JPH02193254A - character processing device - Google Patents

Abstract

PURPOSE:To improve universality by moving an element piece constituting an area and displaying inputted characters so that they are within the area prescribed by area data changed by the movement. CONSTITUTION:When a keyboard KB is operated, the interrupt signal generated from the keyboard KB is transmitted to a microprocessor CPU, and then, control procedures in a control memory ROM are called through the microprocessor CPU and each control is performed in accordance with control procedures. An element piece constituting an area is moved, and inputted characters are so displayed that they are within the area prescribed by area data changed by the movement. Thus, the universality is improved.

Description

[Detailed Description of the Invention] [Industrial Application Field] The present invention allows control characters to be input by the same input operation as normal characters, and input characters within an area defined by the control characters. The present invention relates to a character processing device that can display characters in a manner that fits within the .

[Conventional technology]

Conventionally, the editing area in this type of character processing device has been set in advance, or has been set by an operation other than character input, such as a light pen.

[Problem that the invention seeks to solve]

However, in the above-mentioned conventional technology, the area is fixedly set in advance, or it is necessary to set the area necessary for character input and document editing by an operation other than character input, such as a light pen.

[Means for solving problems]

In order to solve this problem, the present invention provides a means for inputting control characters by the same input operation as ordinary characters, and displaying the input characters so that they fit within an area defined by the control characters. Be prepared.

〔Example〕

Embodiments of the present invention will be described below with reference to the drawings.

The present invention relates to a character processing device that edits data so that the beginning and end of lines of data are aligned.

FIG. 1 is a functional block diagram showing an embodiment of a character processing device according to the present invention. In the figure, KBI is a keyboard, which is composed of, for example, a JIS keyboard, a full Kanji keyboard, a Bentouch input board, etc., and has character keys CK.

KB2 is a keyboard equipped with function keys as shown in FIG. To explain the same figure, DEL
is the delete key that deletes input data.OW is the override key that writes new data on top of the input data.INS is the insert key that writes new data between input data.CAR is the key that moves the cursor.INDI~ IND3 is an indent key for inputting an indent, and WK is a blank key for inputting a blank signal.

KB3 is a keyboard having a print key PRT for issuing print instructions.

The CCPU has an editing processing section that edits data in response to key signals from the keyboards KBI to 3 and outputs the edited data.

Bufl and Buf2 are memories in which data is stored.

CR is a cursor register in which cursor data is stored.

SC is a selector that selects one of the memories Bull I3uf2 according to instructions from the editing processing unit CCPU.

DC is a display control circuit that controls the memory Buf1.C selected by the selector SC. The contents of one of Buf2 and the contents of cursor register CR are controlled and output to CRT device DP.

The PC is a print control circuit that prints the contents of the memory Buf1 or Buf2 selected by the selector SC.

FIG. 3 shows specific configurations of each of the configurations shown in FIGS. 1 and 2. In this figure, the same reference numerals as those shown in FIGS. 1 and 2 are designated by the same reference numerals.

The editing processing unit CCPU consists of three elements as shown in FIG.

The CPU is a microprocessor that performs calculations, logical judgments, etc.

The ROM is a control memory that stores various processing procedures, control procedures shown in the figures, Kanji information, etc.

FIG. 4A shows storage of the control means.

RAM is a random access memory used for temporary storage of various data. Figure 4B shows its main parts. FIG. 5B shows the structure of the indent registers INDR1 and INDR2. AB is an address bus that transfers a signal indicating a control target. DB is a data bus that transfers various data and is bidirectional. CB is a control bus that applies control signals to various control objects.

The memories Bufl and Buf2 have contents of <22 lines x 22 columns (484 words) as shown in FIG. 5A.

The operation of the embodiment constructed as described above will now be described in detail.

This character processing device is activated by operating the keyboard KB. When keyboard KB is operated,
An included signal generated from the keyboard KB is transmitted to the microprocessor CPU, thereby calling up a control procedure in the control memory ROM via the microprocessor CPU, and performing each control according to the control procedure.

First, when the power is turned on, the initialization routine Ml of step 1 in FIG. 9 is performed. The details are in Chapter 10.
As shown in the figure. First, the microprocessor CPU has memory Bu
Clear the contents of fl (step II), memory Euf2
Clear the contents of (step 12).

Subsequently, it sets 1 to the buffer select register BSR.
, and then causes the selector SC to select the contents of the memory Bufl (step 15). Next, the microprocessor CPU sets the override flag OWF to "1".
and set the indent register INDRI.

Enter the value 22 in 2 (22 x 3 x 2W) (
Step 17). By performing the above processing, the initialization routine is completed.

Next, the character processing device enters a key wait state and waits for any key operation on the keyboards KBI to KB2 (step M2). Figure 9 shows the outline.

In steps M3 to MIO, the microprocessor CPU determines that the operated keys are cursor keys C and AR.

Indent keys INDI to IND3, blank key WK, insert key INS, automatic light key OW, DE】)
- The number of the key DEL and the character key CK is determined one after another, and if none of the keys is selected, the input data is discarded (step M10).

If any key is operated (′!,,
At each decision point, the cursor routine step M
11), Indent Routine (Step M12), Blank Paper Key Routine (Step M14L Insert Routine (Step M15), Auto Write Routine (Step M16), Delete Routine (Step M17),
The process moves to the character routine (step M18).

As shown in Figure 6a of Kinshi 6, if you write this one sentence from the 6th column to the 10th column and write other sentences from the 12th column to the 14th column, write the information as follows.

First, the cursor key CAR is operated. The operation of the cursor key 〇AR is half-11g++ at step M3 in Fig. 9, and the process moves to the cursor routine Mll. cursor key CA
When R is operated, the microprocessor CPU increments the register X of the cursor register CR by one ink and one noment (step Cl).

Next, the microprocessor CPU registers the cursor register CR.
Determine whether the content of X is 22 or more (Step C2)
. In this case, the cursor is X. Since the process starts with -0, Y, 20, and A, the above determination becomes NO and the process returns to the key 1 routine.

As described above, operate the cursor key CAR to move the cursor to the fifth column.

Next, operate the indent key INDI to input an indent signal. Processing 11 for such a key is performed as follows. Operation of the relevant key is determined at step M4 in FIG. 9, and A-D in FIG. 12! The processing of this indentation routine is performed by the microprocessor CPU.

The contents of the buffer select register BSC are determined and free memory and free indent registers are searched. "Vacant'
is an unused memory or an unused register. In the initial state (tl), the content of the buffer select register BSR is 1marlJ, so
Memory Buf2 as free memory Buf, indent register INDR as free indent register INDR
2 (Step II).

Next, the contents of the current memory Buf (excluding blank codes) from the line indicated by the cursor register CR to the E line (described later) or the last line (22nd line) are stored in the memory RAM according to the partitions by each indent. Move to WOI, WO2, WO3, WO4.

At that time, memory WOIL, W12L, W23L, W34L
The memories WOI, W12, . Set the data length of W23 and W34.

Next, free memory Buf, free indent register, IN
The contents of the current memory Buf (memory Bufl) and the current indent register INDR (indent register INDRI) are moved to DR up to the line indicated by the cursor register CR. In this case, since the cursor is on line 0, there is no content to be moved (step I3).

Free memory Bu from the line indicated by the cursor register CR to the E line or the last line regarding the next indentation change instruction.
Write the indentation code at the indicated position of f2.

The address is also written into the empty indent register INDR2. Here, an indent code ◇ is written in the fifth column of the memory Buf2 and 5 is written into the indent register INDR2 (step I4).

Next, regarding the indentation that has not been changed, the current memory Buf is stored in the free memory Buf (memory Buf2) from the line indicated by the cursor register CR to the E line or the last line.
Write the indent code at the same position as (memory Bufl). Also, the same indent address as the current indent register INDRI is stored in the empty indent register INDR2 (step 15).

Since there was no indentation code in current memory initially, the contents of free memory do not change in this step.

Next, the microprocessor CPU determines whether the last marching indentation address has been written in the free indentation register INDR2, and if No, performs control to input the indentation address in step F, and moves to step I8. Y
If it is ES, the process moves directly to step I8.

The microprocessor CPU has memory WOI, W12°W23. Check the contents of W34 and check if there is data (
Step I8). Since the answer is now NO, the process moves to step 112.

In step 112, the microprocessor CPU determines whether there is any remaining memory that has been moved to the free memory (memory Buf2) from the current memory (memory Bufl). In this case, the answer is No, and the process moves to step 116. In order to clear the contents of the current memory (memory Bufl) and the current intention register (register INDRI), the microprocessor CPU puts a NULL code in the current memory and 22 in one of them.

Next, the microprocessor CPU changes the contents of the buffer select register BSR from l to 2. In this process, when the content of the buffer select register BSH is 2', the microprocessor CPU enters "work" into it (step 117).

Next, the microprocessor CPU switches the selector SC according to the contents of the buffer select register BSH (
Step 118). The current memory becomes memory Buf2 and the current indent register becomes INDR2.

When the above processing is completed, the system returns to the key wait state.

Next, a second indent code is input to determine the end of the sentence with the first indent at the beginning. First, the cursor key CAR is operated again. When the cursor key CAR is operated, the contents of X in the cursor register are again incremented by +1 for each operation as described above. The content of X is 1
1, when the indent key IND2 is operated in the same way as when inputting the first indent described above, the second indent code ◇ is stored in the free memory (memory Eufl) and the free memory is Indent register (
The address is stored in register INDR1). Also, the indent code ◇ of the first indent of the current memory (memory Buf2) and the indent address of the current indent register (register INDR2) are moved to a free memory and a free indent register. Then, the content of the buffer selector register BSR changes from "2" to "1".

Similarly to the above, the cursor key CAR is operated to make the second indent the beginning of the sentence and the third indent the end of the sentence.
As shown in the diagram, until X months 5, and indent key I
When NP3 is operated, free memory (memory Buf2)
The indent code ◇ is stored in the empty indent register (register ■NDR2), 15 is stored in the empty indent register (register NDR2), and the contents of the current memory (memory Buffl) and the contents of the current intent register INDRI are stored in the empty memory (memory Bu
ff2) Free indent register (register INDR2)
). Furthermore, the buffer select register BSR
The content of changes from l to 2.

When the above-mentioned processing is completed, the machine waits for a key again.

First, operate the cursor key CAR to move the cursor to the 6th column of the 1st row.

Next, when the character key CK is operated, it is determined in step M9 of FIG. 9 that the character key CK has been operated, and the character routine of step M18 is entered. The details are shown in FIG. 17A.

First, it is checked whether the override flag OWF is 1 or not.

In this case, it is set to "1" when setting the initial state, so
Move to step C2. Buffer select register BSR
Find the current memory by.

Next, in step C3, it is checked whether the content of the cursor register CR in the current memory (memory Buff2) is the location where the indentation code exists.

In this case, if the answer is NO, the process moves to step C4, and the input character code is written in the memory location corresponding to (x-y) of the cursor register CR.

Next, the process moves to step C5, and the indent delimitation range (X1, X2) of the line indicated by the cursor is determined by referring to the current indent register INDR2.

Next, the contents of X in the cursor register CR are incremented (step C6).

Next, the contents of x2 obtained from the indent register INDR2 are compared with the value of X in the cursor register CR (step C7).

In this case, since X<X2, the result is No, and key wait control is performed.

Characters up to the ninth column of the row can be entered in the same manner as described above.

A key operation is performed to enter the character in the 10th column, that is, the character to the left of the second intent code.

Steps CI, C2, C3, C4, C5, and C6 are performed in the same manner as described above.

Next, in step C7, the microprocessor CPU checks whether the contents of X in the cursor register CR are equal to x2. In step C6, the content of X is the second intent code
Since the value is the same as the address, the answer is YES, and the process moves to step C8, where the value of Y in the cursor register CR is incremented by +1. Next, it is checked whether the value of Y in the cursor register CR is 22 or more, and since it is No, the process moves to the next step CIO. In step C10, the range separated by indentation of the line indicated by the cursor (Xl
, X2) by referring to the current indent register INDR2.

Next, set the value of X in the cursor register CR to X, +1.

That is, the cursor is moved to the second row, sixth column.

Therefore, characters can be arranged one after another between the indentation dates ◇ and .

Therefore, when the cursor is next placed in the first row, column 12, the character a, shown in lower case in FIG. 6a.

It will be understood from the above description that b, c, . . . are arranged between the second indent and the third indent.

The process when the second indentation of the current memory (memory Buff2) shown in FIG. 6a is moved from the 11th column to the 9th column will be described.

The cursor key CAR is operated to move the cursor to the 0th row, 9th column.

Next, when the indent key IND2 is operated, it is determined in step M4 of FIG. 9 that it is an indent key.
The indent routine starting from A in FIG. 12 is controlled.

First, in step 1, buffer select register BSH
Search for free memory (memory Buffl) and free indent register INDPI according to the contents of . Next, from the line indicated by the cursor register CR, the contents (excluding the blank code) of the current memory (memory Buffl) of the E line or the last line (here, the last line) are transferred to the memory WOI, W12°W23. Move to W34. At that time, the length of the data in the memory above is set as the memory WOIL.
, W12L, W23L, W34L.

Next, in step 3, the contents of the current memory Buffl and the current indent register INDPI up to the line indicated by the cursor register CR are transferred.

Next, regarding the indentation that has been instructed to be changed, an indentation code is written at the specified position in the free memory (memory Euf2) from the line indicated by the cursor register CR to the E line or the last line (in this case, the last line). The designated address is also written into a vacant indent register (indent register INDR2) (step 14).

Regarding the indentation that has not been instructed to change, an indentation code is written in the free memory Buf2 from the line indicated by the cursor register CR to the E line or the last line at the same position as the current memory Bufl. Also, empty indent register INDR
2, write the same indent address as the current indent register INDRI.

After all indent data has been written into the empty indent register INDR2, step 16. After completing I7, in step 8, the memory WOI, W12. W23
Check whether there is data in W34.

In this case, the answer is YES, and in step I9, the memory WO
I, W12. W23. The data saved in W34 is written to the free memory Buf2 according to the delimiter data stored in the free indent register INDR2.

Such control is shown in detail in Figure 12. This processing memory WOI, W12. W23. This is done sequentially for each W34.

In this case, data A, B, C, D, E, F・i1100B between the boundaries ◇ and ◇ shown in Figure 6 A
They are arranged between the partitions Φ and sama shown in .

First, in step l801, the length of the memory W12 is determined.

It is determined that this is not the case, and the XY values of the cursor register CR are saved (step 1802). The range separated by the indentation of the line where the cursor is located (X,.

X2) is obtained by referring to the free indent register INDR2. Here, X1=5, X2-9 then X1+2≦X2
Find out if it is. Since YES, step l805
Move to. Enter X=X and +1 in the cursor register. The data in the memory W12 is moved to the position of the free memory Buf2 indicated by the cursor (step 1806).

Next, the length is decremented by one. Step l808
Check to see if the length is less than 0, and if No, set X=X+1 in cursor register CR.

Next, check whether X≧X2 and if No, step ■
Returning to 806, the contents of the memory WI2 are further transferred to the free memory Buf2. If the value of X becomes X2, that is, 9, the value of Y in the cursor register CR is incremented by +1, and the value of X becomes X1+1 again, and data transfer control is performed again as described above.

The above control is performed by memory WOI, W12. W23
゜Do this for W34.

After completing the above processing, restore the saved XY values of the cursor register CR, move to step 110 in FIG. 12B, and write "E" in the first column of the last row to be written.
Memorize the mark. The loose E mark becomes a partition in the row direction, and the data up to the E mark is treated as one data and processed as described below. In step 111, line E is checked to see if it is the last line of free memory. If YES, step 11
6, and step 116. 117. 118 and wait for the key, if NO in step 111, step 112.116.117°118 or 112.11
3. Proceed to step 114, check whether there is any more free space in the free memory (memory Buf2), and if No here, proceed to steps 114, 116, 117, and 118 to wait for the key, and if YES in step 114 , in step 115, the free memory Buf2 blank code (NVLL
) is written to the corresponding free indent register INDR.
2 is written to 2 and the process goes through steps 116 to 11g to wait for a key.

Align the beginning and end of a line in one sentence as described above. In addition, the data saved in the memory W23 is transferred to the free memory Buf2.
The control for writing to is also performed by the control in the twelfth diagram. Therefore, the data arrangement shown in FIG. 6a is changed to the arrangement shown in FIG. 6s.

In FIG. 7a, data is divided into four stages by key operations as described above, and data is arranged at different indentations for each stage.

Change the position of the first indentation in the second row of the younger brother 6 a from 5 → lO
We will explain the process when changing to .

First, the cursor is moved to the 10th column of the 6th row. Next, when the indent key INDI is operated, the data from the line indicated by the cursor to line E is transferred to the memory WOI, W12. W23. Transferred to W34. Next, the data before the line indicated by the cursor is transferred as is to the free memory and free indent register. Therefore, Figure 6a
The data in the first row appears as is in the first row of FIG. In the second stage, the arrangement is changed as described above.

The data for the third and fourth stages are determined in the next step 112 following step IIO in which the transfer of the third stage data is completed. First, if there are contents of the current memory, the answer is YES in step 112, and in step 113, the contents of the current memory are transferred to a free memory. After that, processing is performed as described above. It is also clear from the above description that the indentation should be arranged as shown in FIG.

Next, if you want to delete part of the input data that has been arranged, move the cursor to the position you want to delete.

Next, when the delete key DEL is operated, the process moves to step D1 shown in FIG. 16 after confirming the delete key DEL, and searches for free memory and free indent registers. The current contents (excluding blank code) from the line indicated by the cursor register CR to the E line or the last line are stored in the memory WOI, W12. W23.
WS2: Move. At that time, WOIL.

Store the respective lengths in W12L, W23L, and W34L (however, blank code (NULL) is not included).

Next, as shown in FIG. 16B, the character indicated by the current cursor register is deleted from the memory WOI-W34.

Transfers the contents of the current memory and current indent register up to the line indicated by the current cursor to the free memory and free indent register. An indent code is written in the free memory from the line indicated by the current cursor to line E or the last line at the same position as the current memory. Also, write the same indent address as the current indent register into a vacant indent register.

Next, the process moves to step 6 shown in FIG. 12A, and the subsequent processing is performed as described above.

Next, the process for inserting characters will be described.

First, when the insert key INS is operated, the key operation of the insert key INS is determined in step M6 shown in FIG. 9, and the insert routine of step M15 is controlled. As shown in Figure 14 (override flag OWF
It resets and waits for the key.

To set the override flag OWF, when the override key OW is operated, the override flag OWF is set as shown in FIG.

After resetting the override flag OWF as described above, move the cursor to the location where you want to insert a character using the cursor key CAR.

Next, when the character key is operated, in step C1 of FIG. 17A, it is determined whether the override flag is 1, which becomes No, and the control shown in FIG. 17B is performed.

First, in step C12, the buffer select register BSH is
Examine the contents of and look for free memory and free indentation registers. Next, the contents of the current memory from the line indicated by the cursor register to line E or the last line (excluding blank code)
The memory WOI, W according to the partition by each indentation
12. W23. Move to W34. At that time, memory WOIL,
W12L, W23L.

Store each length in W34L (however, if the white paper
(Do not include NULL).

Insert the character indicated by the current cursor register onto the memory W1 (FIG. 20).

Transfers the contents of the current memory and current indent register up to the line indicated by the current cursor to the free memory and free indent register.

Write an indent code at the same position as the current one in the empty space from the line indicated by the cursor to line E or the last line. Again, write the same as the current one in the blank space.

Next, the process moves to step 6 shown for the 12th prisoner, and the same operation as described above is performed.

FIG. 22 shows an example of realizing a reduction in the number of indentation keys in the above embodiment. Shown in FIG. 22 are an indent key IND12, a memory Buf, and an indent register INDR. In this example, indent register I
Although the internal structure of the NDR is divided into three parts, they do not have a one-to-one correspondence with the keys as in the previous embodiment.

FIG. 21 shows the control procedure when the indent key and indent register INDR are configured as described above.
It can be inserted into a part of step 4 of FIG. 12A. First, when the first indent key INDI is operated when no indent code is written in the memory Buf, the number of indent codes on the left side is determined based on the contents of the cursor register CR (step Kl).

Next, does the indentation code immediately to the left of the position indicated by the cursor register correspond to the indentation key that was pressed? Find out. If No, the indentation that has been instructed to be changed is written to a predetermined location in the indentation register INDR as the N+1st indentation. In this example, up to three indented data can be written on one line. If Y
If it is ES, the indentation that is instructed to be changed is the Nth indentation.

Therefore, write the indentation address to the indentation register as the Nth indentation.

〔effect〕

As described above, according to the present invention, control characters can be input using the same input operation as normal characters, and the input characters can be displayed so as to fit within the area defined by the control characters. It became possible to provide a character processing device.

[Brief explanation of the drawing]

FIG. 1 is a block diagram showing one embodiment of the present invention, and FIG.
The figure is a detailed diagram of the keyboard KB2 shown in FIG. 1, FIG. 3 is a specific circuit diagram of the block diagram shown in FIG. 1, FIG. 4A is an explanatory diagram of the control memory ROM shown in FIG. 3, and FIG. B is the third
An explanatory diagram of the memory RAM shown in the figure, FIG. 5A is the memory Bu
fl, a diagram showing the configuration of BaF2, FIG. 5B is an explanatory diagram of the configuration of indent register INDI, IND2, FIG. 6A
is an explanatory diagram of the state of memory Bufl (or BaF2) and indent register INI)l (or IND2),
FIG. 6B shows memory Buf2. Bu41 and indent register IND2. A state explanatory diagram of INDI, Figure 7A shows memories Bufl, Buf2 and indent register INDI.
, IND2, and FIG. 7B is a state explanatory diagram of the memory Buf2.
Bufl and indent register IND2゜INDI
Fig. 8 is a state explanatory diagram of memory Buff, BaF2 and indent register INDI, IND2,
Figures 9 to 11 are diagrams showing control procedures, Figures 13 to 1
FIG. 8 is a diagram showing the control procedure, FIGS. 19 and 20 are diagrams showing data arrangement, FIG. 21 is a diagram showing the control procedure, and FIG. 22 is a diagram explaining the control. INDI, IND2...Indent register,
■ND1~3・・・Indent key

Claims (1)

[Scope of Claims] Input means for inputting characters and control characters defining an area; storage means for storing the characters and the control characters inputted from the input means; a cursor on the display means that indicates a display position of a character to be newly inputted from the input means; moving a cursor along a line, if said cursor exceeds the area defined by said control character input by said input means;
cursor control means for moving the cursor to the beginning of the next line within the area; A character processing device characterized by displaying a character.