-1,+1,-1,-1,-1,+1,+1,+1,+1,-1,+1,+1,+1,-1,+1,
-1,-1,+1,-1,+1,+1,-1,+1,+1,+1,-1,-1,+1,+1,+1,-1,
+1,+1,-1,+1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,-1,-1,
+1,-1,+1,+1,+1,-1,+1,+1,+1,+1,-1,+1,-1,-1,+1,-1,
-1,-1,+1,+1,-1,-1,-1,+1,+1,+1,-1,-1,-1,-1,+1,-1,
-1,-1,+1,-1,+1,+1,+1,+1,-1,-1,-1,+1,-1,-1,+1,+1,
-1,+1,+1,+1,+1,-1,+1,+1,+1,-1,+1,-1,-1,+1,-1,-1,
+1,-1,+1,+1,-1,+1,+1,+1,-1,-1,+1,+1,+1,-1,+1,+1,
-1,+1,-1,-1,-1,+1,-1,-1,-1,-1,+1,+1,+1,+1,-1,-1,
-1,+1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,-1,-1,+1,-1,
-1,-1,+1,-1,-1]
主80MHz带宽和辅80MHz带宽在两种频带先后顺序及各种频率间隔下的极性调整系数如下表所示，其中主辅信道间隔指的是两个80M频带的中心频率间隔(间隔80MHz指的是两个相邻80M信道拼接而成)。各种情况下相应的PAPR值也具体见表格，其中PAPR值为数据与导频4种相位差下的最大值。
Figure PCTCN2016096973-appb-000243
另外，为了降低系统实现复杂度，也可选择牺牲一定的PAPR性能，在各种情况下直接拼接主80M序列和辅80M序列得到160M带宽下2x HE-LTF序列，即：所有[主80M,辅80M]情况下均使用[P1,P2]＝[+1,+1]或[P1,P2]＝[+1,-1]的极性调整系数；所有[辅80M,主80M]均使用[P2,P1]＝[+1,+1]或[P2,P1]＝[-1,+1]极性调整系数。
上述各种带宽的2x或者4x模式下的HE-LTF序列仅为具体举例，这些优选的序列具有较低的PAPR值。当然，本发明实施方式还可以有其他的HE-LTF序列，其符合本实施方式提到的序列的特性，可以由前述提到的构造方法得到。
相应的，另一实施方式提供了一种HE-LTF的处理装置(未示出)，应用于采用OFDMA技术的无线局域网，包含处理单元，用于执行前述实施中的方法。具体的帧的结构与内容，可以参考前述各实施方式，此处不再赘述。处理单元可以是通用处理器、数字信号处理器、专用集成电路、现场可编程门阵列或者其他可编程逻辑器件、分立门或者晶体管逻辑器件、分立硬件组件，可以实现或者执行本发明实施例中的公开的各方法、步骤及逻辑框图。通用处理器可以是微处理器或者任何常规的处理器等。结合本发明实施例所公开的方法的步骤可以直接体现为硬件处理器执行完成，或者用处理器中的硬件及软件模块组合执行完成。容易理解的，上述HE-LTF的处理装置，可以位于接入点或者站点。
图15是本发明另一实施例的接入点的框图。图15的接入点包括接口101、处理单元102和存储器103。处理单元102控制接入点100的操作。存储器103可以包括只读存储器和随机存取存储器，并向处理单元102提供指令和数据。存储器103的一部分还可以包括非易失行随机存取存储器(NVRAM)。接入点100的各个组件通过总线系统109耦合在一起，其中总线系统109除包括数据总线之外，还包括电源总线、控制总线和状态信号总线。但是为了清楚说明起见，在图15中将各种总线都标为总线系统109。
上述本发明实施例揭示的发送前述各种帧的方法可以应用于处理单元102中，或者由处理单元102实现。在实现过程中，上述方法的各步骤可以通过处理单元102中的硬件的集成逻辑电路或者软件形式的指令完成。处理单元102可以是通用处理器、数字信号处理器、专用集成电路、现场可编程门阵列或者其他可编程逻辑器件、分立门或者晶 体管逻辑器件、分立硬件组件，可以实现或者执行本发明实施例中的公开的各方法、步骤及逻辑框图。通用处理器可以是微处理器或者任何常规的处理器等。结合本发明实施例所公开的方法的步骤可以直接体现为硬件处理器执行完成，或者用处理器中的硬件及软件模块组合执行完成。软件模块可以位于随机存储器，闪存、只读存储器，可编程只读存储器或者电可擦写可编程存储器、寄存器等本领域成熟的存储介质中。该存储介质位于存储器103，处理单元102读取存储器103中的信息，结合其硬件完成上述方法的步骤。
图16是本发明另一实施例的站点的框图。图16的接入点包括接口111、处理单元112和存储器113。处理单元112控制站点110的操作。存储器113可以包括只读存储器和随机存取存储器，并向处理单元112提供指令和数据。存储器113的一部分还可以包括非易失行随机存取存储器(NVRAM)。站点110的各个组件通过总线系统119耦合在一起，其中总线系统119除包括数据总线之外，还包括电源总线、控制总线和状态信号总线。但是为了清楚说明起见，在图16中将各种总线都标为总线系统119。
上述本发明实施例揭示的接收前述各种帧的方法可以应用于处理单元112中，或者由处理单元112实现。在实现过程中，上述方法的各步骤可以通过处理单元112中的硬件的集成逻辑电路或者软件形式的指令完成。处理单元112可以是通用处理器、数字信号处理器、专用集成电路、现场可编程门阵列或者其他可编程逻辑器件、分立门或者晶体管逻辑器件、分立硬件组件，可以实现或者执行本发明实施例中的公开的各方法、步骤及逻辑框图。通用处理器可以是微处理器或者任何常规的处理器等。结合本发明实施例所公开的方法的步骤可以直接体现为硬件处理器执行完成，或者用处理器中的硬件及软件模块组合执行完成。软件模块可以位于随机存储器，闪存、只读存储器，可编程只读存储器或者电可擦写可编程存储器、寄存器等本领域成熟的存储介质中。该存储介质位于存储器113，处理单元112读取存储器113中的信息，结合其硬件完成上述方法的步骤。
具体地，存储器113存储使得处理单元112执行如前述实施方式中提到的方法。
应理解，说明书通篇中提到的“一个实施例”或“一实施例”意味着与实施例有关的特定特征、结构或特性包括在本发明的至少一个实施例中。因此，在整个说明书各处出现的“在一个实施例中”或“在一实施例中”未必一定指相同的实施例。此外，这些 特定的特征、结构或特性可以任意适合的方式结合在一个或多个实施例中。在本发明的各种实施例中，上述各过程的序号的大小并不意味着执行顺序的先后，各过程的执行顺序应以其功能和内在逻辑确定，而不应对本发明实施例的实施过程构成任何限定。
另外，本文中术语“系统”和“网络”在本文中常被可互换使用。本文中术语“和/或”，仅仅是一种描述关联对象的关联关系，表示可以存在三种关系，例如，A和/或B，可以表示：单独存在A，同时存在A和B，单独存在B这三种情况。另外，本文中字符“/”，一般表示前后关联对象是一种“或”的关系。
应理解，在本发明实施例中，“与A相应的B”表示B与A相关联，根据A可以确定B。但还应理解，根据A确定B并不意味着仅仅根据A确定B，还可以根据A和/或其它信息确定B。
本领域普通技术人员可以意识到，结合本文中所公开的实施例描述的各示例的单元及算法步骤，能够以电子硬件、计算机软件或者二者的结合来实现，为了清楚地说明硬件和软件的可互换性，在上述说明中已经按照功能一般性地描述了各示例的组成及步骤。这些功能究竟以硬件还是软件方式来执行，取决于技术方案的特定应用和设计约束条件。专业技术人员可以对每个特定的应用来使用不同方法来实现所描述的功能，但是这种实现不应认为超出本发明的范围。
所属领域的技术人员可以清楚地了解到，为了描述的方便和简洁，上述描述的系统、装置和单元的具体工作过程，可以参考前述方法实施例中的对应过程，在此不再赘述。
在本申请所提供的几个实施例中，应该理解到，所揭露的系统、装置和方法，可以通过其它的方式实现。例如，以上所描述的装置实施例仅仅是示意性的，例如，所述单元的划分，仅仅为一种逻辑功能划分，实际实现时可以有另外的划分方式，例如多个单元或组件可以结合或者可以集成到另一个系统，或一些特征可以忽略，或不执行。另外，所显示或讨论的相互之间的耦合或直接耦合或通信连接可以是通过一些接口、装置或单元的间接耦合或通信连接，也可以是电的，机械的或其它的形式连接。
所述作为分离部件说明的单元可以是或者也可以不是物理上分开的，作为单元显示的部件可以是或者也可以不是物理单元，即可以位于一个地方，或者也可以分布到多个网络单元上。可以根据实际的需要选择其中的部分或者全部单元来实现本发明实施例方案的目的。
另外，在本发明各个实施例中的各功能单元可以集成在一个处理单元中，也可以是 各个单元单独物理存在，也可以是两个或两个以上单元集成在一个单元中。上述集成的单元既可以采用硬件的形式实现，也可以采用软件功能单元的形式实现。
通过以上的实施方式的描述，所属领域的技术人员可以清楚地了解到本发明可以用硬件实现，或固件实现，或它们的组合方式来实现。当使用软件实现时，可以将上述功能存储在计算机可读介质中或作为计算机可读介质上的一个或多个指令或代码进行传输。计算机可读介质包括计算机存储介质和通信介质，其中通信介质包括便于从一个地方向另一个地方传送计算机程序的任何介质。存储介质可以是计算机能够存取的任何可用介质。以此为例但不限于：计算机可读介质可以包括RAM、ROM、EEPROM、CD-ROM或其他光盘存储、磁盘存储介质或者其他磁存储设备、或者能够用于携带或存储具有指令或数据结构形式的期望的程序代码并能够由计算机存取的任何其他介质。此外。任何连接可以适当的成为计算机可读介质。例如，如果软件是使用同轴电缆、光纤光缆、双绞线、数字STA线(DSL)或者诸如红外线、无线电和微波之类的无线技术从网站、服务器或者其他远程源传输的，那么同轴电缆、光纤光缆、双绞线、DSL或者诸如红外线、无线和微波之类的无线技术包括在所属介质的定影中。如本发明所使用的，盘(Disk)和碟(disc)包括压缩光碟(CD)、激光碟、光碟、数字通用光碟(DVD)、软盘和蓝光光碟，其中盘通常磁性的复制数据，而碟则用激光来光学的复制数据。上面的组合也应当包括在计算机可读介质的保护范围之内。
总之，以上所述仅为本发明技术方案的较佳实施例而已，并非用于限定本发明的保护范围。凡在本发明的精神和原则之内，所作的任何修改、等同替换、改进等，均应包含在本发明的保护范围之内。

Claims (32)

  1. 一种发送无线局域网数据包中长训练序列的方法，其特征在于，所述数据包遵循802.11ax标准，所述方法包括：
    接入点AP根据传输总带宽获得对应所述传输总带宽的HE-LTF序列,(101)
    根据为站点分配的资源块RU大小和RU位置，将所述HE-LTF序列中的与所述RU位置对应的序列段，映射在所述分配的RU的子载波位置上并发送出去(102)；其中，所述传输总带宽为80M时2x模式下的HE-LTF为：
    HELTF2x(-500:2:500)＝[+1,+1,-1,+1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,+1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,-1,-1,+1,+1,+1,+1,-1,+1,+1,+1,-1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,-1,+1,-1,-1,-1,-1,+1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,-1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,+1,+1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,+1,-1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,+1,-1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,+1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,-1,-1,+1,+1,+1,-1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,+1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,+1,-1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,+1,-1,-1,+1,-1,-1,-1,+1,+1,+1,+1,-1,+1,-1,-1,-1,+1,-1,-1,-1,-1,+1,+1,+1,+1,-1,-1,-1,+1,+1,+1,0,0,0,+1,-1,-1,+1,+1,-1,+1,-1,-1,-1,+1,+1,+1,+1,-1,+1,+1,+1,-1,+1,-1,-1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,+1,-1,-1,+1,-1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,+1,-1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,-1,-1,+1,-1, +1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,+1,+1,+1,+1,-1,-1,-1,+1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,-1,+1,-1,+1,+1,-1,+1,-1,-1,-1,+1,-1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,+1,-1,-1,+1,+1,+1,-1,-1,-1,+1,+1,+1,+1,-1,+1,+1,+1,-1,+1,-1,-1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,+1,-1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,+1,-1,-1,-1,+1,+1,+1,+1,-1,+1,+1,+1,-1,+1,+1]；所述表达式的意思为：序号为-500～500的子载波中的偶数位置的子载波上的值依次为上述序列中的值，其他位置上的子载波的值是0。
  2. 根据权利要求1的方法，其特征在于
    所述HE-LTF序列为被存储的序列或者为构造得到的序列。
  3. 一种接收无线局域网数据包的方法，其特征在于，包括：
    接收遵循802.11ax标准的数据包，获得所述数据包中指示的传输总带宽(201)；
    根据所述传输总带宽获得对应所述传输总带宽的HE-LTF序列(202)；
    站点根据所述数据包中分配给所述站点的资源块RU大小和资源块RU位置，确定对应的HE-LTF序列段，作为对应所述RU的用于信道估计的参考序列(203)；
    其中，所述传输总带宽为80M时2x模式下的HE-LTF为：
    HELTF2x(-500:2:500)＝[+1,+1,-1,+1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,+1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,-1,-1,+1,+1,+1,+1,-1,+1,+1,+1,-1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,-1,+1,-1,-1,-1,-1,+1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,-1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1, +1,-1,-1,-1,+1,+1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,+1,-1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,+1,-1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,+1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,-1,-1,+1,+1,+1,-1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,+1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,+1,-1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,+1,-1,-1,+1,-1,-1,-1,+1,+1,+1,+1,-1,+1,-1,-1,-1,+1,-1,-1,-1,-1,+1,+1,+1,+1,-1,-1,-1,+1,+1,+1,0,0,0,+1,-1,-1,+1,+1,-1,+1,-1,-1,-1,+1,+1,+1,+1,-1,+1,+1,+1,-1,+1,-1,-1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,+1,-1,-1,+1,-1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,+1,-1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,-1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,+1,+1,+1,+1,-1,-1,-1,+1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,-1,+1,-1,+1,+1,-1,+1,-1,-1,-1,+1,-1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,+1,-1,-1,+1,+1,+1,-1,-1,-1,+1,+1,+1,+1,-1,+1,+1,+1,-1,+1,-1,-1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,+1,-1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,+1,-1,-1,-1,+1,+1,+1,+1,-1,+1,+1,+1,-1,+1,+1]；所述表达式的意思为：序号为-500～500的子载波中的偶数位置的子载波上的值依次为上述序列中的值，其他位置上的子载波的值是0。
  4. 根据权利要求3的方法，其特征在于，
    所述HE-LTF序列为被存储的序列或者为构造得到的序列。
  5. 一种无线局域网中发送数据包中的长训练序列的方法，所述数据包遵循802.11ax标准，其特征在于，
    站点STA根据指示的传输总带宽大小获得对应该带宽的HE-LTF序列(301)；
    所述站点STA根据被分配的资源块RU大小和RU位置，将所述HE-LTF序列中的与所述RU位置对应的序列段，映射在所述分配的RU的子载波位置上并发送出去(302)
    其中，所述传输总带宽为80M时2x模式下的HE-LTF为：
    HELTF2x(-500:2:500)＝[+1,+1,-1,+1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,+1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,-1,-1,+1,+1,+1,+1,-1,+1,+1,+1,-1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,-1,+1,-1,-1,-1,-1,+1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,-1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,+1,+1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,+1,-1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,+1,-1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,+1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,-1,-1,+1,+1,+1,-1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,+1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,+1,-1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,+1,-1,-1,+1,-1,-1,-1,+1,+1,+1,+1,-1,+1,-1,-1,-1,+1,-1,-1,-1,-1,+1,+1,+1,+1,-1,-1,-1,+1,+1,+1,0,0,0,+1,-1,-1,+1,+1,-1,+1,-1,-1,-1,+1,+1,+1,+1,-1,+1,+1,+1,-1,+1,-1,-1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,+1, -1,-1,+1,-1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,+1,-1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,-1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,+1,+1,+1,+1,-1,-1,-1,+1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,-1,+1,-1,+1,+1,-1,+1,-1,-1,-1,+1,-1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,+1,-1,-1,+1,+1,+1,-1,-1,-1,+1,+1,+1,+1,-1,+1,+1,+1,-1,+1,-1,-1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,+1,-1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,+1,-1,-1,-1,+1,+1,+1,+1,-1,+1,+1,+1,-1,+1,+1]；所述表达式的意思为：序号为-500～500的子载波中的偶数位置的子载波上的值依次为上述序列中的值，其他位置上的子载波的值是0。
  6. 根据权利要求5的方法，其特征在于，
    所述HE-LTF序列为被存储的序列或者为构造得到的序列。
  7. 一种接收无线局域网的数据包的方法，其特征在于，
    接入点AP接收遵循802.11ax标准的数据包，根据传输总带宽获得对应所述传输总带宽的HE-LTF序列(401)；
    所述AP根据为每一个上行站点分配的资源块RU大小和RU位置，从所述HE-LTF序列中确定对应的HE-LTF序列段，作为所述RU的用于信道估计的参考序列(402)；其中，所述传输总带宽为80M时2x模式下的HE-LTF为：
    HELTF2x(-500:2:500)＝[+1,+1,-1,+1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,+1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,-1,-1,+1,+1,+1,+1,-1,+1,+1,+1,-1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1, -1,-1,-1,+1,-1,-1,-1,-1,+1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,-1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,+1,+1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,+1,-1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,+1,-1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,+1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,-1,-1,+1,+1,+1,-1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,+1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,+1,-1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,+1,-1,-1,+1,-1,-1,-1,+1,+1,+1,+1,-1,+1,-1,-1,-1,+1,-1,-1,-1,-1,+1,+1,+1,+1,-1,-1,-1,+1,+1,+1,0,0,0,+1,-1,-1,+1,+1,-1,+1,-1,-1,-1,+1,+1,+1,+1,-1,+1,+1,+1,-1,+1,-1,-1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,+1,-1,-1,+1,-1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,+1,-1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,-1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,+1,+1,+1,+1,-1,-1,-1,+1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,-1,+1,-1,+1,+1,-1,+1,-1,-1,-1,+1,-1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,+1,-1,-1,+1,+1,+1,-1,-1,-1,+1,+1,+1,+1,-1,+1,+1,+1,-1,+1,-1,-1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,+1,-1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,+1,-1,-1,-1,+1,+1,+1,+1,-1, +1,+1,+1,-1,+1,+1]；所述表达式的意思为：序号为-500～500的子载波中的偶数位置的子载波上的值依次为上述序列中的值，其他位置上的子载波的值是0。
  8. 根据权利要求7的方法，其特征在于，
    所述HE-LTF序列为被存储的序列或者为构造得到的序列。
  9. 一种发送无线局域网数据包中长训练序列的方法，所述数据包遵循802.11ax标准，其特征在于，包括：
    接入点AP根据传输总带宽获得对应所述传输总带宽的HE-LTF序列,(101)
    所述AP根据为站点分配的资源块RU大小和RU位置，将所述HE-LTF序列中的与所述RU位置对应的序列段，映射在所述分配的RU的子载波位置上并发送出去(102)；其中，所述传输总带宽为80M时4x模式下的HE-LTF为：
    HELTF4x(-500:500)＝[+1,+1,-1,+1,-1,+1,-1,-1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,+1,+1,-1,-1,+1,+1,+1,+1,-1,+1,-1,+1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,-1,+1,+1,+1,-1,-1,-1,-1,-1,-1,+1,+1,+1,+1,+1,+1,-1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,+1,-1,-1,+1,+1,-1,+1,-1,+1,+1,+1,+1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,+1,+1,+1,+1,-1,-1,+1,+1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,-1,+1,+1,-1,+1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,-1,+1,-1,+1,-1,+1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,+1,+1,+1,+1,-1,+1,+1,+1,+1,+1,+1,+1,-1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,+1,-1,-1,+1,+1,-1,+1,-1,+1,+1,+1,+1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,+1,-1,+1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,-1,+1, -1,+1,-1,+1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,+1,+1,+1,+1,-1,+1,-1,-1,-1,-1,-1,-1,+1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,-1,+1,+1,-1,-1,+1,-1,+1,-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,-1,-1,+1,-1,-1,+1,-1,+1,+1,+1,+1,+1,+1,-1,-1,+1,+1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,-1,+1,+1,-1,+1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,-1,+1,-1,+1,-1,+1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,+1,+1,+1,+1,-1,-1,+1,+1,+1,+1,+1,+1,-1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,+1,-1,-1,+1,+1,-1,+1,-1,+1,+1,+1,+1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,-1,+1,-1,+1,-1,-1,-1,-1,+1,+1,+1,-1,-1,+1,0,0,0,0,0,+1,-1,-1,-1,-1,-1,-1,+1,-1,+1,+1,-1,-1,+1,+1,-1,+1,-1,+1,+1,-1,-1,+1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,-1,+1,+1,+1,+1,+1,+1,+1,-1,+1,-1,-1,+1,-1,-1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,-1,-1,-1,-1,+1,-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,+1,+1,-1,+1,-1,+1,-1,-1,-1,-1,-1,+1,+1,+1,-1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,+1,-1,+1,-1,-1,-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,-1,-1,+1,-1,-1,+1,-1,+1,+1,+1,-1,+1,-1,-1,+1,+1,-1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,+1,-1,-1,-1,-1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,+1,+1,+1,+1,+1,-1, +1,-1,-1,-1,-1,+1,+1,-1,-1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,+1,+1,-1,+1,-1,+1,-1,-1,-1,-1,-1,+1,+1,+1,-1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,+1,-1,+1,-1,+1,+1,+1,-1,+1,-1,-1,+1,+1,-1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,+1,-1,-1,-1,-1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,+1,+1,+1,+1,+1,-1,+1,+1,+1,+1,+1,-1,-1,+1,+1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,-1,+1,+1,+1,+1,+1,-1,-1,-1,+1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,+1,-1,+1,-1,+1,-1,-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,-1,-1,+1,-1,-1,+1,-1,+1,-1,+1,-1,+1,-1,-1,+1,+1,-1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,+1,-1,-1,-1,-1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,+1,+1,+1,+1,+1,-1,+1,-1,-1,-1,-1,+1,+1,-1,-1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,+1,+1,-1,+1,-1,+1,-1,-1,-1,-1,-1,+1,+1,+1,-1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,+1,-1,+1,-1,+1]；所述表达式的意思为：序号为-500～500的子载波中的每个子载波上的值依次为上述序列中的值。
  10. 根据权利要求9的方法，其特征在于
    所述HE-LTF序列为被存储的序列或者为构造得到的序列。
  11. 一种接收无线局域网数据包的方法，其特征在于，包括：
    接收遵循802.11ax标准的数据包，获得所述数据包中指示的传输总带宽(201)；
    根据所述传输总带宽获得对应所述传输总带宽的HE-LTF序列(202)；
    被调度的站点STA根据所述数据包中分配给所述站点的资源块RU大小和资源块RU位置，确定对应的HE-LTF序列段，作为所述RU的用于信道估计的参考序列(203)；
    其中，所述传输总带宽为80M时4x模式下的HE-LTF为：
    HELTF4x(-500:500)＝[+1,+1,-1,+1,-1,+1,-1,-1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,+1,+1,-1,-1,+1,+1,+1,+1,-1,+1,-1,+1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,-1,+1,+1,+1,-1,-1,-1,-1,-1,-1,+1,+1,+1,+1,+1,+1,-1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,+1,-1,-1,+1,+1,-1,+1,-1,+1,+1,+1,+1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,+1,+1,+1,+1,-1,-1,+1,+1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,-1,+1,+1,-1,+1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,-1,+1,-1,+1,-1,+1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,+1,+1,+1,+1,-1,+1,+1,+1,+1,+1,+1,+1,-1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,+1,-1,-1,+1,+1,-1,+1,-1,+1,+1,+1,+1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,+1,-1,+1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,-1,+1,-1,+1,-1,+1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,+1,+1,+1,+1,-1,+1,-1,-1,-1,-1,-1,-1,+1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,-1,+1,+1,-1,-1,+1,-1,+1,-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,-1,-1,+1,-1,-1,+1,-1,+1,+1,+1,+1,+1,+1,-1,-1,+1,+1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,-1,+1,+1,-1,+1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,-1,+1,-1,+1,-1,+1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1, +1,+1,-1,-1,-1,+1,+1,+1,+1,-1,-1,+1,+1,+1,+1,+1,+1,-1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,+1,-1,-1,+1,+1,-1,+1,-1,+1,+1,+1,+1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,-1,+1,-1,+1,-1,-1,-1,-1,+1,+1,+1,-1,-1,+1,0,0,0,0,0,+1,-1,-1,-1,-1,-1,-1,+1,-1,+1,+1,-1,-1,+1,+1,-1,+1,-1,+1,+1,-1,-1,+1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,-1,+1,+1,+1,+1,+1,+1,+1,-1,+1,-1,-1,+1,-1,-1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,-1,-1,-1,-1,+1,-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,+1,+1,-1,+1,-1,+1,-1,-1,-1,-1,-1,+1,+1,+1,-1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,+1,-1,+1,-1,-1,-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,-1,-1,+1,-1,-1,+1,-1,+1,+1,+1,-1,+1,-1,-1,+1,+1,-1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,+1,-1,-1,-1,-1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,+1,+1,+1,+1,+1,-1,+1,-1,-1,-1,-1,+1,+1,-1,-1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,+1,+1,-1,+1,-1,+1,-1,-1,-1,-1,-1,+1,+1,+1,-1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,+1,-1,+1,-1,+1,+1,+1,-1,+1,-1,-1,+1,+1,-1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,+1,-1,-1,-1,-1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,+1,+1,+1,+1,+1,-1,+1,+1,+1,+1,+1,-1,-1,+1,+1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,-1,+1,+1,+1,+1,+1,-1,-1,-1,+1,+1,+1,+1,-1,+1,+1,-1, -1,-1,+1,-1,-1,+1,+1,-1,+1,-1,+1,-1,-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,-1,-1,+1,-1,-1,+1,-1,+1,-1,+1,-1,+1,-1,-1,+1,+1,-1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,+1,-1,-1,-1,-1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,+1,+1,+1,+1,+1,-1,+1,-1,-1,-1,-1,+1,+1,-1,-1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,+1,+1,-1,+1,-1,+1,-1,-1,-1,-1,-1,+1,+1,+1,-1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,+1,-1,+1,-1,+1]；所述表达式的意思为：序号为-500～500的子载波中的每个子载波上的值依次为上述序列中的值。
  12. 根据权利要求11的方法，其特征在于，
    所述HE-LTF序列为被存储的序列或者为构造得到的序列。
  13. 一种无线局域网中发送数据包中的长训练序列的方法，所述数据包遵循802.11ax标准，其特征在于，
    站点STA根据指示的传输总带宽大小获得对应该带宽的HE-LTF序列(301)；
    所述站点STA根据被分配的资源块RU大小和RU位置，将所述HE-LTF序列中的与所述RU位置对应的序列段，映射在所述分配的RU的子载波位置上并发送出去(302)；
    其中，所述传输总带宽为80M时4x模式下的HE-LTF为：
    HELTF4x(-500:500)＝[+1,+1,-1,+1,-1,+1,-1,-1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,+1,+1,-1,-1,+1,+1,+1,+1,-1,+1,-1,+1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,-1,+1,+1,+1,-1,-1,-1,-1,-1,-1,+1,+1,+1,+1,+1,+1,-1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,+1,-1,-1,+1,+1,-1,+1,-1,+1,+1,+1,+1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,+1,+1,+1,+1,-1,-1,+1,+1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,-1,+1,+1, -1,+1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,-1,+1,-1,+1,-1,+1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,+1,+1,+1,+1,-1,+1,+1,+1,+1,+1,+1,+1,-1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,+1,-1,-1,+1,+1,-1,+1,-1,+1,+1,+1,+1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,+1,-1,+1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,-1,+1,-1,+1,-1,+1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,+1,+1,+1,+1,-1,+1,-1,-1,-1,-1,-1,-1,+1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,-1,+1,+1,-1,-1,+1,-1,+1,-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,-1,-1,+1,-1,-1,+1,-1,+1,+1,+1,+1,+1,+1,-1,-1,+1,+1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,-1,+1,+1,-1,+1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,-1,+1,-1,+1,-1,+1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,+1,+1,+1,+1,-1,-1,+1,+1,+1,+1,+1,+1,-1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,+1,-1,-1,+1,+1,-1,+1,-1,+1,+1,+1,+1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,-1,+1,-1,+1,-1,-1,-1,-1,+1,+1,+1,-1,-1,+1,0,0,0,0,0,+1,-1,-1,-1,-1,-1,-1,+1,-1,+1,+1,-1,-1,+1,+1,-1,+1,-1,+1,+1,-1,-1,+1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,-1,+1,+1,+1,+1,+1,+1,+1,-1,+1,-1,-1,+1,-1,-1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,-1,-1,-1,-1, +1,-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,+1,+1,-1,+1,-1,+1,-1,-1,-1,-1,-1,+1,+1,+1,-1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,+1,-1,+1,-1,-1,-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,-1,-1,+1,-1,-1,+1,-1,+1,+1,+1,-1,+1,-1,-1,+1,+1,-1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,+1,-1,-1,-1,-1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,+1,+1,+1,+1,+1,-1,+1,-1,-1,-1,-1,+1,+1,-1,-1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,+1,+1,-1,+1,-1,+1,-1,-1,-1,-1,-1,+1,+1,+1,-1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,+1,-1,+1,-1,+1,+1,+1,-1,+1,-1,-1,+1,+1,-1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,+1,-1,-1,-1,-1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,+1,+1,+1,+1,+1,-1,+1,+1,+1,+1,+1,-1,-1,+1,+1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,-1,+1,+1,+1,+1,+1,-1,-1,-1,+1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,+1,-1,+1,-1,+1,-1,-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,-1,-1,+1,-1,-1,+1,-1,+1,-1,+1,-1,+1,-1,-1,+1,+1,-1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,+1,-1,-1,-1,-1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,+1,+1,+1,+1,+1,-1,+1,-1,-1,-1,-1,+1,+1,-1,-1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,+1,+1,-1,+1,-1,+1,-1,-1,-1,-1,-1,+1,+1,+1,-1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,+1,-1,+1,-1,+1]；所述表达式的意思为：序号为 -500～500的子载波中的每个子载波上的值依次为上述序列中的值。
  14. 根据权利要求13的方法，其特征在于，
    所述HE-LTF序列为被存储的序列或者为构造得到的序列。
  15. 一种接收无线局域网的数据包的方法，其特征在于，
    接入点AP接收遵循802.11ax标准的数据包，根据传输总带宽获得对应所述传输总带宽的HE-LTF序列(401)；
    所述AP根据每一个上行站点被分配的资源块RU大小和RU位置，从所述HE-LTF序列中确定对应的HE-LTF序列段，作为所述RU的用于信道估计的参考序列(402)；
    其中，所述传输总带宽为80M时4x模式下的HE-LTF为：
    HELTF4x(-500:500)＝[+1,+1,-1,+1,-1,+1,-1,-1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,+1,+1,-1,-1,+1,+1,+1,+1,-1,+1,-1,+1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,-1,+1,+1,+1,-1,-1,-1,-1,-1,-1,+1,+1,+1,+1,+1,+1,-1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,+1,-1,-1,+1,+1,-1,+1,-1,+1,+1,+1,+1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,+1,+1,+1,+1,-1,-1,+1,+1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,-1,+1,+1,-1,+1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,-1,+1,-1,+1,-1,+1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,+1,+1,+1,+1,-1,+1,+1,+1,+1,+1,+1,+1,-1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,+1,-1,-1,+1,+1,-1,+1,-1,+1,+1,+1,+1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,+1,-1,+1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,-1,+1,-1,+1,-1,+1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,+1, +1,+1,+1,-1,-1,-1,+1,+1,+1,+1,-1,+1,-1,-1,-1,-1,-1,-1,+1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,-1,+1,+1,-1,-1,+1,-1,+1,-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,-1,-1,+1,-1,-1,+1,-1,+1,+1,+1,+1,+1,+1,-1,-1,+1,+1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,-1,+1,+1,-1,+1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,-1,+1,-1,+1,-1,+1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,+1,+1,+1,+1,-1,-1,+1,+1,+1,+1,+1,+1,-1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,+1,-1,-1,+1,+1,-1,+1,-1,+1,+1,+1,+1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,-1,+1,-1,+1,-1,-1,-1,-1,+1,+1,+1,-1,-1,+1,0,0,0,0,0,+1,-1,-1,-1,-1,-1,-1,+1,-1,+1,+1,-1,-1,+1,+1,-1,+1,-1,+1,+1,-1,-1,+1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,-1,+1,+1,+1,+1,+1,+1,+1,-1,+1,-1,-1,+1,-1,-1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,-1,-1,-1,-1,+1,-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,+1,+1,-1,+1,-1,+1,-1,-1,-1,-1,-1,+1,+1,+1,-1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,+1,-1,+1,-1,-1,-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,-1,-1,+1,-1,-1,+1,-1,+1,+1,+1,-1,+1,-1,-1,+1,+1,-1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,+1,-1,-1,-1,-1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,+1,+1,+1,+1,+1,-1,+1,-1,-1,-1,-1,+1,+1,-1,-1,-1,-1,-1,+1,-1,-1, +1,+1,+1,-1,+1,+1,+1,-1,+1,-1,+1,-1,-1,-1,-1,-1,+1,+1,+1,-1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,+1,-1,+1,-1,+1,+1,+1,-1,+1,-1,-1,+1,+1,-1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,+1,-1,-1,-1,-1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,+1,+1,+1,+1,+1,-1,+1,+1,+1,+1,+1,-1,-1,+1,+1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,-1,+1,+1,+1,+1,+1,-1,-1,-1,+1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,+1,-1,+1,-1,+1,-1,-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,-1,-1,+1,-1,-1,+1,-1,+1,-1,+1,-1,+1,-1,-1,+1,+1,-1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,+1,-1,-1,-1,-1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,+1,+1,+1,+1,+1,-1,+1,-1,-1,-1,-1,+1,+1,-1,-1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,+1,+1,-1,+1,-1,+1,-1,-1,-1,-1,-1,+1,+1,+1,-1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,+1,-1,+1,-1,+1]；所述表达式的意思为：序号为-500～500的子载波中的每个子载波上的值依次为上述序列中的值。
  16. 根据权利要求15的方法，其特征在于，
    所述HE-LTF序列为被存储的序列或者为构造得到的序列。
  17. 一种应用于无线局域网的装置，位于遵循802.11ax的接入点侧，其特征在于，包括
    用于根据传输总带宽获得对应所述传输总带宽的HE-LTF序列的单元(101)
    根据为站点分配的资源块RU大小和RU位置，将所述HE-LTF序列中的与所述RU位置对应的序列段，映射在所述分配的RU的子载波位置上并发送出去(102)的单元；其中，所述传输总带宽为80M时2x模式下的HE-LTF为：
    HELTF2x(-500:2:500)＝[+1,+1,-1,+1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,+1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,-1,-1,+1,+1,+1,+1,-1,+1,+1,+1,-1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,-1,+1,-1,-1,-1,-1,+1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,-1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,+1,+1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,+1,-1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,+1,-1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,+1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,-1,-1,+1,+1,+1,-1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,+1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,+1,-1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,+1,-1,-1,+1,-1,-1,-1,+1,+1,+1,+1,-1,+1,-1,-1,-1,+1,-1,-1,-1,-1,+1,+1,+1,+1,-1,-1,-1,+1,+1,+1,0,0,0,+1,-1,-1,+1,+1,-1,+1,-1,-1,-1,+1,+1,+1,+1,-1,+1,+1,+1,-1,+1,-1,-1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,+1,-1,-1,+1,-1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,+1,-1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,-1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,+1,+1,+1,+1,-1,-1,-1,+1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,-1,+1,-1,+1,+1,-1,+1,-1,-1,-1,+1,-1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,+1,-1,-1,+1,+1,+1,-1,-1,-1,+1,+1,+1,+1,-1,+1,+1,+1,-1,+1, -1,-1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,+1,-1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,+1,-1,-1,-1,+1,+1,+1,+1,-1,+1,+1,+1,-1,+1,+1]；所述表达式的意思为：序号为-500～500的子载波中的偶数位置的子载波上的值依次为上述序列中的值，其他位置上的子载波的值是0。
  18. 根据权利要求17的装置，其特征在于
    所述HE-LTF序列为被存储的序列或者为构造得到的序列。
  19. 一种应用于无线局域网的装置，位于遵循802.11ax的站点侧，其特征在于，包括
    用于接收遵循802.11ax标准的数据包，获得所述数据包中指示的传输总带宽(201)的单元；
    用于根据所述传输总带宽获得对应所述传输总带宽的HE-LTF序列(202)的单元；
    用于根据所述数据包中分配给所述站点的资源块RU大小和资源块RU位置，确定对应的HE-LTF序列段，作为对应所述RU的用于信道估计的参考序列(203)的单元；
    其中，所述传输总带宽为80M时2x模式下的HE-LTF为：
    HELTF2x(-500:2:500)＝[+1,+1,-1,+1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,+1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,-1,-1,+1,+1,+1,+1,-1,+1,+1,+1,-1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,-1,+1,-1,-1,-1,-1,+1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,-1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,+1,+1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,+1,-1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,+1,-1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,+1,-1,-1, +1,+1,-1,+1,+1,+1,-1,-1,-1,-1,+1,+1,+1,-1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,+1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,+1,-1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,+1,-1,-1,+1,-1,-1,-1,+1,+1,+1,+1,-1,+1,-1,-1,-1,+1,-1,-1,-1,-1,+1,+1,+1,+1,-1,-1,-1,+1,+1,+1,0,0,0,+1,-1,-1,+1,+1,-1,+1,-1,-1,-1,+1,+1,+1,+1,-1,+1,+1,+1,-1,+1,-1,-1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,+1,-1,-1,+1,-1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,+1,-1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,-1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,+1,+1,+1,+1,-1,-1,-1,+1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,-1,+1,-1,+1,+1,-1,+1,-1,-1,-1,+1,-1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,+1,-1,-1,+1,+1,+1,-1,-1,-1,+1,+1,+1,+1,-1,+1,+1,+1,-1,+1,-1,-1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,+1,-1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,+1,-1,-1,-1,+1,+1,+1,+1,-1,+1,+1,+1,-1,+1,+1]；所述表达式的意思为：序号为-500～500的子载波中的偶数位置的子载波上的值依次为上述序列中的值，其他位置上的子载波的值是0。
  20. 根据权利要求19的装置，其特征在于，
    所述HE-LTF序列为被存储的序列或者为构造得到的序列。
  21. 一种应用于无线局域网的装置，位于遵循802.11ax的站点侧，其特征在于，包括
    用于根据指示的传输总带宽大小获得对应该带宽的HE-LTF序列(301)的单元；
    用于根据被分配的资源块RU大小和RU位置，将所述HE-LTF序列中的与所述RU位置对应的序列段，映射在所述分配的RU的子载波位置上并发送出去(302)的单元；(302)
    其中，所述传输总带宽为80M时2x模式下的HE-LTF为：
    HELTF2x(-500:2:500)＝[+1,+1,-1,+1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,+1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,-1,-1,+1,+1,+1,+1,-1,+1,+1,+1,-1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,-1,+1,-1,-1,-1,-1,+1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,-1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,+1,+1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,+1,-1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,+1,-1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,+1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,-1,-1,+1,+1,+1,-1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,+1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,+1,-1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,+1,-1,-1,+1,-1,-1,-1,+1,+1,+1,+1,-1,+1,-1,-1,-1,+1,-1,-1,-1,-1,+1,+1,+1,+1,-1,-1,-1,+1,+1,+1,0,0,0,+1,-1,-1,+1,+1,-1,+1,-1,-1,-1,+1,+1,+1,+1,-1,+1,+1,+1,-1,+1,-1,-1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,+1,-1,-1,+1,-1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,+1,-1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,-1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,+1,+1,+1,+1,-1,-1,-1,+1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,-1,+1,+1,+1, -1,+1,+1,+1,-1,+1,-1,+1,+1,-1,+1,-1,-1,-1,+1,-1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,+1,-1,-1,+1,+1,+1,-1,-1,-1,+1,+1,+1,+1,-1,+1,+1,+1,-1,+1,-1,-1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,+1,-1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,+1,-1,-1,-1,+1,+1,+1,+1,-1,+1,+1,+1,-1,+1,+1]；所述表达式的意思为：序号为-500～500的子载波中的偶数位置的子载波上的值依次为上述序列中的值，其他位置上的子载波的值是0。
  22. 根据权利要求21的装置，其特征在于，
    所述HE-LTF序列为被存储的序列或者为构造得到的序列。
  23. 一种应用于无线局域网的装置，位于遵循802.11ax的接入点侧，其特征在于，包括
    用于接收遵循802.11ax标准的数据包，根据传输总带宽获得对应所述传输总带宽的HE-LTF序列(401)的单元；
    用于根据为每一个上行站点分配的资源块RU大小和RU位置，从所述HE-LTF序列中确定对应的HE-LTF序列段，作为所述RU的用于信道估计的参考序列(402)的单元；其中，所述传输总带宽为80M时4x模式下的HE-LTF为：
    HELTF2x(-500:2:500)＝[+1,+1,-1,+1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,+1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,-1,-1,+1,+1,+1,+1,-1,+1,+1,+1,-1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,-1,+1,-1,-1,-1,-1,+1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,-1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,+1,+1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,+1,-1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1, +1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,+1,-1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,+1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,-1,-1,+1,+1,+1,-1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,+1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,+1,-1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,+1,-1,-1,+1,-1,-1,-1,+1,+1,+1,+1,-1,+1,-1,-1,-1,+1,-1,-1,-1,-1,+1,+1,+1,+1,-1,-1,-1,+1,+1,+1,0,0,0,+1,-1,-1,+1,+1,-1,+1,-1,-1,-1,+1,+1,+1,+1,-1,+1,+1,+1,-1,+1,-1,-1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,+1,-1,-1,+1,-1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,+1,-1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,-1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,+1,+1,+1,+1,-1,-1,-1,+1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,-1,+1,-1,+1,+1,-1,+1,-1,-1,-1,+1,-1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,+1,-1,-1,+1,+1,+1,-1,-1,-1,+1,+1,+1,+1,-1,+1,+1,+1,-1,+1,-1,-1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,+1,-1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,+1,-1,-1,-1,+1,+1,+1,+1,-1,+1,+1,+1,-1,+1,+1]；所述表达式的意思为：序号为-500～500的子载波中的偶数位置的子载波上的值依次为上述序列中的值，其他位置上的子载波的值是0。
  24. 根据权利要求23的装置，其特征在于，
    所述HE-LTF序列为被存储的序列或者为构造得到的序列。
  25. 一种应用于无线局域网的装置，位于遵循802.11ax的接入点侧，其特征在于， 包括包括：
    用于根据传输总带宽获得对应所述传输总带宽的HE-LTF序列的单元,(101)
    用于根据为站点分配的资源块RU大小和RU位置，将所述HE-LTF序列中的与所述RU位置对应的序列段，映射在所述分配的RU的子载波位置上并发送出去(102)的单元；其中，所述传输总带宽为80M时4x模式下的HE-LTF为：
    HELTF4x(-500:500)＝[+1,+1,-1,+1,-1,+1,-1,-1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,+1,+1,-1,-1,+1,+1,+1,+1,-1,+1,-1,+1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,-1,+1,+1,+1,-1,-1,-1,-1,-1,-1,+1,+1,+1,+1,+1,+1,-1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,+1,-1,-1,+1,+1,-1,+1,-1,+1,+1,+1,+1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,+1,+1,+1,+1,-1,-1,+1,+1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,-1,+1,+1,-1,+1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,-1,+1,-1,+1,-1,+1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,+1,+1,+1,+1,-1,+1,+1,+1,+1,+1,+1,+1,-1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,+1,-1,-1,+1,+1,-1,+1,-1,+1,+1,+1,+1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,+1,-1,+1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,-1,+1,-1,+1,-1,+1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,+1,+1,+1,+1,-1,+1,-1,-1,-1,-1,-1,-1,+1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,-1,+1,+1,-1,-1,+1,-1,+1,-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,-1,-1,+1,-1, -1,+1,-1,+1,+1,+1,+1,+1,+1,-1,-1,+1,+1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,-1,+1,+1,-1,+1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,-1,+1,-1,+1,-1,+1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,+1,+1,+1,+1,-1,-1,+1,+1,+1,+1,+1,+1,-1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,+1,-1,-1,+1,+1,-1,+1,-1,+1,+1,+1,+1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,-1,+1,-1,+1,-1,-1,-1,-1,+1,+1,+1,-1,-1,+1,0,0,0,0,0,+1,-1,-1,-1,-1,-1,-1,+1,-1,+1,+1,-1,-1,+1,+1,-1,+1,-1,+1,+1,-1,-1,+1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,-1,+1,+1,+1,+1,+1,+1,+1,-1,+1,-1,-1,+1,-1,-1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,-1,-1,-1,-1,+1,-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,+1,+1,-1,+1,-1,+1,-1,-1,-1,-1,-1,+1,+1,+1,-1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,+1,-1,+1,-1,-1,-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,-1,-1,+1,-1,-1,+1,-1,+1,+1,+1,-1,+1,-1,-1,+1,+1,-1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,+1,-1,-1,-1,-1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,+1,+1,+1,+1,+1,-1,+1,-1,-1,-1,-1,+1,+1,-1,-1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,+1,+1,-1,+1,-1,+1,-1,-1,-1,-1,-1,+1,+1,+1,-1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,+1,-1,+1,-1,+1,+1,+1,-1,+1,-1,-1,+1,+1,-1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,+1, -1,-1,-1,-1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,+1,+1,+1,+1,+1,-1,+1,+1,+1,+1,+1,-1,-1,+1,+1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,-1,+1,+1,+1,+1,+1,-1,-1,-1,+1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,+1,-1,+1,-1,+1,-1,-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,-1,-1,+1,-1,-1,+1,-1,+1,-1,+1,-1,+1,-1,-1,+1,+1,-1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,+1,-1,-1,-1,-1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,+1,+1,+1,+1,+1,-1,+1,-1,-1,-1,-1,+1,+1,-1,-1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,+1,+1,-1,+1,-1,+1,-1,-1,-1,-1,-1,+1,+1,+1,-1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,+1,-1,+1,-1,+1]；所述表达式的意思为：序号为-500～500的子载波中的每个子载波上的值依次为上述序列中的值。
  26. 根据权利要求25的装置，其特征在于
    所述HE-LTF序列为被存储的序列或者为构造得到的序列。
  27. 一种应用于无线局域网的装置，位于遵循802.11ax的站点侧，其特征在于，包括：
    用于接收遵循802.11ax标准的数据包，获得所述数据包中指示的传输总带宽(201)的单元；
    用于根据所述传输总带宽获得对应所述传输总带宽的HE-LTF序列(202)的单元；
    用于根据所述数据包中分配给所述站点的资源块RU大小和资源块RU位置，确定对应的HE-LTF序列段，作为所述RU的用于信道估计的参考序列(203)的单元；
    其中，所述传输总带宽为80M时4x模式下的HE-LTF为：
    HELTF4x(-500:500)＝[+1,+1,-1,+1,-1,+1,-1,-1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,+1,+1,-1,-1,+1,+1,+1,+1,-1,+1,-1, +1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,-1,+1,+1,+1,-1,-1,-1,-1,-1,-1,+1,+1,+1,+1,+1,+1,-1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,+1,-1,-1,+1,+1,-1,+1,-1,+1,+1,+1,+1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,+1,+1,+1,+1,-1,-1,+1,+1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,-1,+1,+1,-1,+1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,-1,+1,-1,+1,-1,+1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,+1,+1,+1,+1,-1,+1,+1,+1,+1,+1,+1,+1,-1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,+1,-1,-1,+1,+1,-1,+1,-1,+1,+1,+1,+1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,+1,-1,+1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,-1,+1,-1,+1,-1,+1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,+1,+1,+1,+1,-1,+1,-1,-1,-1,-1,-1,-1,+1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,-1,+1,+1,-1,-1,+1,-1,+1,-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,-1,-1,+1,-1,-1,+1,-1,+1,+1,+1,+1,+1,+1,-1,-1,+1,+1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,-1,+1,+1,-1,+1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,-1,+1,-1,+1,-1,+1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,+1,+1,+1,+1,-1,-1,+1,+1,+1,+1,+1,+1,-1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,+1,-1,-1,+1,+1,-1,+1,-1,+1,+1,+1,+1,+1,-1,-1,+1, +1,+1,-1,+1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,-1,+1,-1,+1,-1,-1,-1,-1,+1,+1,+1,-1,-1,+1,0,0,0,0,0,+1,-1,-1,-1,-1,-1,-1,+1,-1,+1,+1,-1,-1,+1,+1,-1,+1,-1,+1,+1,-1,-1,+1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,-1,+1,+1,+1,+1,+1,+1,+1,-1,+1,-1,-1,+1,-1,-1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,-1,-1,-1,-1,+1,-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,+1,+1,-1,+1,-1,+1,-1,-1,-1,-1,-1,+1,+1,+1,-1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,+1,-1,+1,-1,-1,-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,-1,-1,+1,-1,-1,+1,-1,+1,+1,+1,-1,+1,-1,-1,+1,+1,-1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,+1,-1,-1,-1,-1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,+1,+1,+1,+1,+1,-1,+1,-1,-1,-1,-1,+1,+1,-1,-1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,+1,+1,-1,+1,-1,+1,-1,-1,-1,-1,-1,+1,+1,+1,-1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,+1,-1,+1,-1,+1,+1,+1,-1,+1,-1,-1,+1,+1,-1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,+1,-1,-1,-1,-1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,+1,+1,+1,+1,+1,-1,+1,+1,+1,+1,+1,-1,-1,+1,+1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,-1,+1,+1,+1,+1,+1,-1,-1,-1,+1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,+1,-1,+1,-1,+1,-1,-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,-1,-1,+1,-1,-1,+1,-1,+1,-1,+1,-1,+1,-1,-1,+1, +1,-1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,+1,-1,-1,-1,-1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,+1,+1,+1,+1,+1,-1,+1,-1,-1,-1,-1,+1,+1,-1,-1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,+1,+1,-1,+1,-1,+1,-1,-1,-1,-1,-1,+1,+1,+1,-1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,+1,-1,+1,-1,+1]；所述表达式的意思为：序号为-500～500的子载波中的每个子载波上的值依次为上述序列中的值。
  28. 根据权利要求27的装置，其特征在于，
    所述HE-LTF序列为被存储的序列或者为构造得到的序列。
  29. 一种应用于无线局域网的装置，位于遵循802.11ax的站点侧，其特征在于，包括
    用于根据指示的传输总带宽大小获得对应该带宽的HE-LTF序列(301)的单元；
    用于根据被分配的资源块RU大小和RU位置，将所述HE-LTF序列中的与所述RU位置对应的序列段，映射在所述分配的RU的子载波位置上并发送出去(302)
    其中，所述传输总带宽为80M时4x模式下的HE-LTF为：
    HELTF4x(-500:500)＝[+1,+1,-1,+1,-1,+1,-1,-1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,+1,+1,-1,-1,+1,+1,+1,+1,-1,+1,-1,+1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,-1,+1,+1,+1,-1,-1,-1,-1,-1,-1,+1,+1,+1,+1,+1,+1,-1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,+1,-1,-1,+1,+1,-1,+1,-1,+1,+1,+1,+1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,+1,+1,+1,+1,-1,-1,+1,+1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,-1,+1,+1,-1,+1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,-1,+1,-1,+1,-1,+1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,+1, -1,-1,-1,+1,+1,+1,+1,-1,+1,+1,+1,+1,+1,+1,+1,-1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,+1,-1,-1,+1,+1,-1,+1,-1,+1,+1,+1,+1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,+1,-1,+1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,-1,+1,-1,+1,-1,+1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,+1,+1,+1,+1,-1,+1,-1,-1,-1,-1,-1,-1,+1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,-1,+1,+1,-1,-1,+1,-1,+1,-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,-1,-1,+1,-1,-1,+1,-1,+1,+1,+1,+1,+1,+1,-1,-1,+1,+1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,-1,+1,+1,-1,+1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,-1,+1,-1,+1,-1,+1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,+1,+1,+1,+1,-1,-1,+1,+1,+1,+1,+1,+1,-1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,+1,-1,-1,+1,+1,-1,+1,-1,+1,+1,+1,+1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,-1,+1,-1,+1,-1,-1,-1,-1,+1,+1,+1,-1,-1,+1,0,0,0,0,0,+1,-1,-1,-1,-1,-1,-1,+1,-1,+1,+1,-1,-1,+1,+1,-1,+1,-1,+1,+1,-1,-1,+1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,-1,+1,+1,+1,+1,+1,+1,+1,-1,+1,-1,-1,+1,-1,-1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,-1,-1,-1,-1,+1,-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,+1,+1,-1,+1,-1,+1,-1,-1,-1,-1,-1,+1,+1,+1,-1,-1,-1,-1,+1,-1,-1,+1,+1,+1, -1,+1,+1,-1,-1,+1,-1,+1,-1,-1,-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,-1,-1,+1,-1,-1,+1,-1,+1,+1,+1,-1,+1,-1,-1,+1,+1,-1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,+1,-1,-1,-1,-1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,+1,+1,+1,+1,+1,-1,+1,-1,-1,-1,-1,+1,+1,-1,-1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,+1,+1,-1,+1,-1,+1,-1,-1,-1,-1,-1,+1,+1,+1,-1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,+1,-1,+1,-1,+1,+1,+1,-1,+1,-1,-1,+1,+1,-1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,+1,-1,-1,-1,-1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,+1,+1,+1,+1,+1,-1,+1,+1,+1,+1,+1,-1,-1,+1,+1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,-1,+1,+1,+1,+1,+1,-1,-1,-1,+1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,+1,-1,+1,-1,+1,-1,-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,-1,-1,+1,-1,-1,+1,-1,+1,-1,+1,-1,+1,-1,-1,+1,+1,-1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,+1,-1,-1,-1,-1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,+1,+1,+1,+1,+1,-1,+1,-1,-1,-1,-1,+1,+1,-1,-1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,+1,+1,-1,+1,-1,+1,-1,-1,-1,-1,-1,+1,+1,+1,-1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,+1,-1,+1,-1,+1]；所述表达式的意思为：序号为-500～500的子载波中的每个子载波上的值依次为上述序列中的值。
  30. 根据权利要求29的装置，其特征在于，
    所述HE-LTF序列为被存储的序列或者为构造得到的序列。
  31. 一种应用于无线局域网的装置，位于遵循802.11ax的接入点侧，其特征在于，包括
    用于接收遵循802.11ax标准的数据包，根据传输总带宽获得对应所述传输总带宽的HE-LTF序列(401)的单元；
    用于根据每一个上行站点被分配的资源块RU大小和RU位置，从所述HE-LTF序列中选择对应的HE-LTF序列段，作为所述RU的用于信道估计的参考序列(402)的单元；
    其中，所述传输总带宽为80M时4x模式下的HE-LTF为：
    HELTF4x(-500:500)＝[+1,+1,-1,+1,-1,+1,-1,-1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,+1,+1,-1,-1,+1,+1,+1,+1,-1,+1,-1,+1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,-1,+1,+1,+1,-1,-1,-1,-1,-1,-1,+1,+1,+1,+1,+1,+1,-1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,+1,-1,-1,+1,+1,-1,+1,-1,+1,+1,+1,+1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,+1,+1,+1,+1,-1,-1,+1,+1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,-1,+1,+1,-1,+1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,-1,+1,-1,+1,-1,+1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,+1,+1,+1,+1,-1,+1,+1,+1,+1,+1,+1,+1,-1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,+1,-1,-1,+1,+1,-1,+1,-1,+1,+1,+1,+1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,+1,-1,+1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,-1,+1,-1,+1,-1,+1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,+1,+1,+1,+1,-1,+1,-1,-1,-1,-1,-1,-1,+1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1, -1,+1,+1,-1,-1,+1,-1,+1,-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,-1,-1,+1,-1,-1,+1,-1,+1,+1,+1,+1,+1,+1,-1,-1,+1,+1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,-1,+1,+1,-1,+1,-1,+1,-1,+1,+1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,-1,+1,-1,+1,-1,+1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,+1,-1,-1,-1,+1,+1,+1,+1,-1,-1,+1,+1,+1,+1,+1,+1,-1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,+1,-1,-1,+1,+1,-1,+1,-1,+1,+1,+1,+1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,-1,+1,-1,+1,-1,-1,-1,-1,+1,+1,+1,-1,-1,+1,0,0,0,0,0,+1,-1,-1,-1,-1,-1,-1,+1,-1,+1,+1,-1,-1,+1,+1,-1,+1,-1,+1,+1,-1,-1,+1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,-1,+1,+1,+1,+1,+1,+1,+1,-1,+1,-1,-1,+1,-1,-1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,+1,+1,-1,-1,-1,-1,-1,+1,-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,+1,+1,-1,+1,-1,+1,-1,-1,-1,-1,-1,+1,+1,+1,-1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,+1,-1,+1,-1,-1,-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,-1,-1,+1,-1,-1,+1,-1,+1,+1,+1,-1,+1,-1,-1,+1,+1,-1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,+1,-1,-1,-1,-1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,+1,+1,+1,+1,+1,-1,+1,-1,-1,-1,-1,+1,+1,-1,-1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,+1,+1,-1,+1,-1,+1,-1,-1,-1,-1,-1,+1,+1,+1,-1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1, +1,+1,-1,-1,+1,-1,+1,-1,+1,+1,+1,-1,+1,-1,-1,+1,+1,-1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,+1,-1,-1,-1,-1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,+1,+1,+1,+1,+1,-1,+1,+1,+1,+1,+1,-1,-1,+1,+1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,-1,-1,+1,-1,+1,-1,+1,+1,+1,+1,+1,-1,-1,-1,+1,+1,+1,+1,-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,+1,-1,+1,-1,+1,-1,-1,-1,-1,-1,-1,+1,+1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,-1,-1,+1,-1,-1,+1,-1,+1,-1,+1,-1,+1,-1,-1,+1,+1,-1,+1,-1,+1,+1,+1,-1,-1,+1,-1,-1,-1,+1,-1,-1,-1,-1,-1,-1,-1,+1,-1,+1,+1,-1,+1,+1,-1,+1,-1,-1,-1,+1,+1,-1,+1,+1,+1,-1,-1,+1,+1,+1,+1,+1,-1,+1,-1,-1,-1,-1,+1,+1,-1,-1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,+1,+1,-1,+1,-1,+1,-1,-1,-1,-1,-1,+1,+1,+1,-1,-1,-1,-1,+1,-1,-1,+1,+1,+1,-1,+1,+1,-1,-1,+1,-1,+1,-1,+1]；所述表达式的意思为：序号为-500～500的子载波中的每个子载波上的值依次为上述序列中的值。
  32. 根据权利要求31的装置，其特征在于，
    所述HE-LTF序列为被存储的序列或者为构造得到的序列。
PCT/CN2016/096973 2015-08-26 2016-08-26 传输he-ltf序列的方法和装置 Ceased WO2017032343A1 (zh)

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