WO2022057614A1 - 冰箱及其控制方法 - Google Patents

冰箱及其控制方法 Download PDF

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Publication number
WO2022057614A1
WO2022057614A1 PCT/CN2021/115636 CN2021115636W WO2022057614A1 WO 2022057614 A1 WO2022057614 A1 WO 2022057614A1 CN 2021115636 W CN2021115636 W CN 2021115636W WO 2022057614 A1 WO2022057614 A1 WO 2022057614A1
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WO
WIPO (PCT)
Prior art keywords
air
compartment
room
temperature
supply port
Prior art date
Legal status (The legal status is an assumption and is not a legal conclusion. Google has not performed a legal analysis and makes no representation as to the accuracy of the status listed.)
Ceased
Application number
PCT/CN2021/115636
Other languages
English (en)
French (fr)
Inventor
崔展鹏
李佳明
吕鹏
姬立胜
Current Assignee (The listed assignees may be inaccurate. Google has not performed a legal analysis and makes no representation or warranty as to the accuracy of the list.)
Qingdao Haier Refrigerator Co Ltd
Haier Smart Home Co Ltd
Chongqing Haier Refrigeration Electric Appliance Co Ltd
Original Assignee
Qingdao Haier Refrigerator Co Ltd
Haier Smart Home Co Ltd
Chongqing Haier Refrigeration Electric Appliance Co Ltd
Priority date (The priority date is an assumption and is not a legal conclusion. Google has not performed a legal analysis and makes no representation as to the accuracy of the date listed.)
Filing date
Publication date
Application filed by Qingdao Haier Refrigerator Co Ltd, Haier Smart Home Co Ltd, Chongqing Haier Refrigeration Electric Appliance Co Ltd filed Critical Qingdao Haier Refrigerator Co Ltd
Priority to EP21868441.3A priority Critical patent/EP4206573B1/en
Priority to AU2021343202A priority patent/AU2021343202B2/en
Priority to US18/025,274 priority patent/US12292222B2/en
Publication of WO2022057614A1 publication Critical patent/WO2022057614A1/zh
Anticipated expiration legal-status Critical
Ceased legal-status Critical Current

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Classifications

    • F—MECHANICAL ENGINEERING; LIGHTING; HEATING; WEAPONS; BLASTING
    • F25—REFRIGERATION OR COOLING; COMBINED HEATING AND REFRIGERATION SYSTEMS; HEAT PUMP SYSTEMS; MANUFACTURE OR STORAGE OF ICE; LIQUEFACTION SOLIDIFICATION OF GASES
    • F25D—REFRIGERATORS; COLD ROOMS; ICE-BOXES; COOLING OR FREEZING APPARATUS NOT OTHERWISE PROVIDED FOR
    • F25D17/00—Arrangements for circulating cooling fluids; Arrangements for circulating gas, e.g. air, within refrigerated spaces
    • F25D17/04—Arrangements for circulating cooling fluids; Arrangements for circulating gas, e.g. air, within refrigerated spaces for circulating air, e.g. by convection
    • F25D17/06—Arrangements for circulating cooling fluids; Arrangements for circulating gas, e.g. air, within refrigerated spaces for circulating air, e.g. by convection by forced circulation
    • F25D17/062—Arrangements for circulating cooling fluids; Arrangements for circulating gas, e.g. air, within refrigerated spaces for circulating air, e.g. by convection by forced circulation in household refrigerators
    • F—MECHANICAL ENGINEERING; LIGHTING; HEATING; WEAPONS; BLASTING
    • F25—REFRIGERATION OR COOLING; COMBINED HEATING AND REFRIGERATION SYSTEMS; HEAT PUMP SYSTEMS; MANUFACTURE OR STORAGE OF ICE; LIQUEFACTION SOLIDIFICATION OF GASES
    • F25D—REFRIGERATORS; COLD ROOMS; ICE-BOXES; COOLING OR FREEZING APPARATUS NOT OTHERWISE PROVIDED FOR
    • F25D11/00—Self-contained movable devices, e.g. domestic refrigerators
    • F—MECHANICAL ENGINEERING; LIGHTING; HEATING; WEAPONS; BLASTING
    • F25—REFRIGERATION OR COOLING; COMBINED HEATING AND REFRIGERATION SYSTEMS; HEAT PUMP SYSTEMS; MANUFACTURE OR STORAGE OF ICE; LIQUEFACTION SOLIDIFICATION OF GASES
    • F25D—REFRIGERATORS; COLD ROOMS; ICE-BOXES; COOLING OR FREEZING APPARATUS NOT OTHERWISE PROVIDED FOR
    • F25D21/00—Defrosting; Preventing frosting; Removing condensed or defrost water
    • F25D21/04—Preventing the formation of frost or condensate
    • F—MECHANICAL ENGINEERING; LIGHTING; HEATING; WEAPONS; BLASTING
    • F25—REFRIGERATION OR COOLING; COMBINED HEATING AND REFRIGERATION SYSTEMS; HEAT PUMP SYSTEMS; MANUFACTURE OR STORAGE OF ICE; LIQUEFACTION SOLIDIFICATION OF GASES
    • F25D—REFRIGERATORS; COLD ROOMS; ICE-BOXES; COOLING OR FREEZING APPARATUS NOT OTHERWISE PROVIDED FOR
    • F25D23/00—General constructional features
    • F25D23/02—Doors; Covers
    • F—MECHANICAL ENGINEERING; LIGHTING; HEATING; WEAPONS; BLASTING
    • F25—REFRIGERATION OR COOLING; COMBINED HEATING AND REFRIGERATION SYSTEMS; HEAT PUMP SYSTEMS; MANUFACTURE OR STORAGE OF ICE; LIQUEFACTION SOLIDIFICATION OF GASES
    • F25D—REFRIGERATORS; COLD ROOMS; ICE-BOXES; COOLING OR FREEZING APPARATUS NOT OTHERWISE PROVIDED FOR
    • F25D29/00—Arrangement or mounting of control or safety devices
    • F—MECHANICAL ENGINEERING; LIGHTING; HEATING; WEAPONS; BLASTING
    • F25—REFRIGERATION OR COOLING; COMBINED HEATING AND REFRIGERATION SYSTEMS; HEAT PUMP SYSTEMS; MANUFACTURE OR STORAGE OF ICE; LIQUEFACTION SOLIDIFICATION OF GASES
    • F25D—REFRIGERATORS; COLD ROOMS; ICE-BOXES; COOLING OR FREEZING APPARATUS NOT OTHERWISE PROVIDED FOR
    • F25D2317/00—Details or arrangements for circulating cooling fluids; Details or arrangements for circulating gas, e.g. air, within refrigerated spaces, not provided for in other groups of this subclass
    • F25D2317/06—Details or arrangements for circulating cooling fluids; Details or arrangements for circulating gas, e.g. air, within refrigerated spaces, not provided for in other groups of this subclass with forced air circulation
    • F25D2317/062—Details or arrangements for circulating cooling fluids; Details or arrangements for circulating gas, e.g. air, within refrigerated spaces, not provided for in other groups of this subclass with forced air circulation along the inside of doors
    • F—MECHANICAL ENGINEERING; LIGHTING; HEATING; WEAPONS; BLASTING
    • F25—REFRIGERATION OR COOLING; COMBINED HEATING AND REFRIGERATION SYSTEMS; HEAT PUMP SYSTEMS; MANUFACTURE OR STORAGE OF ICE; LIQUEFACTION SOLIDIFICATION OF GASES
    • F25D—REFRIGERATORS; COLD ROOMS; ICE-BOXES; COOLING OR FREEZING APPARATUS NOT OTHERWISE PROVIDED FOR
    • F25D2323/00—General constructional features not provided for in other groups of this subclass
    • F25D2323/02—Details of doors or covers not otherwise covered
    • F25D2323/023—Door in door constructions
    • F—MECHANICAL ENGINEERING; LIGHTING; HEATING; WEAPONS; BLASTING
    • F25—REFRIGERATION OR COOLING; COMBINED HEATING AND REFRIGERATION SYSTEMS; HEAT PUMP SYSTEMS; MANUFACTURE OR STORAGE OF ICE; LIQUEFACTION SOLIDIFICATION OF GASES
    • F25D—REFRIGERATORS; COLD ROOMS; ICE-BOXES; COOLING OR FREEZING APPARATUS NOT OTHERWISE PROVIDED FOR
    • F25D2700/00—Means for sensing or measuring; Sensors therefor
    • F25D2700/12—Sensors measuring the inside temperature
    • F—MECHANICAL ENGINEERING; LIGHTING; HEATING; WEAPONS; BLASTING
    • F25—REFRIGERATION OR COOLING; COMBINED HEATING AND REFRIGERATION SYSTEMS; HEAT PUMP SYSTEMS; MANUFACTURE OR STORAGE OF ICE; LIQUEFACTION SOLIDIFICATION OF GASES
    • F25D—REFRIGERATORS; COLD ROOMS; ICE-BOXES; COOLING OR FREEZING APPARATUS NOT OTHERWISE PROVIDED FOR
    • F25D2700/00—Means for sensing or measuring; Sensors therefor
    • F25D2700/12—Sensors measuring the inside temperature
    • F25D2700/121—Sensors measuring the inside temperature of particular compartments
    • F—MECHANICAL ENGINEERING; LIGHTING; HEATING; WEAPONS; BLASTING
    • F25—REFRIGERATION OR COOLING; COMBINED HEATING AND REFRIGERATION SYSTEMS; HEAT PUMP SYSTEMS; MANUFACTURE OR STORAGE OF ICE; LIQUEFACTION SOLIDIFICATION OF GASES
    • F25D—REFRIGERATORS; COLD ROOMS; ICE-BOXES; COOLING OR FREEZING APPARATUS NOT OTHERWISE PROVIDED FOR
    • F25D29/00—Arrangement or mounting of control or safety devices
    • F25D29/005—Mounting of control devices

Definitions

  • the invention relates to the technical field of refrigeration and freezing, in particular to a refrigerator and a control method thereof.
  • the traditional refrigerator door is used to open and close the refrigerating compartment of the box.
  • a bottle seat is provided at the inner lining of the refrigerator door for placing bottled items.
  • the composite door refrigerator improves the structure and function of the door, so that the door includes a main door and an auxiliary door, and the main door is used to open and close the refrigeration compartment.
  • the main door defines a door body compartment whose front side is open, and the sub door is used to open and close the door body compartment.
  • the auxiliary door remains closed.
  • the door body compartment can be used for storage, and only the auxiliary door needs to be opened when picking and placing, and the main door does not need to be opened. Not only makes the operation more convenient and quick, but also avoids excessive cooling loss caused by frequent opening of the main door.
  • the purpose of the present invention is to solve at least one of the above-mentioned defects in the prior art, and to provide a refrigerator and a control method thereof.
  • the purpose of the present invention is to reduce or avoid condensation on the inner wall of the door compartment.
  • a further object of the present invention is to avoid the adverse effect on the room temperature and humidity between the doors due to fluctuations in the room temperature and humidity between the cabinets.
  • the present invention provides a control method for a refrigerator
  • the refrigerator includes a box body whose front side is opened to define a first compartment and a door body for opening and closing the first compartment
  • the door body includes a main door and a sub-door
  • the main door is used to open and close the first room and defines the second room
  • the auxiliary door is used to open and close the second room
  • the rear side of the main door is provided with a cold air for introducing the cold air in the first room into the second room.
  • the air outlet includes:
  • control method further includes:
  • the inner wall temperature T3 is taken as the dew point temperature
  • the air temperature T2 is taken as the ambient temperature
  • the critical value of the air relative humidity is calculated according to the corresponding relationship among the dew point temperature, ambient temperature and relative humidity
  • the step of acquiring the inner wall temperature T 3 of the second compartment includes: detecting the rear wall temperature of the second compartment and using it as the inner wall temperature T 3 .
  • the distance between the detection point of the temperature of the rear wall of the second compartment and the air supply port is less than or equal to the first preset distance.
  • the distance between the detection point of the air temperature T 2 and the air supply port is less than or equal to the second preset distance.
  • control method further includes:
  • air temperature T1 and air relative humidity The distance between the detection point and the air outlet is less than or equal to the third preset distance.
  • a fan is installed at the air supply port; and in the control method, if The steps of making the air supply port supply air to the second room, otherwise stopping the air supply port from supplying air to the second room include:
  • the present invention also provides a refrigerator, comprising:
  • a box the front side of which is open to define a first compartment
  • the door body includes a main door and an auxiliary door, the main door is used for opening and closing the first room and defines a second room, the auxiliary door is used for opening and closing the second room, and the rear side of the main door is provided with a door for opening and closing the first room.
  • the cold air in the room is introduced into the air supply port of the second room;
  • a controller which includes a processor and a memory, the memory stores a computer program for implementing the control method according to any of the above when the computer program is executed by the processor.
  • the first compartment is a refrigerating compartment; and the air supply port is provided at the top of the rear side of the main door, and the bottom of the rear side of the main door is also provided with an air return port for allowing the air of the second compartment to flow to the first compartment.
  • the refrigerator and the control method thereof of the present invention solve the problem that condensation is likely to occur on the inner wall of the second compartment defined by the door body in the composite door refrigerator to a certain extent.
  • the inventors realized that condensation is likely to occur on the inner wall of the second compartment, and an important reason is that high-humidity air is introduced from the first compartment of the cabinet. Especially after the door opening and closing operation of the first room is completed, the air with relatively high humidity and high temperature from the outside enters the first room. If it enters the second room immediately, condensation will easily occur on the inner wall of the second room. .
  • the present invention calculates the expected relative humidity of the air in the first room when the temperature changes to the air temperature T2 of the second room before introducing the cold air of the first room into the second room and the critical value of the air relative humidity at which the air condenses on the inner wall of the second compartment (The relative humidity of the air around the inner wall of the second room is greater than or equal to the critical value of the relative humidity of the air Condensation will inevitably occur on the inner wall), and compare the two, only if the Only make the air supply port supply air to the second room under the conditions of the first room, otherwise stop the air supply port from supplying air to the second room, so as to avoid opening and closing the door in the first room or other reasons that cause the air humidity in the room to rise.
  • the cold air in the first room is immediately introduced into the second room, resulting in the problem of condensation on the inner wall of the second room.
  • the present invention can prevent the outside high humidity and high temperature gas from entering the second room after the door opening and closing operation of the first room is completed, the temperature and humidity of the second room are also avoided due to fluctuations in the temperature of the first room.
  • the adverse effect of the second room keeps the air temperature and humidity of the second room at a more reasonable level.
  • the present invention estimates the air in the first room after entering the second room according to the absolute humidity ⁇ 1 of the air in the first room and the air temperature T 2 before the air in the first room enters the second room. , the expected relative humidity at a temperature change to T2 To determine whether it will generate condensation on the inner wall of the second room after entering the first room. This calculation method is very clever to realize the prediction of the condensation situation and avoid the generation of condensation.
  • the air temperature T 1 of the first compartment and the relative humidity of the air are The distance between the detection point of the rear wall temperature of the second room, the detection point of the air temperature T 2 and the air supply port is limited, so that the above detection points are closer to the air supply port, so as to target the airflow that will first enter the air supply port in the later stage. Temperature and humidity detection, so that the prediction of whether condensation will be caused after the airflow of the first room flows into the second room is more accurate.
  • FIG. 1 is a schematic structural diagram of a refrigerator according to an embodiment of the present invention.
  • FIG. 2 is a schematic block diagram of a refrigerator according to one embodiment
  • FIG. 3 is a schematic diagram of a control method of a refrigerator according to an embodiment of the present invention.
  • FIG. 4 is a flowchart of a control method of a refrigerator according to an embodiment of the present invention.
  • FIG. 1 is a schematic structural diagram of a refrigerator according to an embodiment of the present invention.
  • FIG. 2 is a schematic block diagram of a refrigerator according to one embodiment.
  • Embodiments of the present invention provide a control method for a refrigerator.
  • the refrigerator includes a box body 100 , a door body 200 and a controller 700 .
  • the front side of the box 100 is opened to define the first compartment 101 .
  • the door body 200 includes a main door 210 and an auxiliary door 220.
  • the main door 210 is used to open and close the first room 101 and defines a second room 201.
  • the auxiliary door 220 is used to open and close the second room 201.
  • the main door 210 is behind the main door 210.
  • An air supply port 212 for introducing the cold air in the first compartment 101 into the second compartment 201 is opened on the side. After the cold air enters the second compartment 201, the second compartment 201 is cooled.
  • the main door 210 can be rotatably installed on the box body 100 on the front side of the box body 100 , the front side of the main door 210 is opened to define the aforementioned second compartment 201 , and the auxiliary door 220 can be rotatably installed on the front side of the main door 210 at Main Gate 210.
  • the main door 210 When the main door 210 is open, the user accesses items from the first compartment 101 .
  • the main door 210 is closed and the auxiliary door 220 is opened, the user can access items from the second compartment 201 .
  • the controller 700 includes a processor 720 and a memory 710.
  • the memory 710 stores a computer program 711, and when the computer program 711 is executed by the processor 720, is used to implement the refrigerator control method of the embodiment of the present invention.
  • the refrigerator can be refrigerated by vapor compression refrigeration cycle system, semiconductor refrigeration system or other means.
  • the various compartments inside the refrigerator can be divided into refrigerating compartment, freezing compartment and changing room.
  • the temperature in the refrigerator is generally controlled between 2°C and 10°C, preferably 4°C to 7°C.
  • the temperature range in the freezer is generally controlled at -22°C to -14°C.
  • the variable temperature chamber can be adjusted between -18°C to 8°C to achieve a variable temperature effect.
  • the optimal storage temperature for different types of items is different, and the storage compartments suitable for storage are also different. For example, fruit and vegetable foods are suitable for storage in the refrigerator compartment, and meat foods are suitable for storage in the freezer compartment.
  • the aforementioned first compartment 101 is a refrigerator compartment.
  • the air supply port 212 can be arranged on the top of the rear side of the main door 210, and the bottom of the rear side of the main door 210 is also provided with a return air port 214 for allowing the air of the second room 201 to flow to the first room 101, and the cold air flows from the air supply port.
  • the air return port 214 at the bottom flows back to the first chamber 101 . In this way, a smoother air path circulation is formed, and the cooling effect of the second chamber 201 is improved. It can be understood that, if the air return port 214 is not provided, the air return can also be achieved through the air supply port 212 .
  • FIG. 3 is a schematic diagram of a control method of a refrigerator according to an embodiment of the present invention.
  • the control method of the refrigerator of the embodiment of the present invention is applicable to the refrigerator of each embodiment of the present invention.
  • the control method of the refrigerator includes:
  • Step S302 Acquire the air absolute humidity ⁇ 1 of the first room 101 and the air temperature T 2 of the second room 201 .
  • the absolute humidity ⁇ 1 of the air in the first compartment 101 may be measured in a direct manner. However, it is preferable to obtain the air absolute humidity ⁇ 1 through indirect calculation, so as to obtain a more accurate result. Specifically, the air temperature T 1 in the first room 101 and the air relative humidity in the first room 101 can be detected first According to air temperature T1 and air relative humidity Calculate the air absolute humidity ⁇ 1 .
  • Step S304 Calculate the expected relative humidity of the air in the first room 101 when the temperature changes to T 2 according to the absolute air humidity ⁇ 1 and the air temperature T 2 And, determine the critical value of the relative humidity of the air at which the air of the second room 201 condenses on the inner wall of the second room 201
  • the absolute humidity of moist air refers to the mass of water vapor contained in a unit volume of moist air. Under the conditions of a certain air pressure and a certain temperature, there is an upper limit of the water vapor that can be contained in a unit volume of air. If the water vapor contained in the volume of air exceeds the upper limit, that is, the maximum absolute humidity is reached, and water vapor condensation will occur.
  • the relative humidity of moist air refers to the ratio of the absolute humidity of moist air at a certain temperature to the maximum absolute humidity that can be achieved at the same temperature, and the number is a percentage. Since the higher the temperature, the stronger the ability of the air to hold water vapor, so the relative humidity of the humid air will change with the change of the temperature when the absolute humidity of the humid air is constant.
  • step S304 the expected relative humidity That is: if the air intake air whose absolute humidity is ⁇ 1 in the first room 101 enters the second room 201, it exchanges heat with the air in the second room 201, and the temperature changes to the temperature of the air in the second room 201.
  • the critical value of relative humidity refers to the minimum relative humidity that can make the air condense on the inner wall of the second compartment 201 when the air temperature is T 2 , that is, the minimum relative humidity that keeps the inner wall of the second compartment 201 in a non-condensing state.
  • Maximum relative humidity The relative humidity of the air around the inner wall of the second compartment 201 is greater than or equal to the critical value of the relative humidity of the air , condensation will form on the inner wall.
  • Step S306 Compare the expected relative humidity and air relative humidity threshold the size of.
  • Step S308 if The air supply port 212 is made to blow air to the second room 201 , otherwise, the air supply port 212 is made to stop blowing air to the second room 201 .
  • a fan 230 is installed at the air supply port 212.
  • step S308 if The fan 230 is turned on to make the air supply port 212 supply air to the second room 201 ; otherwise, the fan 230 is turned off, so that the air supply port 212 stops supplying air to the second room 201 .
  • a damper can also be provided at the air supply port 212, and the air supply to the second compartment 201 can be started or stopped by controlling the opening and closing of the damper.
  • the fan 230 and the damper are set at the same time, and the fan 230 and the damper are controlled to be turned on or off at the same time, so as to control the air supply state of the air supply port 212 more precisely.
  • steps S302 to S308 need to be re-executed, so that the first room 101 and the second room need to be re-executed.
  • the change of the temperature and humidity of 201 adjusts the switch state of the air supply port 212 as soon as possible.
  • the control method of the embodiment of the present invention solves, to a certain extent, the problem that condensation easily occurs on the inner wall of the second compartment 201 defined by the door body 200 in the composite door refrigerator.
  • the inventor realized that the inner wall of the second compartment 201 is prone to condensation, and an important reason is that high-humidity air is introduced from the first compartment 101 of the box body 100 .
  • the outside air with relatively high humidity and temperature enters the first room 101 , and then enters the second room 201 , and it is easier for the inner wall of the second room 201 Condensation occurs.
  • the present invention calculates the expected relative humidity of the air in the first room 101 when the temperature changes to the air temperature T2 of the second room 201 before introducing the cold air of the first room 101 into the second room 201 and the critical value of the relative humidity of the air at which the air condenses on the inner wall of the second compartment 201 and compare the two, only satisfying Only make the air supply port 212 supply air to the second room 201 under certain conditions, otherwise make the air supply port 212 stop supplying air to the second room 201 to avoid opening and closing the door of the first room 101 or other causes.
  • the cold air in the first room 101 is introduced into the second room 201 , resulting in condensation on the inner wall of the second room 201 . Since the present invention can prevent the outside high humidity and high temperature gas from entering the second room 201 after the door opening and closing operation of the first room 101 is completed, it also avoids the impact on the second room 201 due to the temperature fluctuation of the first room 101. The adverse effects of the temperature and humidity in the second room 201 keep the air temperature and humidity in the second room 201 at a reasonable level.
  • the air in the first room 101 before the air of the first room 101 enters the second room 201, according to the absolute humidity ⁇ 1 of the air in the first room 101 and the air temperature T 2 , it is estimated that if the air in the first room 101 is air The expected relative humidity when the temperature changes to T2 after entering the second chamber 201 To determine whether condensation will occur on the inner wall of the second room 201 after entering the first room 101 .
  • This calculation method is very clever to realize the prediction of the condensation situation and avoid the generation of condensation.
  • the refrigerator can achieve higher technical effects by further optimizing and configuring the above steps.
  • the following describes the control method of the refrigerator in this embodiment in detail with reference to the introduction of an optional execution process of this embodiment. It should be noted that this embodiment is only an example to illustrate the execution process. During specific implementation, the execution sequence and operating conditions of some steps may be modified according to specific implementation requirements.
  • FIG. 4 is a flowchart of a control method of a refrigerator according to an embodiment of the present invention. As shown in Figure 4, the control method of the refrigerator may include the following steps:
  • Step S402 Detect the air temperature T 1 in the first room 101 and the relative humidity of the air in the first room 101 and the air temperature T 2 of the second compartment 201 and the inner wall temperature T 3 of the second compartment 201 .
  • the first temperature sensor 300 can be used to detect the air temperature T 1 in the first room 101
  • the relative humidity sensor 400 can be used to detect the relative humidity of the air in the first room 101 .
  • humidity The air temperature T 2 of the second compartment 201 is detected by the second temperature sensor 500
  • the inner wall temperature T 3 of the second compartment 201 is detected by the third temperature sensor 600 .
  • the first temperature sensor 300 , the relative humidity sensor 400 , the second temperature sensor 500 and the third temperature sensor 600 are all connected to the controller 700 so as to transmit detection signals to the controller 700 .
  • the temperature of the rear wall 211 of the second compartment 201 is detected and used as the inner wall temperature T 3 .
  • the inventor realized that since the rear wall 211 of the second room 201 is adjacent to the first room 101, and the air in the first room 101 can conduct heat transfer through thermal conduction, the temperature of the rear wall 211 is higher than that of the second room 101.
  • the temperature of the wall surface of the chamber 201 is lower, and condensation is more likely to occur. It is only necessary to ensure that the rear wall 211 does not condense, and basically other walls can be guaranteed not to condense. Therefore, in this embodiment, only the temperature of the rear wall is detected, so as to better realize the purpose of preventing condensation.
  • Step S404 According to the air temperature T1 in the first room 101 and the relative humidity of the air in the first room 101 The absolute air humidity ⁇ 1 of the first chamber 101 is calculated.
  • the specific calculation method for calculating absolute humidity by air temperature and relative humidity is known to those skilled in the art, and belongs to the basic knowledge commonly used in the refrigeration field.
  • Step S406 According to the absolute air humidity ⁇ 1 and the air temperature T 2 , calculate the expected relative humidity of the air in the first room 101 when the temperature changes to T 2
  • Step S408 Taking the inner wall temperature T3 of the second compartment 201 as the dew point temperature, taking the air temperature T2 as the ambient temperature, and calculating the critical value of the air relative humidity according to the corresponding relationship among the dew point temperature, the ambient temperature and the relative humidity Specifically, the "correspondence between dew point temperature, ambient temperature and relative humidity" is known to those skilled in the art, and belongs to the basic knowledge commonly used in the refrigeration field, including calculation formulas and relational tables, which need not be repeated here.
  • Step S404 and step S408 are both steps after step S402, but this embodiment does not limit the execution order between step S404 and step S408.
  • Step S410 Judgment is established. If yes, go to step S412; if not, go to step S414.
  • Step S412 Turn on the fan 230.
  • the purpose of turning on the fan 230 is to make the air supply port 212 supply air to the second compartment 201 .
  • Step S414 Turn off the fan 230.
  • the purpose of turning off the fan 230 is to stop the air supply from the air supply port 212 to the second compartment 201 .
  • step S402 is continuously performed again to form a loop.
  • step S402 is continuously performed again to form a loop.
  • the distance between the detection point of the rear wall temperature of the second compartment 201 and the air supply port 212 is less than or equal to the first preset distance, that is, the distance between the second temperature sensor 500 and the air supply port 212 (refer to is the lower edge closest to the air supply port 212 ) is less than or equal to the first preset distance.
  • the distance between the detection point of the air temperature T 2 and the air supply port 212 is less than or equal to the second preset distance, that is, the distance between the third temperature sensor 600 and the air supply port 212 is less than or equal to the second preset distance.
  • the distance between the detection point and the air supply port 212 is less than or equal to the third preset distance, that is, the distance between the first temperature sensor 300 and the relative humidity sensor 400 and the air supply port 212 is less than or equal to the third preset distance.
  • the first preset distance, the second preset distance and the third preset distance may be the same or different values between 10 and 20 cm.
  • the air temperature T 1 and the air relative humidity of the first room 101 The distance between the detection point of the rear wall temperature of the second room 201, the detection point of the air temperature T 2 and the air supply port 212 is limited, and the purpose is to make the above detection points closer to the air supply port 212, so that the air supply port will be the first to enter the air supply port in the later stage.
  • the airflow of 212 is subjected to targeted temperature and humidity detection, so that the prediction of whether condensation will be caused after the airflow of the first room 101 flows into the second room 201 is more accurate.

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  • Engineering & Computer Science (AREA)
  • Chemical & Material Sciences (AREA)
  • Combustion & Propulsion (AREA)
  • Physics & Mathematics (AREA)
  • Mechanical Engineering (AREA)
  • Thermal Sciences (AREA)
  • General Engineering & Computer Science (AREA)
  • Cold Air Circulating Systems And Constructional Details In Refrigerators (AREA)
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Abstract

一种冰箱及其控制方法。冰箱包括前侧敞开以限定出第一间室的箱体和用于开闭第一间室的门体，门体包括主门和副门，主门用于开闭第一间室且限定有第二间室，副门用于开闭第二间室，主门后侧开设有用于将第一间室内的冷气引入第二间室的送风口，控制方法包括：获取第一间室的空气绝对湿度ρ 1和第二间室的空气温度T 2；根据空气绝对湿度ρ 1和空气温度T 2，计算第一间室空气在温度变化至T 2时的预期相对湿度φ3；确定第二间室空气在第二间室内壁产生凝露的空气相对湿度临界值φ0；比较预期相对湿度φ3和空气相对湿度临界值φ0的大小；若φ3＜φ0使送风口对第二间室送风，否则使送风口停止对第二间室送风。本发明的减少或避免门体间室内壁的凝露。

Description

冰箱及其控制方法 技术领域
本发明涉及冷藏冷冻技术领域，特别涉及一种冰箱及其控制方法。
背景技术
随着技术的进步和人们生活水平的提升，用户对于冰箱的要求越来越高。传统的仅设置冷藏室、冷冻室和变温室的冰箱已经不能满足用户对于存储空间多样化的需求。
近年来，冰箱领域出现了一种复合门体技术。众所周知，传统的冰箱门体用于开闭箱体的制冷间室，最多在冷藏门体的内衬处设置瓶座用于放置瓶装物。而复合门体的冰箱则对门体结构和功能进行改进，使门体包括主门和副门，主门用于开闭制冷间室。并且，主门限定出前侧敞开的门体间室，副门用于开闭门体间室。主门转动过程中，副门保持关闭状态。门体间室可供放置存储物，且取放时仅需打开副门，无需打开主门。不仅使操作更加方便快捷，而且避免频繁打开主门引起冷量过多损耗。
但是，复合门冰箱在运行过程中，门体间室的内壁常常出现凝露现象，影响了用户体验，阻碍了复合门技术的进一步发展。因此，如何减少或避免门体间室内壁凝露也成为本领域亟待解决的技术难题。
发明内容
本发明的目的在于至少解决现有技术存在的上述缺陷之一，提供一种冰箱及其控制方法。
本发明的目的是要减少或避免门体间室内壁的凝露。
本发明的进一步的目的是要避免因箱体间室温湿度波动对门体间室温湿度的不利影响。
一方面，本发明提供了一种冰箱的控制方法，冰箱包括前侧敞开以限定出第一间室的箱体和用于开闭第一间室的门体，门体包括主门和副门，主门用于开闭第一间室且限定有第二间室，副门用于开闭第二间室，主门后侧开设有用于将第一间室内的冷气引入第二间室的送风口，控制方法包括：
获取第一间室的空气绝对湿度ρ 1和第二间室的空气温度T 2；
根据空气绝对湿度ρ 1和空气温度T 2，计算第一间室空气在温度变化至 T 2时的预期相对湿度
Figure PCTCN2021115636-appb-000001
确定第二间室空气在第二间室内壁产生凝露的空气相对湿度临界值
Figure PCTCN2021115636-appb-000002
比较预期相对湿度
Figure PCTCN2021115636-appb-000003
和空气相对湿度临界值
Figure PCTCN2021115636-appb-000004
的大小；
若
Figure PCTCN2021115636-appb-000005
使送风口对第二间室送风，否则使送风口停止对第二间室送风。
可选地，控制方法还包括：
获取第二间室的内壁温度T 3；和
以内壁温度T 3作为露点温度，以空气温度T 2为环境温度，根据露点温度、环境温度和相对湿度三者的对应关系，计算空气相对湿度临界值
Figure PCTCN2021115636-appb-000006
可选地，获取第二间室的内壁温度T 3的步骤包括：检测第二间室的后壁温度，以其作为内壁温度T 3。
可选地，第二间室的后壁温度的检测点与送风口的距离小于等于第一预设距离。
可选地，空气温度T 2的检测点与送风口的距离小于等于第二预设距离。
可选地，控制方法还包括：
检测第一间室内的空气温度T 1和第一间室的空气相对湿度
Figure PCTCN2021115636-appb-000007
根据空气温度T 1和空气相对湿度
Figure PCTCN2021115636-appb-000008
计算空气绝对湿度ρ 1。
可选地，空气温度T 1和空气相对湿度
Figure PCTCN2021115636-appb-000009
的检测点与送风口的距离小于等于第三预设距离。
可选地，送风口处安装有风机；且控制方法中，若
Figure PCTCN2021115636-appb-000010
使送风口对第二间室送风，否则使送风口停止对第二间室送风的步骤包括：
若
Figure PCTCN2021115636-appb-000011
开启风机，以使送风口对第二间室送风；否则关闭风机，使送风口停止对第二间室送风。
另一方面，本发明还提供了一种冰箱，包括：
箱体，其前侧敞开以限定出第一间室；
门体，其包括主门和副门，主门用于开闭第一间室且限定有第二间室，副门用于开闭第二间室，主门后侧开设有用于将第一间室内的冷气引入第二间室的送风口；
控制器，其包括处理器和存储器，存储器存储有计算机程序，计算机程序被处理器执行时用于实现根据以上任一项的控制方法。
可选地，第一间室为冷藏室；且送风口设置在主门的后侧顶部，主门的 后侧底部还开设有用于使第二间室空气流向第一间室的回风口。
本发明的冰箱及其控制方法在一定程度上解决了复合门冰箱中，门体所限定的第二间室的内壁容易出现凝露的问题。具体地，发明人认识到，第二间室内壁容易产生凝露，一个重要原因是从箱体的第一间室引入了高湿空气。特别是当第一间室刚刚进行完开关门操作后，外界相对高湿和高温的空气进入了第一间室，如果再随即进入第二间室，很容易在第二间室内壁产生凝露。为此，本发明在将第一间室的冷气引入第二间室前，先计算第一间室空气在温度变化至第二间室的空气温度T 2时的预期相对湿度
Figure PCTCN2021115636-appb-000012
以及空气在第二间室内壁产生凝露的空气相对湿度临界值
Figure PCTCN2021115636-appb-000013
(第二间室内壁周围空气的相对湿度大于等于该空气相对湿度临界值
Figure PCTCN2021115636-appb-000014
时，必然会在内壁上产生凝露)，并对两者进行比较，只有满足
Figure PCTCN2021115636-appb-000015
的条件下，才使送风口对第二间室送风，否则使送风口停止对第二间室送风，以避免在第一间室刚进行完开关门或其他导致其内空气湿度升高的操作后，随即将第一间室内的冷气引入第二间室，导致第二间室内壁产生凝露的问题。并且，由于本发明可避免在第一间室进行完开关门操作后使外界高湿和高温气体进入第二间室，也就避免了因第一间室温度波动对第二间室温度和湿度的不利影响，使得第二间室的空气温湿度保持在较合理的水平。
特别地，本发明是在第一间室空气进入第二间室前，根据第一间室空气绝对湿度ρ 1和空气温度T 2，来预估假如第一间室空气进入第二间室后，温度变化至T 2时的预期相对湿度
Figure PCTCN2021115636-appb-000016
以确定其进入第一间室后是否会在第二间室内壁产生凝露。这种计算方式非常巧妙地实现了对凝露情况的预判，避免了凝露的产生。
进一步地，本发明的冰箱及其控制方法中，对第一间室空气温度T 1、空气相对湿度
Figure PCTCN2021115636-appb-000017
第二间室后壁温度的检测点、空气温度T 2的检测点与送风口的距离进行限定，使上述各检测点更加靠近送风口，以便对后期将最先进入送风口的气流进行针对性温湿度检测，以使对第一间室气流流入第二间室后是否会造成凝露的预判更加准确。
根据下文结合附图对本发明具体实施例的详细描述，本领域技术人员将会更加明了本发明的上述以及其他目的、优点和特征。
附图说明
后文将参照附图以示例性而非限制性的方式详细描述本发明的一些具体实施例。附图中相同的附图标记标示了相同或类似的部件或部分。本领域技术人员应该理解，这些附图未必是按比例绘制的。附图中：
图1是根据本发明一个实施例的冰箱的结构示意图；
图2是根据一个实施例的冰箱的示意性框图；
图3是根据本发明一个实施例的冰箱的控制方法的示意图；
图4是根据本发明一个实施例的冰箱的控制方法的流程图。
具体实施方式
图1是根据本发明一个实施例的冰箱的结构示意图。图2是根据一个实施例的冰箱的示意性框图。
本发明实施例提供了一种冰箱的控制方法。如图1和图2所示，冰箱包括箱体100、门体200和控制器700。
箱体100的前侧敞开以限定出第一间室101。门体200包括主门210和副门220，主门210用于开闭第一间室101且限定有第二间室201，副门220用于开闭第二间室201，主门210后侧开设有用于将第一间室101内的冷气引入第二间室201的送风口212。冷气进入第二间室201后，对第二间室201进行制冷。可使主门210在箱体100前侧可转动地安装于箱体100，主门210前侧敞开以限定出前述第二间室201，使副门220在主门210前侧可转动地安装于主门210。主门210打开时，用户从第一间室101存取物品。主门210关闭，副门220打开时，用户可从第二间室201存取物品。控制器700包括处理器720和存储器710，存储器710存储有计算机程序711，计算机程序711被处理器720执行时用于实现本发明实施例的冰箱的控制方法。
冰箱可通过蒸气压缩制冷循环系统、半导体制冷系统或其他方式进行制冷。根据制冷温度的不同，冰箱内部的各间室可划分为冷藏室、冷冻室和变温室。例如冷藏室内的温度一般控制在2℃至10℃之间，优先为4℃至7℃。冷冻室内的温度范围一般控制在-22℃至-14℃。变温室可在-18℃至8℃之间调节，以实现变温效果。不同种类的物品的最佳存储温度并不相同，适宜存放的储物间室也并不相同。例如果蔬类食物适宜存放于冷藏室，而肉类食物适宜存放于冷冻室。
在一些实施例中，前述的第一间室101为冷藏室。并且，可使送风口212 设置在主门210的后侧顶部，主门210的后侧底部还开设有用于使第二间室201空气流向第一间室101的回风口214，冷气从送风口212流入第二间室201后，因密度相对较大具有下沉作用，将向下流动并依次对第二间室201各高度区域进行制冷，空气温度逐渐升高后再从第二间室201底部的回风口214流回第一间室101。这样形成了更加通畅的风路循环，提升了第二间室201的制冷效果。可以理解的是，假如不设置回风口214，也可通过送风口212实现回风。
图3是根据本发明一个实施例的冰箱的控制方法的示意图。本发明实施例的冰箱的控制方法适用于本发明各实施例的冰箱。如图3所示，冰箱的控制方法包括：
步骤S302：获取第一间室101的空气绝对湿度ρ 1和第二间室201的空气温度T 2。
在步骤S302中，可通过直接方式测量第一间室101的空气绝对湿度ρ 1。但优选通过间接方式计算得到空气绝对湿度ρ 1，以获取更加精确的结果。具体地，可先检测第一间室101内的空气温度T 1和第一间室101的空气相对湿度
Figure PCTCN2021115636-appb-000018
根据空气温度T 1和空气相对湿度
Figure PCTCN2021115636-appb-000019
计算空气绝对湿度ρ 1。
步骤S304：根据空气绝对湿度ρ 1和空气温度T 2，计算第一间室101空气在温度变化至T 2时的预期相对湿度
Figure PCTCN2021115636-appb-000020
以及，确定第二间室201空气在第二间室201的内壁产生凝露的空气相对湿度临界值
Figure PCTCN2021115636-appb-000021
本领域技术人员可知，湿空气(含有水蒸气的空气)的绝对湿度是指单位体积湿空气中所含水蒸气的质量。在一定的气压和一定的温度的条件下、单位体积空气中能够含有的水蒸气存在上限，若该体积空气中所含水蒸气超过上限，即达到最大绝对湿度，将出现水蒸气凝结现象。而湿空气的相对湿度指的是湿空气在某一温度时的绝对湿度与相同温度下可能达到的最大绝对湿度之比，得数是一个百分比。由于温度越高，空气容纳水蒸气的能力越强，故湿空气绝对湿度不变的情况下，其相对湿度是要随温度的变化而变化。
故在步骤S304中，预期相对湿度
Figure PCTCN2021115636-appb-000022
就是指：假如第一间室101的绝对湿度为ρ 1的进风气流进入第二间室201后，与第二间室201的空气进行热交换，温度变化为与第二间室201空气温度相同(即T 2)时，进风气流最终的相对湿度值。而相对湿度临界值指的是：在空气温度为T 2时，能使空气在第二间室201内壁产生凝露的最小相对湿度，也就是使第二间室201内壁保 持不凝露状态的最大相对湿度。第二间室201内壁周围空气的相对湿度大于等于该空气相对湿度临界值
Figure PCTCN2021115636-appb-000023
时，将会在内壁上产生凝露。
步骤S306：比较预期相对湿度
Figure PCTCN2021115636-appb-000024
和空气相对湿度临界值
Figure PCTCN2021115636-appb-000025
的大小。
步骤S308：若
Figure PCTCN2021115636-appb-000026
使送风口212对第二间室201送风，否则使送风口212停止对第二间室201送风。
优选使送风口212处安装有风机230，在步骤S308中，若
Figure PCTCN2021115636-appb-000027
开启风机230，以使送风口212对第二间室201送风；否则关闭风机230，使送风口212停止对第二间室201送风。在一些替代性实施例中，也可在送风口212处设置风门，通过控制风门的开闭来启动或停止对第二间室201的送风。或者，同时设置风机230和风门，控制风机230和风门同时开启或关闭，以对送风口212的送风状态进行更加精确地控制。
本发明实施例的上述步骤是循环进行的，也就是说，在使送风口212开启送风或者停止送风之后，需要重新执行步骤S302～S308，以便根据第一间室101和第二间室201的温湿度的变化尽快调整送风口212的开关状态。
本发明实施例的控制方法在一定程度上解决了复合门冰箱中，门体200所限定的第二间室201的内壁容易出现凝露的问题。具体地，发明人认识到，第二间室201内壁容易产生凝露，重要原因是从箱体100的第一间室101引入了高湿空气。特别是当第一间室101刚刚进行完开关门操作后，外界相对高湿和高温的空气进入了第一间室101，随即进入第二间室201后，更容易在第二间室201内壁产生凝露。为此，本发明在将第一间室101的冷气引入第二间室201前，先计算第一间室101空气在温度变化至第二间室201的空气温度T 2时的预期相对湿度
Figure PCTCN2021115636-appb-000028
以及空气在第二间室201内壁产生凝露的空气相对湿度临界值
Figure PCTCN2021115636-appb-000029
并对两者进行比较，只有满足
Figure PCTCN2021115636-appb-000030
的条件下，才使送风口212对第二间室201送风，否则使送风口212停止对第二间室201送风，以避免在第一间室101刚进行完开关门或其他导致其内空气湿度升高的操作后，随即将第一间室101内的冷气引入第二间室201，导致第二间室201内壁产生凝露。由于本发明可避免在第一间室101进行完开关门操作后使外界高湿和高温气体进入第二间室201，也就避免了因第一间室101的温度波动对第二间室201的温度和湿度的不利影响，使得第二间室201的空气温湿度保持在较合理的水平。
特别地，本发明实施例是在第一间室101空气进入第二间室201前，根 据第一间室101空气绝对湿度ρ 1和空气温度T 2，来预估假如第一间室101空气进入第二间室201后，温度变化至T 2时的预期相对湿度
Figure PCTCN2021115636-appb-000031
以确定其进入第一间室101后是否会在第二间室201内壁产生凝露。这种计算方式非常巧妙地实现了对凝露情况的预判，避免了凝露的产生。
在一些可选实施例中，可以通过对上述步骤的进一步优化和配置使得冰箱实现更高的技术效果，以下结合对本实施例的一个可选执行流程的介绍对本实施例的冰箱的控制方法进行详细说明，该实施例仅为对执行流程的举例说明，在具体实施时，可以根据具体实施需求，对部分步骤的执行顺序、运行条件进行修改。
图4是根据本发明一个实施例的冰箱的控制方法的流程图。如图4所示，冰箱的控制方法可包括以下步骤：
步骤S402：检测第一间室101内的空气温度T 1、第一间室101的空气相对湿度
Figure PCTCN2021115636-appb-000032
和第二间室201的空气温度T 2和第二间室201的内壁温度T 3。
在该步骤中，如图1和图2所示，可利用第一温度传感器300来检测第一间室101内的空气温度T 1，利用相对湿度传感器400来检测第一间室101的空气相对湿度
Figure PCTCN2021115636-appb-000033
利用第二温度传感器500来检测第二间室201的空气温度T 2，利用第三温度传感器600来检测第二间室201的内壁温度T 3。第一温度传感器300、相对湿度传感器400、第二温度传感器500和第三温度传感器600均与控制器700连接，以便将检测信号传递给控制器700。
在该步骤中，检测第二间室201的后壁211的温度，以其作为内壁温度T 3。发明人认识到，由于第二间室201的后壁211临近第一间室101，与第一间室101内的空气可通过热传导进行传热，故该后壁211的温度相比第二间室201的其壁面的温度要更低，更容易产生凝露。只需保证后壁211不凝露，基本可保证其他壁面不凝露。故本实施例仅检测后壁温度，以更好地实现防凝露的目的。
步骤S404：根据第一间室101内的空气温度T 1和第一间室101的空气相对湿度
Figure PCTCN2021115636-appb-000034
计算第一间室101的空气绝对湿度ρ 1。通过空气温度和相对湿度计算绝对湿度的具体计算方式是本领域技术人员都知晓的，属于制冷领域常用的基础知识，具体可通过公式计算出或者通过查表获得，在此无需赘述。
步骤S406：根据空气绝对湿度ρ 1和空气温度T 2，计算第一间室101空气在温度变化至T 2时的预期相对湿度
Figure PCTCN2021115636-appb-000035
步骤S408：以第二间室201的内壁温度T 3作为露点温度，以空气温度T 2为环境温度，根据露点温度、环境温度和相对湿度三者的对应关系，计算空气相对湿度临界值
Figure PCTCN2021115636-appb-000036
具体地，“露点温度、环境温度和相对湿度三者的对应关系”是本领域技术人员都知晓的，属于制冷领域常用的基础知识，具体包括计算公式和关系表，在此无需赘述。步骤S404和步骤S408都是步骤S402之后的步骤，但本实施例不限定步骤S404和步骤S408之间的执行顺序。
步骤S410：判断
Figure PCTCN2021115636-appb-000037
是否成立。若是，执行步骤S412；若否，执行步骤S414。
步骤S412：开启风机230。开启风机230的目的在于使送风口212对第二间室201送风。
步骤S414：关闭风机230。关闭风机230的目的在于使送风口212停止对第二间室201送风。
本发明实施例的上述步骤是循环进行的。也就是说，在执行完步骤S412或步骤S414后，继续重新执行步骤S402，形成循环。以便根据第一间室101和第二间室201的温湿度的变化尽快调整送风口212的开关状态。
在上述步骤中，优选使第二间室201的后壁温度的检测点与送风口212的距离小于等于第一预设距离，也就是使第二温度传感器500与送风口212的距离(指的是与送风口212最接近的下边缘处)小于等于第一预设距离。优选使空气温度T 2的检测点与送风口212的距离小于等于第二预设距离，也就是使第三温度传感器600与送风口212的距离小于等于第二预设距离。优选使空气温度T 1和空气相对湿度
Figure PCTCN2021115636-appb-000038
的检测点与送风口212的距离小于等于第三预设距离，也就是使第一温度传感器300和相对湿度传感器400与送风口212的距离小于等于第三预设距离。第一预设距离、第二预设距离和第三预设距离可为10～20cm之间的相同或不同数值。本实施例对第一间室101的空气温度T 1、空气相对湿度
Figure PCTCN2021115636-appb-000039
第二间室201后壁温度的检测点、空气温度T 2的检测点与送风口212的距离进行限定，目的是使上述各检测点更加靠近送风口212，以便对后期将最先进入送风口212的气流进行针对性地温湿度检测，以使对第一间室101气流流入第二间室201后是否会造成凝露的预判更加准确。
至此，本领域技术人员应认识到，虽然本文已详尽示出和描述了本发明 的多个示例性实施例，但是，在不脱离本发明精神和范围的情况下，仍可根据本发明公开的内容直接确定或推导出符合本发明原理的许多其他变型或修改。因此，本发明的范围应被理解和认定为覆盖了所有这些其他变型或修改。

Claims (10)

  1. 一种冰箱的控制方法，所述冰箱包括前侧敞开以限定出第一间室的箱体和用于开闭所述第一间室的门体，所述门体包括主门和副门，所述主门用于开闭所述第一间室且限定有第二间室，所述副门用于开闭所述第二间室，所述主门后侧开设有用于将所述第一间室内的冷气引入所述第二间室的送风口，所述控制方法包括：
    获取所述第一间室的空气绝对湿度ρ 1和所述第二间室的空气温度T 2；
    根据所述空气绝对湿度ρ 1和所述空气温度T 2，计算所述第一间室空气在温度变化至T 2时的预期相对湿度
    Figure PCTCN2021115636-appb-100001
    确定所述第二间室空气在所述第二间室内壁产生凝露的空气相对湿度临界值
    Figure PCTCN2021115636-appb-100002
    比较所述预期相对湿度
    Figure PCTCN2021115636-appb-100003
    和所述空气相对湿度临界值
    Figure PCTCN2021115636-appb-100004
    的大小；
    若
    Figure PCTCN2021115636-appb-100005
    使所述送风口对所述第二间室送风，否则使所述送风口停止对所述第二间室送风。
  2. 根据权利要求1所述的控制方法，还包括：
    获取所述第二间室的内壁温度T 3；和
    以所述内壁温度T 3作为露点温度，以所述空气温度T 2为环境温度，根据露点温度、环境温度和相对湿度三者的对应关系，计算所述空气相对湿度临界值
    Figure PCTCN2021115636-appb-100006
  3. 根据权利要求2所述的控制方法，其中获取所述第二间室的内壁温度T 3的步骤包括：
    检测所述第二间室后壁的温度，以其作为所述内壁温度T 3。
  4. 根据权利要求3所述的控制方法，其中
    所述第二间室的后壁温度检测点与所述送风口的距离小于等于第一预设距离。
  5. 根据权利要求2所述的控制方法，其中
    所述空气温度T 2的检测点与所述送风口的距离小于等于第二预设距离。
  6. 根据权利要求1所述的控制方法，还包括：
    检测所述第一间室内的空气温度T 1和所述第一间室的空气相对湿度
    Figure PCTCN2021115636-appb-100007
    根据所述空气温度T 1和所述空气相对湿度
    Figure PCTCN2021115636-appb-100008
    计算所述空气绝对湿度ρ 1。
  7. 根据权利要求6所述的控制方法，其中
    所述空气温度T 1和所述空气相对湿度
    Figure PCTCN2021115636-appb-100009
    的检测点与所述送风口的距离小于等于第三预设距离。
  8. 根据权利要求1所述的控制方法，其中
    所述送风口处安装有风机；且所述控制方法中，若
    Figure PCTCN2021115636-appb-100010
    使所述送风口对所述第二间室送风，否则使所述送风口停止对所述第二间室送风的步骤包括：
    若
    Figure PCTCN2021115636-appb-100011
    开启所述风机，以使所述送风口对所述第二间室送风；否则关闭所述风机，使所述送风口停止对所述第二间室送风。
  9. 一种冰箱，包括：
    箱体，其前侧敞开以限定出第一间室；
    门体，其包括主门和副门，所述主门用于开闭所述第一间室且限定有第二间室，所述副门用于开闭所述第二间室，所述主门后侧开设有用于将所述第一间室内的冷气引入所述第二间室的送风口；
    控制器，其包括处理器和存储器，所述存储器存储有计算机程序，所述计算机程序被所述处理器执行时用于实现根据权利要求1至8中任一项所述的控制方法。
  10. 根据权利要求9所述的冰箱，其中
    所述第一间室为冷藏室；且
    所述送风口设置在所述主门的后侧顶部，所述主门的后侧底部还开设有用于使所述第二间室空气流向所述第一间室的回风口。
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