JPH0926858A - Data storage method and device - Google Patents

Abstract

PROBLEM TO BE SOLVED: To uniformalize readout speed by dividing write data into prescribed pieces of data when the data is written, allocating and writing divided data on a rotary storage means, respectively, and reading out the divided data from the rotary storage means, respectively and restoring the data to the one when it is written when the data is read out. SOLUTION: A control circuit 106 divides the write data into the one of prescribed length when the data from an external device 20 is written, and performs the write of the data divided by the pieces of data corresponding to respective data write speed in areas in which the areas of an optical disk device 102 and an optical device 104 are divided into plural areas advancing from an inner periphery to an outer periphery. Also, when the data is read out, the data is read out stored by dividing in the optical device 102 and the optical device 104 are read out, and the data when it is written is restored from read out divided data. In this way, write or readout rate is uniformalized.

Description

Detailed Description of the Invention

[0001]

BACKGROUND OF THE INVENTION 1. Field of the Invention The present invention relates to a rotary memory device, such as an optical disk device, for writing and reading data at a constant angular velocity. Hereinafter, the rotary storage device will be described as an optical disc, but the present invention is not limited to this.

[0002]

2. Description of the Related Art Currently used optical disk devices read and write data at a constant angular velocity, and there is a considerable difference in data reading and writing speed between the inner circumference and the outer circumference. For example, Matsushita Electric Industrial Co., Ltd. optical disk device LF
-7300J has an inner circumference of 0.78MB / sec and an outer circumference of 1.56MB / sec.

[0003]

If a plurality of optical disk devices are connected in parallel and the parallel reading method is directly adapted to the physical positional relationship of the inner circumference and the outer circumference,
The speed difference between the inner circumference and the outer circumference is increasing. For example, when reading and writing data in parallel with two units, about 3 MByte /
The speed is about 1.5 MByte / sec near the inner circumference. It is impossible for such a conventional device to read and write data at a constant speed.

In view of the above problems, the present invention provides a data storage device using an optical disk for the purpose of averaging the read speeds when a plurality of optical disk devices are used.

[0005]

In order to solve the above problems, a storage device of the present invention comprises a plurality of rotary type storage devices that perform a constant angular velocity when writing and reading data, and a plurality of rotary type storage devices. A rotary type that divides the area into multiple areas corresponding to the writing and reading speeds from the inner circumference to the outer circumference, divides the write data into a fixed number when writing data, and writes the data to the outer circumference area where the writing speed is high. Allocate a large number to the memory device, and write a small number to the rotary memory device that writes data to the inner area where the writing speed is slow. At the same time, data is written from each rotary memory device, and at the time of reading, data is read from the corresponding positions of the plurality of rotary memory devices. Those having a data storage apparatus characterized by comprising a control circuit for reading stitched read them at the same time.

[0006]

In the above structure, the areas of the plurality of rotary storage devices are divided into a plurality of areas according to the writing or reading speed, and the divided areas are combined for reading and writing, so that the plurality of rotary storage devices are It is possible to average the writing or reading speed of the.

[0007]

【Example】

(Embodiment 1) A data storage device of the present invention will be described below with reference to the drawings.

FIG. 1 shows the structure of the data storage device. In FIG. 1, reference numerals 102 and 104 denote an optical disk device A and an optical disk device B for storing data in the data storage device 108 of the present invention. When writing data from the outside, 106 divides the write data into a fixed length, and the optical disc device A 102 and the optical disc device B 1
The area 04 is divided into a plurality of areas from the inner circumference to the outer circumference, and the divided data is written by the number corresponding to each data writing speed, and at the time of reading the data, the optical disk device A 102 and the optical disk device B are written.
This is a control circuit for reading out and storing the data divided into 104 and stored. An external device 200 writes / reads data to / from the data storage device 108 of the present invention. For example, the external device 200 may be a normal workstation or the like, and the external device 200 and the data storage device 108 are connected by a general interface such as SCSI.

FIG. 2 is a diagram for explaining how the optical disk is divided into areas from the inner circumference to the outer circumference. For the following description, the values of the optical disk manufactured by Matsushita are used as a reference for the continuous writing and reading speeds in each area. Therefore, when the area 1, the area 2, the area 3, and the area 4 are arranged from the inner circumference, it is assumed that they are 0.84 MB / sec, 1.03 MB / sec, 1.22 MB / sec, and 1.40 MB / sec, respectively. Furthermore, the area 1 of the optical disk device A102
Will be referred to as area A1 and will be described.

An embodiment of the present invention will be described below with reference to (FIG. 1) and (FIG. 2). From external device 200 (Fig. 3)
It is assumed that writing of data of 256 kB occurs as shown in. In this case, the controller 106 that received this data
Divides the 256 KByte into 16 and writes the data into the pair of areas of the optical disk device A 102 and the optical disk device B 104 with the divided area and the number of read / write divisions shown in FIG. For example, in pair 1, six 16kBytes in A1 and one in B4
0 pieces of 16 kByte data will be written.

Here, since the number of optical disk devices is 2 and the number of divisions is 4, the area combination method is (4 + 1) * 2.
/ 2 = 5, and the total sum of the areas is 5. Therefore, the pair of areas A1 and B4 (pair type 1) and area A
Since the pair of 4 and B1 (type of pair 4), the pair of regions A2 and B3 (type of pair 2) and the regions A3 and B2 (type of pair 3) have the same relationship, here, in the case of each former Just explain.

An optical disk device A1 like the pair type 1
When writing data to the area 1 of 02 and the area 4 of the optical disk device B 104, the optical disk device A writes six 16 Kbyte data as shown in FIG.
e * 6 / 0.84 = 114.3 milliseconds, 16kByte * 10 / 1.40 = 11 to write 10 pieces of 16kByte data in the optical disk device B
It takes only 4.3 milliseconds to write the data. Therefore, this writing requires 114.3 milliseconds, and the writing speed in this case is 2.23 MByte / sec.

When data is written in the area 2 of the optical disk device A 102 and the area 3 of the optical disk device B 104 as in the case of the pair type 2, as shown in FIG. 6, the optical disk device A stores seven 16 kByte data. 16 to write
kByte * 7 / 1.03 = 108.7 milliseconds, 16kByte * 9 / 1.22 = 11 to write nine 16kByte data in optical disk device B
The data writing time is only 8.0 milliseconds. Therefore, this writing requires 118 milliseconds, and the writing speed in this case is 2.17 MByte / second.

When data is read from the data storage device, the reverse operation is performed.

When reading data from the area 1 of the optical disk device A 102 and the area 4 of the optical disk device B 104,
As shown in (Fig. 5), the optical disc device A has six 16K units.
16 kByte * 6 / 0.84 = 114.3 milliseconds for reading the byte data, and 16 kByte * 10 / 1.40 = 114.3 milliseconds for reading the 16 16 kByte data in the optical disk device B. Therefore, this read requires 114.3 milliseconds, and the read speed in this case is
It is 2.23 MByte / sec. The read data are connected by the control circuit 106 and sent to the external device 200.

Further, when reading data from the area 2 of the optical disk device A 102 and the area 3 of the optical disk device B 104, 16 kByte * 7 / 1.03 for reading seven 16 kByte data from the optical disk device A as shown in (FIG. 6). = 10
In 8.7 milliseconds, the optical disc device B reads 9 pieces of 16 kByte data, and therefore requires 16 kByte * 9 / 1.22 = 118.0 milliseconds data read time. Therefore, this reading requires 118 milliseconds, and the reading speed in this case is 2.17 MByte / second. The read data are connected by the control circuit 106 and sent to the external device 200.

That is, the speed at the time of writing and reading the data can be averaged from 2.17 MByte to 2.23 MByte.

Therefore, the data from the external device 200 is divided by the control device 106 at the time of writing the data as described above, and it is predetermined in the area from the inner circumference to the outer circumference of the two optical discs corresponding to the writing speed. It is possible to average the writing and reading speeds for the two optical disks by writing the data at a ratio and by connecting the data read from the two optical disks by the control device 106 when reading the data. Become.

In this embodiment, the storage device with a constant angular velocity is an optical disk, but another storage device may be used as long as it satisfies the condition with a constant angular velocity.

In this embodiment, the number of divisions from the inner circumference to the outer circumference of the optical disc is set to 4, and the number of optical discs is limited to 2. However, even if the number of optical discs is more than this, it is possible to combine the areas. If so, there is no particular problem.

(Second Embodiment) Next, a second embodiment of the present invention will be described.

FIG. 7 shows the structure of the data storage device of this embodiment. In FIG. 7, 102 is an optical disk device A for storing data in the data storage device 108, and 104 is an optical disk device B for storing data in the data storage device 108.

Reference numeral 110 is area information for storing the positions of the divided areas of the optical disk device 102 and the optical disk device 104 and the writing and reading speeds.

111 reads the value of the area information 110,
It is a division size calculation means for determining the size of the division data to be written in the optical disc device 102 and the optical disc device 104 so that the times of reading are the same.

When writing data from the outside, 106 simultaneously divides the data divided by the division size calculating means 111 into areas obtained by dividing the areas of the optical disk device 102 and the optical disk device 104 into a plurality of areas from the inner circumference to the outer circumference. This is a control device for simultaneously reading and connecting data stored separately in the optical disk device 102 and the optical disk device 104 at the time of writing and reading of data.

Reference numeral 112 holds all address information of the optical disk device 102 and the optical disk device 104, and the control device 106.
Records the position when the data is written by the controller 1
It is a disk address management means for giving an address when reading the data of 06.

Reference numeral 200 denotes the data storage device 108 of the present invention.
It is an external device for writing and reading data to and from. For example, the external device 200 may be a normal workstation or the like, and the external device 200 and the data storage device 10 may be used.
8 is connected by a general interface such as SCSI.

An embodiment will be described below with reference to (FIG. 7) and the above (FIG. 2). It is assumed that the external device 200 writes data of 256 kBytes as shown in FIG.
In this case, the control device 106 that received this data
A value of the division size is requested to the division size calculation means 111. At this time, the minimum unit of size is 1 kByte due to the limitation of the present disk device, so 256 kByte data is divided into 256 units of d1 to d256 as shown in (FIG. 8).

The division size calculation means 111 uses the area information 1
Using the speeds of the respective areas stored in 10, the division size is calculated so that the read times are the same. Hereinafter, a calculation method in the division size calculation means 111 will be described in the case of two combinations of different speeds as in this embodiment. If the slower speed of the two disks is SS, the size is DS, the faster speed is SF, and the size is DF, then the two from (Equation 1) and (Equation 2) will be SF.
And DF can be determined.

[0030]

[Equation 1]

[0031]

[Equation 2]

[Equation 1] is the data length 25 when the sizes are summed up.
It is established because it becomes 6 kByte, and (Equation 2) is established because the read time length becomes the same.

The actual combination of areas is the pair of areas A1 and B4.
(Pair type 1) and area A2 and B3 pair (pair type 2) and area
The size obtained by substituting the above values for four pairs of A3 and B2 (pair type 3) and regions A4 and B1 (pair type 4) is shown in FIG. As shown in (FIG. 8), the data size value in (FIG. 9) is a rounded-off approximate value because the minimum size unit is 1 kByte.

Based on the value of the division size calculation means 111 thus obtained, the control device 106 causes the optical disk device 102 to have 256 KBytes in the area and size shown in FIG.
And data is written in a pair of the area of the optical disk device 104. For example, pair 1 has 96kByte for A1 and 16 for B4
0kByte data will be written. Further, the control device 106 controls the optical disk device 102 and the optical disk device 10.
When writing data to No. 4, the written position and size are stored in the disk address management means 112.

Next, when reading, the control device 106 which has received the position and size by the disk address management means 112 is the optical disk device 102 and the optical disk device 1.
Connect the data read from 04 respectively,
Send it to the external device 200.

The state of this reading is shown in FIG.
0) and (FIG. 11). (FIG. 10) shows reading in a pair of areas A1 and B4 (pair type 1) and pair of areas A4 and B1 (pair type 4), and (FIG. 11) shows a pair of areas A2 and B3.
(Type of pair 2) and reading of a pair of regions A3 and B2 (type of pair 3). Since the read time is from 114.3 ms to 113.9 ms from (FIG. 10) and (FIG. 11), the speed at the time of data read is averaged from 2.24 MByte to 2.25 MByte.

Further, in (FIG. 10), the read times from the two optical disk devices are the same, and unlike the (FIG. 6) in the previous embodiment, the read times are different and the time is not wasted. Also in (FIG. 11), the difference in read time is negligible at 0.3 msec, which can be said to be the same read time. This difference in read time is due to the fact that an approximate value that matches the minimum size unit is used during the calculation in the division size calculation unit 111. If the minimum size unit is smaller, the read time also differs. It is possible to lose it.

In this way, when the data is stored in the area from the inner circumference to the outer circumference of the two optical disks at a rate corresponding to the writing speed, the division size calculating means 111 makes the read times the same (Equation 1). By calculating the size from (1) and (Equation 2) and dividing the size, it becomes possible to read data from two optical disks at a higher speed and at an averaged speed.

The value of 256 in (Equation 1) is due to the fact that one data length in this embodiment is 256 kBytes, and even if the data length is an arbitrary value, (Equation 1) holds and the size should be obtained. You can

In this embodiment, the storage device with a constant angular velocity is the optical disk device, but another storage device may be used as long as it satisfies the condition with a constant angular velocity.

[0041]

As described above, according to the present invention, the data inputted from the outside at the time of writing the data is divided and the ratio of the divided data is determined in the area from the inner circumference to the outer circumference of the plurality of constant angular velocity rotation type storage devices. By writing to the memory, it is possible to average the write or read speeds for a plurality of rotary storage devices.

[Brief description of drawings]

FIG. 1 is a diagram showing a data storage device according to an embodiment of the present invention.

FIG. 2 is an explanatory diagram of area division of the optical disc in the embodiment.

FIG. 3 is an explanatory diagram of data from an external device and a division method in the same embodiment.

FIG. 4 is an explanatory diagram of a use area pair of two optical disks in the same embodiment.

FIG. 5 is an explanatory diagram at the time of reading and writing data in the same embodiment.

FIG. 6 is an explanatory view at the time of reading and writing data in the same embodiment.

FIG. 7 is a configuration diagram of a data storage device according to a ninth embodiment.

FIG. 8 is an explanatory diagram of data from an external device and a dividing method according to a ninth embodiment.

FIG. 9 is an explanatory diagram of a used area pair of two optical disks in a ninth embodiment.

FIG. 10 is an explanatory diagram of reading data according to the ninth embodiment.

FIG. 11 is an explanatory diagram of reading data according to the ninth embodiment.

[Explanation of symbols]

 102 optical disk device A 104 optical disk device B 106 control circuit 108 data storage device 110 area information 111 division size calculation means 112 disk address management means 200 external device

 ─────────────────────────────────────────────────── ─── Continuation of the front page (72) Inventor Yoshimasa Obayashi 1006 Kadoma, Kadoma City, Osaka Prefecture Matsushita Electric Industrial Co., Ltd.

Claims (6)

[Claims] 1. A plurality of rotary type memory means for writing or reading data at a constant angular velocity, wherein a plurality of areas corresponding to the write or read speeds of the memory areas of the respective rotary type memory means from the inner circumference to the outer circumference. When the data is written, the write data is divided into a predetermined number, and the divided data is assigned to each rotary storage unit for writing according to the writing speed in the area for writing, and each rotary storage is Means for writing the allocated divided data, for reading, for reading each of the data from the corresponding positions of the plurality of rotary storage means, and for restoring the data for writing from the read divided data. Method. 2. When the number of rotary type storage means is N, the number of divisions of the storage area of each rotary type storage means is M, and the number of the divided areas is 1 to M, writing is performed respectively. 2. The data storage method according to claim 1, wherein the combination of the storage areas of the rotary type storage means is specified so that the total sum of the area numbers of the rotary type storage means becomes (1 + M) * N / 2. 3. The division size when dividing the write data is determined so that the time required to read the written data from the writing area of each rotary storage means becomes substantially the same. The method for storing data according to claim 1. 4. A plurality of rotary memory means for writing or reading data at a constant angular velocity, and a plurality of memory areas corresponding to the write or read speeds from the inner circumference to the outer circumference of the respective memory areas of the rotary memory means. When the data is written, the write data is divided into a predetermined number of areas, and the divided data is assigned to each rotation type storage means for writing, according to the writing speed in the area to be written, and each rotation type storage is performed. Means for writing the allocated divided data, for reading, for reading each of the data from corresponding positions of the plurality of rotary storage devices, and for controlling the data for writing from the read divided data Storage device. 5. When the number of rotary type memory means is N, the number of divided memory areas of each rotary type memory means is M, and the numbers of the divided areas are 1 to M, writing is performed respectively. 5. The data storage device according to claim 4, wherein the combination of the storage areas of the rotary type storage means is designated so that the total sum of the area numbers of the rotary type storage means becomes (1 + M) * N / 2. 6. A plurality of rotary storage means for writing or reading data at a constant angular velocity, and a storage area of the rotary storage means in a plurality of areas corresponding to write and read speeds from the inner circumference toward the outer circumference. When the data is divided and the data input from the external device is written, the write data is divided, and the divided data is respectively written in the storage areas on the plurality of rotary type memory devices, and when the data is read, the correspondence of the rotary type memory device is performed. The data from each of the read positions, restores the data at the time of writing from the read data, and outputs the data to the external device; and when the control device writes the data to the rotary storage unit, a plurality of data are stored. When divided and stored in the areas of the rotary type storage means, the control means separates from the respective rotary type storage means. A data storage device, comprising: a division size calculating means for determining the division size of the data so that the time required to read the divided data is substantially the same, and for giving the division size to the control means. .