JPS6073226A - Room heating and cooling device - Google Patents

Abstract

PURPOSE:To improve comfortable property by a method wherein the heat exchanger of a heat pump is arranged in the underfloor of a house and cool air is circulated through the spaces of the underfloor and the rear side of ceiling so that the air is introduced into rooms when the temperature thereof becomes close to a room temperature and it has turned mild. CONSTITUTION:When the heat pump is operated to warm a condenser or an underfloor radiator 1 and a fan 1' is rotated, warm air circulation is begun. The fans 9, 10 at the rear side of the ceiling of first and second floor are operated and a damper 3 is closed, then, warm air circulates from the underfloor to a duct 11 as shown by arrow signs 2, 4, half of it flows to a passage through the arrow signs 31, 12, 12' and remain-half of it flows to the passage as shown by the arrow signs 32, 13, 13', both of them join in the passage and stair case, enter into the underfloor through the floor lattice of the passage of first floor as shown by the arrow sign 33 and sucked by the fan 1' to return to the radiator 1. Thus, warm air circulates through the whole of the spaces in the house.

Description

[Detailed Description of the Invention] In recent years, heat pumps have been increasingly used for heating and cooling houses (residences, law offices, factories, etc.). In conventional heat pump equipment, the heat exchanger of the heat pump (refrigerant condenser for heating, refrigerant evaporator for cooling) is placed indoors, and a fan circulates indoor air through the heat exchanger. There are many methods that are used.

This way, you can reach your goal, but the next drawback is that you can't lie.

(1) There is a fan noise.

(2) Indoor air temperature often becomes uneven.

(3) Since the heat exchanger is inside the room, it reduces the effective area of the room, makes it difficult to find a place to place it, and is a nuisance because it doesn't look good.

(4) In the case of air conditioning, the cold air sometimes hits the body directly and is not good for health.

The present invention places a heat exchanger for a heat pump under the floor of a house, circulates warm air for heating (cold air for cooling) under the floor and in the ceiling, and heat exchanges the floor and ceiling to increase the temperature. This is a heating/cooling device that allows air to cool down (in the case of air conditioning, the temperature rises) and introduce mild air that is close to room temperature into the room.

This will be explained with reference to an embodiment as follows. 1st
The figure is a perspective view of the second floor of the house, with the upper structure removed to show the basic layout, as an example, and the right side shows a duct that guides air from under the floor to the ceiling. Figure 2 is a cross-sectional view drawn to explain the flow of air in a cross-sectional view, but in order to make the explanation easier, it is not a vertical cross-sectional view corresponding to the foundation in Figure 1. , shown as a schematic diagram with a vertical duct placed on the left. FIG. 6 is an enlarged view of the area within the circle indicated by A in FIG. 2, and shows an example of the structure of the subfloor of a building.

First, the case of heating operation will be explained.

1 is a heating radiator. This is a heat pump condenser that combines a fin tube and a fan. The fan 1' circulates warm air under the floor in the direction of arrow 2. 3
is a damper installed in a hole in the partition wall of the foundation, which is opened to circulate warm air only under the floor, and also circulates warm air to the ceilings of the first and second floors as shown by arrows 4, 31, 32, and 33. Close it when you need it. The surrounding area 5 of the foundation structure is completely sealed to prevent air from circulating inside and outside, and the internal foundation 6 is built under the pillars and walls inside the house to divide the underfloor space into several sections as shown in the figure. A gap or hole is created in a part of the partition so that warm air can circulate all over the underfloor area as shown by arrow 2. T is a heat pump set that houses a compressor, expansion valve, evaporator, fan, control device, etc. A condenser 1, which is a component of the heat pump, is located under the floor as shown in the figure, and a pipe 8 connects it to the main body. A fan in the heat pump set 7 draws air from outside the set, hits the fin coils of the evaporator, and discharges it outside the radius giving heat to the refrigerant.

Due to the action of this heat pump, the condenser 1 becomes a radiator for heating.

Figure 2 schematically shows a longitudinal section of the house.

Warm air circulates under the floor, but this cannot be depicted in the cross-sectional view, so only one arrow 2 is drawn. Also, in this figure, the door 3 shown in Figure 1 is closed and hot air is directed to the ceilings of the first and second floors as shown by arrows 4, 31, and 32.

The picture is taken in a circulating situation as shown in Figure 33. When the damper 3 is closed and the fan 9 installed in the attic on the first floor and the fan 10 installed in the attic on the second floor are operated, warm air passes through the duct 11 and is distributed to the first and second floors as shown by arrows 4, 31, and 32. Climb up to the attic. In the ceiling of each room, holes with grids are installed at appropriate places so that warm air passes through the ceiling and enters the room as shown by arrows 12 and 13, and then through holes in the walls and doors. Pass through the 1st cool room and exit into the corridors 14 and 15 on the right as shown by arrows 12' and 13'. The hallway 15 on the second floor and the hallway 14 on the first floor are connected by a staircase 16, allowing air to circulate freely. The air exiting the hallway passes through holes in the lattice floor installed at appropriate locations in the hallway on the first floor, enters under the floor as shown by arrow 33, and is sucked into the fan 1' built into the underfloor radiator 1, causing I' The circulation of ilA wind is completed. In Figure 2, the first and second floors are each depicted as one room, but
This shows the flow of air when the room is divided into several parts.
It is illustrated as one room because it would be inconvenient to have a room. Even if the number of rooms is divided into spaces,
If each room faces a hallway, this explanation will be the same for each room.

The outer wall 1T of the house needs to be sufficiently insulated, as is done in most modern constructions. In addition, a double ceiling 18 is created by leaving a gap in the attic on the second floor where air can flow horizontally, and
The heating and cooling effect will be greater if the heavy ceiling 18 is sufficiently insulated.

If the double ceiling 18 is not installed, it is necessary to install sufficient insulation work behind the roof 19. 1st floor floor 20, ceiling 21.
The second floor floor 22 and ceiling 23 can be constructed using general construction methods.

The surface under the floor can be left as is, as in the conventional construction method, but moisture control will not be sufficient in this case, so it is better to construct as shown in Figure 6.

A concrete layer 24 is poured on top of the soil at an appropriate height, a waterproof layer 25 is made of, for example, a vinyl sheet, and a mortar layer 26 is placed on top of it.

Ku. Rather than making the surface of the mortar layer flat, it is better to make it uneven, for example as shown in the figure, to increase the surface area and increase the heat transfer coefficient. In this way, the underfloor space is isolated from underground moisture by the waterproof layer 25, and the heat exchange rate with the underground is also improved.

Sufficient insulation work is carried out on the outer peripheral foundation 5 to isolate heat from inside and outside.

□The heating effect with the above structure is explained as follows.

When the heat pump is operated and its condenser, that is, the underfloor radiator 1 is heated, and the attached fan 1' is rotated, hot air begins to circulate. When the fans 9 and 10 in the attic on the first and second floors are also operated and the damper 3 is closed, the warm air flows from under the floor in the direction of arrows 2 and 4 and up the duct 11, and half of the air flows through arrows 31, 12, 12'.
Turn around and go to the hallway, and the other half are arrows 32, 13, 1
3' and into the hallway, and then they meet in the hallway 9 stair room, pass through the floor grate of the first floor hallway as shown by arrow 33, and the person 1) is sucked in by the fan 1' and returns to the radiator 1. .

In this way, the warm air is circulated throughout the house. In this case 1
If the floor is constructed using the normal construction method, it will be ``base board + cushion sheet + jutan'', ``base board 10 tatami mats'', etc. When heated from the bottom of the floor, the heat transmission coefficient of the floor is 1.2 to 1.5 K'a'/'77 (.hr, degree Celsius, ratio K])! The flow is large. Since it is heated by warm air under the floor, the heat is transmitted as shown by arrow 21, and the effect as floor heating is great.

It is empirically known that when heat is applied from below as floor heating, the heating effect felt on the body is large, and that even if the indoor air temperature is about 3°C lower than with other heating methods, the room feels warm enough. Being able to keep the room temperature low means saving on heating energy. In other words, it leads to energy saving.

It passes through the hot air duct 11 and enters the ceiling as shown by arrows 31 and 32. In the attic on the first floor, the heat of the warm air is indicated by arrow 28.
As shown in the figure, it is transmitted downward through the ceiling 21 on the first floor, and at the same time two
It passes through the Vlj floor 22 and is transmitted to the room on the second floor as shown by the arrow 29. If the structure of the ceiling 21 on the first floor were to be constructed using normal construction methods, it would be ``stone = T; i board + cloth pasting'' and ``one Japanese-style ceiling board.''
Others.

Its downward heat transmission coefficient is 2. r3Kcal/171. h
It is about r, -r2. On the other hand, if the outer wall is sufficiently insulated, the heat transmission coefficient is 0.5 K ("CL l
/771', h, r', around °C. The heat transmission coefficient of a glass window is 5.5 Kcal/71 (, h, r,
'(2(If double glass is used, 3KCαlΔcriticalhγ6°C
), but the glass window area is 15 to 20 times the outer wall area.
%, the average thermal shell flow rate of the entire outer wall is 12. If the indoor temperature is 20°C and the outdoor temperature is 5°C, the temperature difference is 15
℃, the amount of heat escaping from the outer wall with this temperature difference is 1.2 Kcal/7r (".hr,"CX 15°C
X90777”-1,620Kcal/nr.

The average temperature under the entire warm air floor is 31"C, and the heat transmission coefficient of the first floor is 1.5I<cal/77)7.hr,"C
Then, the amount of heat transmitted through the floor is 1.5 Kc (tl/rti, hr, "c x (31-20
) "CX50m" = 830 Kcal/hr From the warm air under the floor through the Jm surface jII! , the heat valve entering the inside reduces the downward heat conductivity of the ground to 1.5 Kcal/H (
', A? ","C1 underground temperature is 15°C, '15Kcal/771",,hr,"CX (31
-15) X50 = 1.200 KCαlArS,
The temperature of the hot air leaving radiator 1 is 34°.
C, the temperature of the air that enters the duct 11 after circulating under the floor and giving heat to the L floor 20 and the ground 26 is 64°C - (8
30+ 1.2 [] 0) KCQ, l/hγ-, C
2o771r6x 60 minutes cutting 2' (9/mLxx [1
,24Kl? αl/2. 'C)-345,9=28.
The average temperature under the floor of 1°C is (34 + 28.1) ÷ 2 = 31
．． 05°C1, that is, the average temperature of 31°C assumed earlier is almost correct.

The warm air 172 of 28.1°C that went up the duct 11 enters the ceiling on the first floor, flows through the ceiling 21 on the first floor, and applies heat to the room 11@downward as shown by arrow 28, and at the same time heats the room on the second floor. The heat flows through the floor 22 and flows upward as shown by arrow 29, imparting heat to the room on the second floor.

The amount of heat flowing through the first floor ceiling 21 has a heat transmission coefficient of 2, OK c
ati71゜hr, ``C Assuming the average temperature of the attic air on the 11th floor is 25℃, 2.0Kcal/77%, Ar, 'CX (25-20)
'CX50774500KCαl/Aγ Also, the structure of the second floor 22 is almost the same as that of the first floor, and the heat transfer coefficient is set to 1.
5Kcal/m", ,nr,"Q, and the floor area is 1
If the temperature of the room on the second floor is <50771", which is the same as the room on the first floor, and the temperature of the room on the second floor is <20°C, the average temperature of the air in the attic on the first floor is 25°C. 21;〃The amount of heat that enters the room is 1.5Kcal/,-,nr,”cX(25-20)X
50=380KccL/'/hrIVR When calculating the temperature at which heat is removed from the attic air through heat flow, we find that 28.1°C-(500+380 >Kc(tl/)L
t4c 1 ey&g x SO min x1. q'v-sx O
, 24Kca17Kg, °C) = 28.1-5.1 =
25.0"c The average temperature of the air in the attic on the first floor is (28, 1 + 23.0) ÷ 2 = 25.5°C. In other words, the average temperature of 25°C assumed earlier is almost correct. In the attic on the first floor, 23 The air that has become 0°CK enters the room on the first floor as shown by arrow 12 through the grid hole provided in the ceiling 21 on the first floor.
Supply the shortage of heat. Since the temperature of the room on the first floor is 20"C, the amount of heat supplied by the air entering the room on the first floor from the ceiling of the first floor is (23,0-20)'CX 10yr10X 1.2K
y/ix 024KctL14. ”(2=520K
cal / hr Therefore, the heat fjl transmitted through the first floor 20
Adding 830 Kcal/hr and the heat jx 50 D Kcal/hr transmitted through the first floor ceiling 21, the total amount of heat supplied to the first floor room is 5
20+850+500= 1.85[IKCal/h
It becomes r. First, we calculated the amount of heat escaping to the outside through the outside walls and windows on the first floor and found 1.620 KC (Li/hγ. Therefore, there was enough time for heating fever, and 8%
There is some leeway. We assumed that the temperature of the room on the first floor was 20°C, but it would be around 205°C.

Next, calculate the second floor. 21@, like the first floor, will have a floor area of 50m and an exterior wall area of 90m. The amount of heat that flows through the second floor floor 22 and enters the second floor room is 38 CJI<C(
It was calculated as 11/hγ. The air volume that follows the duct 17 and enters the ceiling of the second floor as shown by arrow 32 is 10 tn/min.
Its temperature is 281°C.

The water flows through the ceiling 23 on the second floor and flows in the dry direction as shown by the arrow 30.
The amount of heat entering the room on the floor is calculated as follows. The second floor ceiling structure has a downward heat transmission coefficient of 2.0 Kc, the same as the first floor.
al 771f -hr -°C12th floor W % 20
If kept at ℃, 2.0 KC (11/71(".hr,"CX
6-20)X50=60DI(cal/Ay then 2nd floor 2
Calculate the amount of heat that flows through the heavy ceiling 18 and escapes to the attic.

Assuming that the second floor ceiling 18 has been sufficiently insulated, its heat transmission rate is 0.6 Kcal/go. hr, "(2).Also, assume that there is little circulation between the roof and the outside air, and when the outside air is 5°C, the temperature in the attic is 10°C. Then, 2
The heat flowing through the heavy ceiling 18 and escaping to the attic is 0.61<c(Ll/yrf-Ar,"CX(26-1
0)"CX50)5=240 Kcal/hr Air temperature Q from the attic on the second floor, passing through the ceiling grid and entering the room on the second floor following arrow 13" - 28,1°C - (600+240) KC (L'/hr
2 (IDi/7X60minX 1.2+J, o24Kcc
tl/, 9. "C)=28.1"C-4,9°'C=
-23,2'C The average temperature of the air in the attic on the second floor is (28,1+23.2)÷2=25.7°C, that is, the 26°C assumed earlier is almost correct.

The air heated to 232°C passes through a grid hole provided in the ceiling 23 of the second floor and enters the second floor as shown by arrow 13 to supply the insufficient amount of heat. The temperature for the second floor is 20°C, so the amount of heat it supplies is (25, 2-20)'CX10 x 60 minutes x t2%? x O, 24Kcal/Ky
550KpalAr This amount of heat is supplied for the second floor by adding 38DK"l/hr of heat transmitted through the second floor floor 22 and 600 Kcal/hγ transmitted through the second floor ceiling 23. The total amount of heat is 5
50+:580+600"-1,530KCal/Ay
Assuming that the amount of heat escaping to the outside through the outer walls and windows on the second floor is <1.620 Kcal/hτ, the same as in the case of 1hη, the heat input is 6% less than the heat output from the room. Set the temperature of the room to 20°
Since it was assumed that the temperature was 195°C, there would be a lack of heat, and the room temperature would be 195°C.
If it is set to °C, it will be almost balanced.

Since the temperature on the first floor is 205°C and the second floor is 19.5°C, there is no particular problem, but if you want to force both the first and second floors to 20°C, you can reduce the amount of warm air sent to the attic on the first floor. You can reduce it a little and increase the amount of warm air sent to the attic on the second floor. In that case, it can be easily done with dampers and other parts.

If you look at it like this, you can see 20. 'When kept at C, 1
On the second floor, air at 230°C is supplied through the ceiling lattice holes, and on the second floor, air is heated at 230°C.
, 2°C air will be blown through the ceiling grid holes. Since mild air that is not much different from the room temperature is blown into each room, there is less uneven temperature inside the room, and the underfloor heating creates a comfortable environment. Also, since you enter the room after passing through a long winding passage, you can hardly hear the sound of the fan.

Next, we will discuss the heat transmitted underground (floor).

Heat is conducted from the earth's surface 26 into the earth and is stored therein.

If the vehicle is operated for a long time, for example, about 12 hours, the temperature of the surface mountain j will be close to the temperature of the air below the floor. In the previous example, the underfloor air temperature Je-
', when the temperature is 31°C, the ground surface becomes about 27°C, and a constant 9-heat distribution is applied underground to about 1 meter underground. When the heat pump and fans are stopped and turned on late at night, the temperature under the floor and in each room begins to drop, but when this happens, heat is transferred from the subfloor surface to the first floor floor 20 by convection and radiation, reducing the effectiveness of the residual heat floor heating for a long time. Obtainable. If the underground fans 1', 9, and 10 are operated with the heat pump turned off and the air is circulated up to the ceiling, it is possible to heat up to the second floor using underground heat storage. When there is no need to heat the second floor, first floor fan 9, second floor fan 10
If you turn off the heat pump, open the damper 3, and perform underfloor heating with a heat pump while circulating air only under the floor, the first floor will be fairly warm with just the floor heating, and heat can be stored underground. When the heat pump is stopped after operating for a certain period of time, the heat stored in the ground slowly comes out, heating the first floor for a long time and creating a comfortable environment.

The power of the heat pump is calculated as follows using the numerical example shown earlier. The temperature of the air that exits the underfloor radiator 1 is 64°C, and the air temperature that returns from each room through the hallway as shown by the arrow 33 is 20°C, which is the same as the room temperature. Since the circulating air is 20m'/6, the amount of heat emitted by the radiator 1 is (34-20)"CX2D77/10X60minX1.
2 to 9/1. iX O,24KC(tl/1(y-4,
840Kcal/nγOutside temperature 5°C1If the air temperature passing through the radiator is 64°C, the heat pump will produce approximately IKW!
1.00 [.

Since it outputs KCαl/hr, the power of the heat pump is 4.8
40÷3. [l 00 = 1.6KW, that is, approximately 2KW of power is required.

The above explanation was for heating, but this device can also be used directly for cooling. In the case of cooling, switch the four-way valve in the heat pump set 7 and change the heat exchanger 1, which was the condenser during heating, to the evaporator, and the heat exchanger in the heat pump set 7, which was the evaporator during heating. Make it a condenser. The heat of condensation of the refrigerant is released into the outside air by the attached fan. The evaporator 1 extracts heat from the air passing through it by means of a fan 1'. The air cooled by the evaporator 1 is circulated through the same route as explained for heating. The heat radiation at the 1st floor floor 20 and ceiling 21° and the 2nd floor floor 22 and ceiling 23 is completely opposite to that in heating, with air entering from the ceiling grid on the 1st floor as indicated by arrow 12, and air entering from the ceiling grid on the 2nd floor as indicated by arrow 13.
Although the air in the room is colder than room temperature, it receives heat from the floor and ceiling, so it is close to room temperature. Therefore, there is little non-uniformity in the indoor air temperature, and even if the blown air hits your body directly, it will not harm your health. Storing heat underground from the ground beneath the floor also stores cold heat, so you can think of it as the complete opposite of heating. In the case of only air conditioning, the heat flow through the first floor floor 20 and the second floor floor 22 is from top to bottom, and the heat transmission coefficient is smaller than that in the case of heating. In other words, heat is difficult to transfer. However, on the contrary, heat flow through the ceiling 21 on the first floor and the ceiling 23 on the second floor is from bottom to top, and the heat penetration coefficient is larger than in the case of heating, that is, heat is easily transmitted. Also, the heat flow through the subfloor is greater than in the case of heating. In the case of air conditioning, it is necessary to dehumidify. That is, the cooler 1 removes moisture from the air as water droplets,
Drain the water outside. The temperature of the cooled and dehumidified air is increased through heat exchange between the floor and ceiling, and the dehumidified and mildly heated air is introduced into the room, keeping the room comfortable. In the case of an air conditioner, the rate of cooling from above is high, so in this case as well, you get what is commonly called ``cold head, cold feet,'' creating a healthy environment. The amount of heat can be calculated in the same way as in the case of heating, just by reversing the flow of heat. The numerical values applied to the calculations so far are not limited to these, but are shown as an example to make the explanation easier to understand.

In the explanation so far, we have explained that the house will be heated and cooled all-purpose, but it is also possible to partition part of the house and use the partition wall under the floor to match [1: Cut and heat and cool only part of the house. It can be practiced within the scope of the invention. Further, although the explanation has been made for a two-story house, the present invention can also be implemented in a one-story house, or a house with three or more floors, if the structure is adapted to that. Also, in the explanation so far, the floor and ceiling are used as heat flow surfaces for heating and cooling, but if necessary, the walls can be made into a double structure, circulating air can be passed through the space between the outer wall and the inner wall, and the outer wall can be heated and cooled. It can be used within the scope of the present invention to filter heat from the outside air and use it as an inner wall for heat flow when the floor and ceiling alone do not provide enough heat flow. Furthermore, although the explanation has been made using a house such as a general residence, this can also be implemented within the scope of the invention by designing a factory building accordingly. Recently, constant temperature, constant humidity, and dust-free rooms are often constructed in factories, and in such cases, by applying the present invention, the amount of indoor air circulation can be reduced, eliminating the problem caused by the large amount of circulating air. This has the advantage of reducing the amount of fine dust generated, and therefore requiring smaller fans, filters and other equipment. In the explanation so far, we have explained that heat conduction is measured underground and heat is stored underground, but if there is no need for underground heat storage, it is possible to prevent heat conduction underground by constructing insulation work on the ground surface. can.

Also, in the explanation so far, the explanation has been given as a heat pump, but in the case of heating, it is not limited to a heat pump. That is, it is also possible within the scope of the present invention to use a radiator placed under the floor that uses hot water or steam, and to send hot water or steam from a boiler placed outside to provide heating.

Furthermore, in the explanation so far, we have explained that the air that has passed through the attic passes through the room through the ceiling lattice hole, but it is also possible to install an air duct outside the room and direct the air that comes out from the attic to the floor below. It is also possible within the scope of the present invention to circulate the air without passing it through the room, and to perform heating and cooling using only the heat that flows through the floor and ceiling.

As is clear from the explanation up to now, if the heating and cooling device according to the present invention is applied, it will be possible to create a suitably air-conditioned environment, which will make a great contribution to the industry.

[Brief explanation of the drawing]

FIG. 1 shows the upper part 4 of a residential house as an embodiment of the present invention.
It is a perspective view showing the base part and the duct which leads air to the upper part after removing the Y structure. FIG. 2 is a vertical fur side view of the house shown in FIG. 1, but for the sake of clarity, it is shown in a horizontal view, not corresponding to FIG. 1. Figure 6 is an enlarged detail of the area inside the circle marked A in Figure 2! : ii figure. 1... Heating radiator (air cooler in the case of Cool J),
3... Air passage damper, 5... External wall base of the building ('
rM, 6... Internal foundation of the building, 7... Heat pump set, 8... Arrangement connecting the heat pump and heat exchanger 1, 9.10... Fan, 11... Duct, 1
4.15...corridor, 16...stairs, 17...outer wall, 18...double ceiling, 19...roof, 20...1
Floor, 21...1F47 Ceiling, 22...2nd floor, 2
3...Second floor ceiling, 24...Subfloor concrete layer, 25...Waterproof layer, 26...Pressure mortar layer, 2
,4.12.12',13,13',31°32,3
3--Arrows indicating the path of air, 27, 28. 29, 30...Arrows indicating heat transfer. Above 1-J. Procedural amendment filed May 60, 1980 Patent Office 5 8 9 Layer 1. Indication of case 1982 Patent Application No. 182552 2. Name of invention Heating/cooling device 3. Make amendments. Relationship with the case filed by the applicant: Toshin Kise Sera Toshin 1, Ikusetsu Co., Ltd. 4, Agent 5, Date of amendment order: 1925, Month, Day 6, Subject of amendment: Particulars and detailed explanation (1) , BA Rigid Axis Page 6 No. 1
5. Next to ``U and the ceiling]'', insert ``Do not move the heat return surface''. (2), page 16, line 15 [Thermal gradient J is corrected to read "thermal gradient."that's all

Claims (2)

[Claims] (1) A heat exchanger under the floor of the building (-a radiator in the case of a cell,
In the case of air conditioning, install a vent cooler), and circulate the air warmed by the heat exchanger (chilled air in the case of air conditioning) through all or part of the underfloor space using a fan, and then pass the air through the duct. 1st floor ceiling! (If there is a 2nd floor, the air is divided into the attic of the 2nd floor, and if there is a 3vj, the air is divided and the attic of the 3rd floor is installed; the same applies if there are 4, 5, etc. floors) After circulating all or part of the attic, it is guided into each room through the openings in the ceiling, and then into the hallway through the openings in the partition wall, the openings in the door, and the gaps. . They meet in the stairwell and are guided below the floor through an opening made in the floor of the 1vj corridor (such as a lattice floor), or after circulating in the attic, they are led directly below the floor through a duct without passing through each room. By circulating it back to the heat exchanger and doing so, 1
floor. The first floor ceiling is used as a heat flow surface to heat and cool rooms on the first floor, and the second floor and second floor ceilings are used as heat flow surfaces to heat and cool rooms on the second floor (3
Heating/cooling equipment designed to operate (same below if above). (2) Heat exchanger (heat radiator in case of heating) under the floor of the building,
In the case of air conditioning, install an air cooler), and use a fan to circulate the air warmed by the heat exchanger (chilled air in the case of air conditioning) through all or part of the underfloor space, from the ground surface under the floor to the ground. Conduct heat (or cold) inside and store heat (or cold storage),
A heating/cooling device characterized in that after the heating/cooling device is stopped, the heat storage (or cold storage) slowly rises to cool the house by +2.